Hope your doing all fine...
Ok my next idea is that I have this page that it contains a content. Whenever i click something in menu it loads the proper page inside the content. But when I click a button with the method POST it redirects the whole page and not the content only.
I want to display if a driver is successfully added or not inside the same page!!
Code of Admin.php:
include("Conx.php");
if(isset($_POST['AName']) && isset($_POST['CEOName'])&& isset($_POST['Address']) && isset($_POST['AEmail']) && isset($_POST['ATel'])){
$target = "images/";
$target = $target . basename( $_FILES['AImage']['name']);
$an=$_POST['AName'];
$cn=$_POST['CEOName'];
$a=$_POST['Address'];
$ae=$_POST['AEmail'];
$at=$_POST['ATel'];
$file=$_FILES['AImage']['tmp_name'];
$sql="INSERT INTO agence(agID,nom_loueur,adresse,email,tel,AImage)values('".$an."','".$cn."','".$a."','".$ae."','".$at."','".$file."')";
if(move_uploaded_file($_FILES['AImage']['tmp_name'], $target)){
$res=mysql_query($sql) or die(mysql_error());
header('location: ../Admin.php?add');
}else{
echo "<html><font size='4' color='white'><b>Can't insert..</b></font></html>";
}
}
and in the main page Admin.php added:
if(isset($_GET['add']))
{
echo "<html><center><font size='4' color='white'><b>Successfuly added!!</b></font></center></html>";
}else{
echo"<html><center><font size='4' color='white'><b>Welcome to Admin's page!!</b></font></center></html>";
}
I know that this way gives the result on Admin.php and not inside the content in page chosen...
Thanks in advance
