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PDO statement error


gmc1103
Go to solution Solved by Barand,

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Hi

 

I'm having an error in the following code and i don't get why

 public function delItem($id_itens){
        try {
            $sql = 'DELETE FROM `item` WHERE `id_itens`=:me';
            $stmt = $this->db->prepare($sql);
            $stmt->bindValue(':me', $id_itens, PDO::PARAM_STR);
            if (!$stmt->execute()) {
                print_r($stmt->errorInfo());
                return array('status' => 'error', 'message' => 'Problema ao remover este item...');
            } else {
                print_r($this->db->query($sql));
                return array('status' => 'success', 'message' => 'O registo foi removido com sucesso...');
            }
        }
        catch (PDOException $e) {
            echo $e->getMessage();
        }
        
    }

and the error is 

 

SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ':me' at line 1

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Hi Barand

 

i have removed this line 

print_r($this->db->query($sql));

and i don't have that error again but i have a strange situation

 

 

From my sqlyog i use this

DELETE FROM `esmaior_biblioteca`.`item` WHERE `id_itens` = "6";

and it works

 

in the code i put a line to check if i receive the var and i have result (11)

print_r($id_itens);
4a "11"{"status":"success","message":"O registo foi removido com sucesso..."} 0 

And it say removed but when i check it still in my database..

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i'm going to guess that the value in your $id_itens variable actually contains double-quotes around it.

 

if you are using print_r($id_itens) and it produced "11" in the output, the only way that can happen is if there are double-quotes in $id_itens.

$var = 1;
print_r($var);
echo '<br>';

$var = '1';
print_r($var);
echo '<br>';

$var = "1";
print_r($var);
echo '<br>';

$var = '"1"';
print_r($var);
echo '<br>';

output -

1
1
1
"1"

instead of print_r(), use var_dump() as it also gives the length of whatever is in the variable.

 

so, what is your code that is producing $id_itens?

Edited by mac_gyver
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Hi mac_gyver

 

The double quote comes from this part of code

 'click .remove': function (e, value, row, index) {
                $('#myModal').modal('show').find('.modal-body #nome').val(JSON.stringify(row.nome));
                $('#myModal').modal('show').find('.modal-body #id_itens').val(JSON.stringify(row.id_itens));
            }

And i have checked and i can see double quotes in input text area of modal

 

Using var_dump the $id_itens retrives ""3""

 

What's wrong, it is the JSON??

 

Thanks

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Yes, it is an object, i have resolved this issue using

  var jobstr=JSON.stringify(row);
  var semAspas=JSON.parse(jobstr);
  var itemN = semAspas.id_itens; // id_itens
  var nome = semAspas.nome; // name
 

Now i receive just the number and not with double quotes.

 

Thank all for pointing me to the rigth direction

 

Bes regards

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