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mar92

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  1. Hello, I create PHP/Mysql table that consist of 6 column.I want to make the column grade as select input of A,B,C,D to the database and i want to add select input to the Add it column .I tried several way but didn't know How ? <?php // build SELECT query $query = "SELECT * FROM study"; // Connect to MySQL if ( !( $database = mysql_connect( "localhost", "gjk", "hj" ) ) ) die( "Could not connect to database </body></html>" ); // open database if ( !mysql_select_db( "adv", $database ) ) die( "Could not open database </body></html>" ); // query database if ( !( $result = mysql_query( $query, $database ) ) ) { print( "<p>Could not execute query!</p>" ); die( mysql_error() . "</body></html>" ); } // end if mysql_close( $database ); ?><!-- end PHP script --> <table> <caption>Results of "SELECT <?php print( "$select" ) ?> "</caption> <tr> <th> </th> <th>Code</th> <th>Title</th> <th>cr</th> <th> prerequisite</th> <th>Addit</th> <th>Grade</th> <tr> <?php // fetch each record in result set while ( $row = mysql_fetch_row( $result ) ) { // build table to display results print( "<tr>" ); foreach ( $row as $value ) print( "<td>$value</td>" ); print( "</tr>" ); } // end while ?><!-- end PHP script --> </table> <p>Your search yielded <?php print( mysql_num_rows( $result ) ) ?> results.</p> </body> </html>
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