Leaderboard

$this (programming pun intended) is the correct syntax, but produced a different error than the one you posted about the undefined variable. what was the error message in $this case? i'm going to guess that the database connection probably failed and there's no useful error handling in the code. while not the cause of the most immediate problem, your main code should be responsible for creating the database connection, then use dependency injection to supply that to any class that needs it. by making each class responsible for getting a specific database connection, your code is not general purpose. if the data source changes, to use an additional/different database type or using a remote api, you would need to go through and edit all the current code.