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atom_p

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  1. This is the first time Im trying to use REGEXP, but cant get it working. It gives no error, just nothing..Anyone got idea why, please? Thanks <?php include ('connectToDatabase.php'); $getSearch = $_REQUEST['getSearch']; $keywordSearchQuery = "SELECT shoeName, shoeSize, colour, price, gender, description WHERE shoeName REGEXP '.*($getSearch).*' || shoeSize REGEXP '.*($getSearch).*' || colour REGEXP '.*($getSearch).*' || price REGEXP '.*($getSearch).*' || gender REGEXP '.*($getSearch).*' || description REGEXP '.*($getSearch).*" ; $keywordSearchQueryResult = mysql_query($keywordSearchQuery); echo "$keywordSearchQueryResult"; ?>
  2. thanks a lot!! now I got it working finally: $getBrandID = mysql_query("SELECT brandID FROM brand WHERE brandName = '$brand'"); $row = mysql_fetch_assoc($getBrandID); $detectedID = "$row[brandID]"; echo "$detectedID";
  3. I have just realised the mistake in select statement, it should be like this, however it still doesnt work : $getBrandID = "SELECT brandID FROM brand WHERE brandName = $brand"; $queryresult = mysql_query($getBrandID) or die(mysql_error()); $id = $queryresult; echo ($id);
  4. I give up. I was trying to do what you recommended, I have tried to set variable that would get the id that match to selected brand, but it keeps giving me the same ID no matter what brand I select. here is the full code if you want to have a look, maybe you can spot what Im doing wrong, I cant.. Form: <form id="insertingDataToBrand" action="administratorCode.php" method="post"> <div> <p>Choose the brand</p> <select name="selectBrand"> <option value="Adidas">Adidas</option> <option value="Lacoste">Lacoste</option> <option value="New Balance">New Balance</option> <option value="Nike">Nike</option> <option value="Skechers">Skechers</option> </select> </div> <p>Insert Details</p> <div>Shoe name: <input type="text" name="shoeName"/></div> <div>Shoe size: <input type="text" name="shoeSize"/></div> <div>Colour: <input type="text" name="colour"/></div> <div> <p>Select gender</p> <select name="selectGender"> <option value="Male">Male</option> <option value="Female">Female</option> </select> </div> <div>Description: <input type="text" name="description"/></div> <div><input type="submit" value="Submit"/></div> </form> PHP: <?php include 'connectToDatabase.php'; $brand = $_POST['selectBrand']; $sname = $_POST['shoeName']; $ssize = $_POST['shoeSize']; $colour = $_POST['colour']; $gender = $_POST['selectGender']; $desc = $_POST['description']; echo($brand); echo($sname); echo($ssize); echo($colour); echo($gender); echo($desc); $getBrandID = "SELECT brandID FROM brand WHERE brandName = 'nike'"; $queryresult = mysql_query($getBrandID) or die(mysql_error()); $id = $queryresult; echo ($id); ?>
  5. Thanks a lot it gave me an idea but I still cant work it out. You said that: "Before you do the insert into brand, do a select brand_id from brand where brand_name = the new name. If you get a result, use that brand_id for the product insert, otherwise insert into the brand table as you have done." I have tried and got this so far: $getBrandID = "SELECT brandID FROM brand WHERE brandName = $brand" $queryresult = mysql_query($getBrandID) or die(mysql_error()); (i dont think thats even right)... Im having problem with that last bit, "use that brand_id for the product insert, otherwise insert into the brand table as you have done." Could you give a hint on how to write the code maybe? Much appreciated. Thanks
  6. Lets say I have this database: table brand [brandID] [brandName] where brandID -> auto increment and one brand always has the same brandID table product [brandID] [productID] [price] where productID -> auto increment I want to insert new product into the database using only values [brandName] and [price] and want brandID and productID to be created automatically I use this form: <form id="insertingDataToBrand" action="administratorCode.php" method="post"> <div>Brand Name: <input type="text" name="brandName"/></div> <div>Price: <input type="text" name="price"/></div> </form> And here is the php code: <?php //connection to database include 'connectToDatabase.php'; //data retrieveing $brand = $_POST['brandName']; $price = $_POST['price']; //As I am inserting to two different tables I use two INSERT statements $sql = "INSERT INTO brand (brandName) values ('$brand')"; mysql_query($sql) or die (mysql_error()); //as brandID is created automatically I am going to insert the same value to another table $last_id = mysql_insert_id (); $sql = "INSERT INTO product (price, brandID) values ('$price', '$last_id')"; ?> This should work just fine (it doesnt tho) BUT my question is: I have 3 different brands (brand A with brandID 1, brand B with brandID 2, brand C with brandID 3). When want to insert brand D, automatically created brandID should be automatically set to 4. BUT when I want to insert product of the same brand, lets say brand A (with different productID) brandID is automatically set to 4(or higher) as well. What do I have to do(use) so it would be able to realise what brandID should be added? Thanks a lot.
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