Jump to content

NewcastleFan

Members
  • Posts

    64
  • Joined

  • Last visited

Everything posted by NewcastleFan

  1. Hmmm ok thanks for the help guys! i'll look into it some more and see how else I can get this working
  2. Flash I've been told is a big no for SEO and website development.
  3. Would this be possible to be 3d? forgot to mention that in the fist post. It would have to look real like a video not just like a static image falling into another static image.
  4. I'm not sure if this is possible but im looking to get an object say a ball, and drop it into a pool of water at the bottom of of the page and for the water to splash upwards and freeze (like watching a video of it). Is this possible not using flash? This is for a web project on a browser so I'm not sure if it is possible using html5, css, jquery? If it is possible does anyone know of any examples that use or do this sort of thing it that I could look at? Thanks!
  5. Hey all, I'm trying a little project to help improve my php and mysql knowledge. I'm struggling with email validation and security. I'm looking to check if an email is valid or not before I add the ability to add it into a database. What I have so far: <?php $errormsg =""; if (isset($_POST['adduser'])){ $email = mysql_real_escape_string($_POST['email']); $pword = mysql_real_escape_string($_POST['pword']); $pword2 = mysql_real_escape_string($_POST['pword2']); if (!filter_var($email, FILTER_VALIDATE_EMAIL)) { if ($email == "") { $errormsg ="Error, You must fill in the email box."; } else if ($pword == "") { $errormsg ="Error, You must fill in the password box."; } else if ($pword2 == "") { $errormsg ="Error, You must fill in the repeat password box."; } else if ($pword != $pword2) { $errormsg ="Error, Your passwords don't match!"; } else { $errormsg = "Success!"; } } else { $errormsg = "Invalid email format, please use a valid email address."; } } ?> This always outputs the error message "Error, You must fill in the email box" now, however without the Filter_Validate_email it outputs success when all boxes are filled in. Anyone got any help on a ) whats going wrong and b ) any other security features I can add? Thanks!
  6. Hey everyone, I'm trying to select multiple rows from one table, depending on the ID given from another table. I've got it half working with the code below, however it echo's out each blog multiple times depending on how many different tags are assigned to it, how would I go about so it displays multiple tag's on one copy of the blog post? $sqlCommand = "SELECT blogid, blogtitle, content, blogtime, category, blogseourl, author FROM blog ORDER BY blogtime DESC"; $query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error()); $blogDisplay = ''; while ($row = mysqli_fetch_array($query)) { $blogid = $row["blogid"]; $blogtitle = $row["blogtitle"]; $content = $row["content"]; $blogtime = $row["blogtime"]; $category = $row["category"]; $blogseourl = $row["blogseourl"]; $author = $row["author"]; $contentshort = substr($content, 0, 250); $sqlCommand2 = "SELECT tag FROM blogtags WHERE blogid='$blogid'"; $query2 = mysqli_query($myConnection, $sqlCommand2) or die (mysqli_error()); while ($row = mysqli_fetch_array($query2)) { $tag = $row['tag']; $blogDisplay .= '<h1><a href="/blog/'. $blogseourl .'"> ' . $blogtitle . ' </a></h1> ' . $contentshort . '... <a href="/blog/'. $blogseourl .'">Read More...</a><br /><br /> ' . $author . ' posted on ' . $blogtime . ' | Category: ' . $category . ' | Tags: ' . $tag . ' | <a href="/blog/'. $blogseourl .'#disqus_thread"></a>'; } } mysqli_free_result($query); So everything is working correctly apart from it echoing multiple $blogDisplay's for each tag. Anyone got any ideas?
  7. Was hoping I wouldn't have to create another table So I need another table like: BlogID ¦ Tag 1 ¦ testtag1 1 ¦ testtag2 1 ¦ test 2 ¦ testtag2 2 ¦ test 2 ¦ testtag1 To then re-write everything to pull from both tables? I thought it would of been a lot simpler to just use one table and the implode and explode functions
  8. That would work if I only had one tag for each post correct? The tag column has the option of multiple values e.g; "testtag1, testtag2". So if I only used the "LIKE '$pageid'" it will only filter items if they are the exact match so I couldn't have a tag page for testtag1 and a separate page for testtag2 it would have to be a page for both testtag1 and testtag2.
  9. Hey guys, not sure if anyone will be able to help with this but I have a small issue with a select filter I'm trying to use. I'm trying to select posts with the correct tag's to display a list of the posts in the page. I've got it working to a certain extent with the code below, however I have this small issue: If I click the link that says "testtag1" it will filter the posts and only show the posts with testtag1. But If I have a shortened link say the tag is called just "test" it will bring up anything with test in it, so posts with testtag1, testtag2, test will appear. is there a way to refine the LIKE filter in mysql to stop this? if (!$_GET['tagseourl']) { $pageid = ''; } else { $pageid = $_GET['tagseourl']; } $sqlCommand = "SELECT blogid, blogtitle, content, blogtime, category, blogseourl, tag, author FROM blog WHERE tag LIKE '%$pageid%'"; $query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error()); $blogDisplay = ''; while ($row = mysqli_fetch_array($query)) { $blogid = $row["blogid"]; $blogtitle = $row["blogtitle"]; $content = $row["content"]; $blogtime = $row["blogtime"]; $category = $row["category"]; $blogseourl = $row["blogseourl"]; $tag = $row["tag"]; $author = $row["author"]; $contentshort = substr($content, 0, 250); $blogDisplay .= '<h1><a href="/blog/'. $blogseourl .'"> ' . $blogtitle . ' </a></h1> ' . $contentshort . '... <a href="/blog/'. $blogseourl .'">Read More...</a><br /><br /> ' . $author . ' posted on ' . $blogtime . ' | Category: ' . $category . ' | Tags: ' . $tag . ' | <a href="/blog/'. $blogseourl .'#disqus_thread"></a>'; } mysqli_free_result($query); The field tag in the database looks like this: ID ¦ tags 1 ¦ testtag1, testtag2, testtag3 2 ¦ test. testtag1 3 ¦ testtag2, testtag3 etc.
  10. Not sure how its working now but this is what worked no idea why if anyone else is stuck: $sqlCommand = "SELECT tag FROM tags"; $query2 = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error()); $tagoptions=""; $posttag = explode(',', str_replace(' ', '', $posttag)); while ($row = mysqli_fetch_array($query2)) { $tag = $row["tag"]; if (in_array($tag, $posttag)) { $checked = "checked"; } else { $checked = ""; } $tagoptions.="<input type='checkbox' name='checkboxname[]' value='$tag' $checked>".$tag.'<br>'; }
  11. Yes, unfortunately all of them are $posttag in my script. No idea where this is going wrong.
  12. $tagoptions was echoed yes, it output the correct list of check boxes but none were selected. $posttag was pulled from the database column posttag which is a text field, and had the value of "tag1, tag2" so the check boxes for tag1 and tag2 should be selected.
  13. Thanks for the reply, this still unfortunately does nothing I've tried to take it back to basics and remove the database calls just to figure out how to get this to work: <?php $posttag = "tag1, tag2"; $posttag = explode(',', str_replace(' ', '', $posttag)); $tag = "tag1, tag2, tag3"; if (in_array($tag, $posttag)) { $checked = "checked"; } else { $checked = ""; } } echo $posttag; ?> <br> <input type='checkbox' name='checkboxname[1]' value='tag1' <?php echo $checked ?>>Tag1<br> <input type='checkbox' name='checkboxname[2]' value='tag2' <?php echo $checked ?>>Tag2<br> <input type='checkbox' name='checkboxname[3]' value='tag3' <?php echo $checked ?>>Tag3<br> However this now isn't even working ha, just returns a blank screen
  14. That doesn't seem to do anything, no boxes are checked no matter the value of $posttag. Not sure if I've explained it correctly I'm not the greatest at explaining sorry. $posttag would come through with a value of "tag1, tag2" $tag would come through in an array with my while loop "tag1" "tag2" "tag3"
  15. The posttag is opened up in the array here? $string = $posttag; $array = explode(',', $string); if ($string == $array) { $checked = "checked"; } else { $checked = ""; } I've used explode to separate them but then I'm not sure how to get from that point to checking to check the box?
  16. Post tag comes through as: tag1, tag2 tag1, tag3, tag4 I think it may be an issue on how do I separate the values to then check? Not 100%.
  17. Hey guys, Not sure if anyone is able to help me out I'm trying to split up some data from a table and select check boxes depending on if the tag exists: Database: Table: Tags Fields: id, tag PHP so far: $sqlCommand = "SELECT tag FROM tags"; $query2 = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error()); $tagoptions=""; while ($row = mysqli_fetch_array($query2)) { $tag = $row["tag"]; $string = $posttag; $array = explode(',', $string); if ($string == $tag) { $checked = "checked"; } else { $checked = ""; } $tagoptions.="<input type='checkbox' name='checkboxname[]' value='$tag' $checked>".$tag.'<br>'; } The data in the tag's field: ID - TAG 1 tag1 2 tag2 3 tag3 The tag table is used to generate the tag check boxes. Once they are generated (Which works). I then have the data been requested from a different table which could be multiple options e.g.: tag1, tag3 However if only one tag is selected then the box is checked, if 2 tags or more are selected then neither work. Anyone have any ideas where I am going wrong here?
  18. Hey guys, I'm trying to make the value pulled from the mysql database be the selected option which the list is dynamically selected from a directory. <?php function list_files($the_path) { $handle = dir($the_path); while ($file = $handle->read()) { if (($file != ".") && ($file != "..")) { $options .= "<option value='$file' selected='$picked'>$file</option>\n"; } } return $options; } ?> <select name="tempname"> <?php echo list_files("../templates/pages/"); ?> </select> I'm trying to make the value of $picked to be "true". I've pulled the file name from the database and it is stored in $tempname and I'm trying to use something like: <?php if ($file == $tempname) { $picked = "true"; } ?> But I can't seem to get it to work, I don't think the $file variable can be edited in the function. Anyone got any ideas or suggestions?
  19. It's for fun yes, I'm using this to teach my self more php. How would you suggest doing it so I could have 3 price bands and the ability to override the percentage off then? I'm no php expert so I'm trying to learn.
  20. The prices change weekly for everything anyway so would only be pressing update when they all needed updating anyway, then the special prices would also change weekly after updating.
  21. I figured it out! Not sure how efficient it is but it works ha If anyone else is struggling with this here is what I used: <?php if(isset($_POST['updateprices'])) { $sql1= mysqli_query($myConnection, "REPLACE INTO pricestwo (priceid,productname,productweight,productprice) SELECT priceid,productname,productweight,productprice *0.9 FROM prices"); $sql2= mysqli_query($myConnection, "REPLACE INTO pricesthree (priceid,productname,productweight,productprice) SELECT priceid,productname,productweight,productprice *0.85 FROM prices"); echo "<meta http-equiv=\"refresh\" content=\"0;URL=edit_product_prices.php#tabone-tab\">"; } ?>
  22. As far as I'm aware? I may not be explaining it correctly lets give an example: Product 1 is set to £10.00, I update this across all tables so the data looks like: Tableone Product 1, £10.00 Product 2, £20.00 Tabletwo Product 1, £9.00 Product 2, £18.00 Tablethree Product 1, £8.50 Product 2, £17.00 Now that's what I'm trying to make happen on the update of all the tables. But I currently want to run an offer for users of the tablethree group, I want to reduce product 1 to £6.50 so I go manually update the price in tablethree. Does that make any sense? ha. I've played around with it a bit more now and got to this point: <?php if(isset($_POST['updateprices'])) { $sql1= mysqli_query($myConnection, "REPLACE INTO pricestwo (priceid,productname,productweight,productprice) SELECT priceid,productname,productweight,productprice FROM prices"); $sql2= mysqli_query($myConnection, "REPLACE INTO pricesthree (priceid,productname,productweight,productprice) SELECT priceid,productname,productweight,'$productpricetwo' FROM prices"); echo "<meta http-equiv=\"refresh\" content=\"0;URL=edit_product_prices.php#tabone-tab\">"; } ?> However I still cannot figure out how to reduce the productprice column by a % on update
  23. Thanks for your reply, Unfortunately I need them to be stored separate because once the data is passed to the other tables with the % off I need the ability to manually edit the price for special offers etc for certain price bands.
  24. Yes they will be identical, but editable at the same time (Ability to remove product's and add new ones). So user puts data into price table. Presses button to update pricetwo to the same name,weight, and price with 10% off, and pricethree to the same name, weight, and price with 10% off. If that makes sense? Sorry if I'm not explaining it well.
  25. Thanks for your reply, I've never used inner join, not 100% sure how it works but I've done the following as per your example however it returns a server error. How are the variables p1.priceid defined? <?php // Variables defined for update of multiple tables $priceid = $_POST['priceid'] ; $name = $_POST['productname'] ; $weight = $_POST['productweight']; $price = $_POST['productprice']; if(isset($_POST['updateprices'])) { for($i=0;$i<$count;$i++){ $sql1= mysqli_query($myConnection, "UPDATE pricetwo p2 INNER JOIN priceone p1 USING (priceid) SET p2.price = p1.price * 0.9, p2.productname = '$name', p2.producweight = $weight WHERE p1.priceid = $priceid"; $sql2= mysqli_query($myConnection, "UPDATE pricesthree SET productname='$name[$i]', productweight='$weight[$i]', productprice='$price[$i]' WHERE priceid='$priceid[$i]'"); } echo "<meta http-equiv=\"refresh\" content=\"0;URL=edit_product_prices.php#tabone-tab\">"; } ?> Not sure if I'm completely off the mark here, feeling a tad out of my knowledge depth at the moment!
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.