[Get Shipping Rates Function Not Working]

Here is my code, it is not working.

	 
<?PHP 

function USPSParcelRate($weight,$dest_zip) {

$userName = '696RYANW7228';
$orig_zip = '11705'; 


$url = "http://Production.ShippingAPIs.com/ShippingAPI.dll";
$ch = curl_init();


curl_setopt($ch, CURLOPT_URL,$url);
curl_setopt($ch, CURLOPT_HEADER, 1);
curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);


curl_setopt($ch, CURLOPT_POST, 1);

$data = "API=RateV3&XML=<RateV3Request USERID=\"$userName\"><Package ID=\"1ST\"><Service>PRIORITY</Service><ZipOrigination>$orig_zip</ZipOrigination><ZipDestination>$dest_zip</ZipDestination><Pounds>$weight</Pounds><Ounces>0</Ounces><Size>REGULAR</Size><Machinable>TRUE</Machinable></Package></RateV3Request>";

// send the POST values to USPS
curl_setopt($ch, CURLOPT_POSTFIELDS,$data);

$result=curl_exec ($ch);
$data = strstr($result, '<?');
// echo '<!-- '. $data. ' -->'; // Uncomment to show XML in comments
$xml_parser = xml_parser_create();
xml_parse_into_struct($xml_parser, $data, $vals, $index);
xml_parser_free($xml_parser);
$params = array();
$level = array();
foreach ($vals as $xml_elem) {
if ($xml_elem['type'] == 'open') {
	if (array_key_exists('attributes',$xml_elem)) {
		list($level[$xml_elem['level']],$extra) = array_values($xml_elem['attributes']);
	} else {
	$level[$xml_elem['level']] = $xml_elem['tag'];
	}
}
if ($xml_elem['type'] == 'complete') {
$start_level = 1;
$php_stmt = '$params';
while($start_level < $xml_elem['level']) {
	$php_stmt .= '[$level['.$start_level.']]';
	$start_level++;
}
$php_stmt .= '[$xml_elem[\'tag\']] = $xml_elem[\'value\'];';
eval($php_stmt);
}
}
curl_close($ch);
// echo '<pre>'; print_r($params); echo'</pre>'; // Uncomment to see xml tags
return $params['RATEV3RESPONSE']['1ST']['1']['RATE'];
}

echo USPSParcelRate(10,11705);

?>

 

[new Website]

My servers are hosted in Texas.

[New Site]

I also recently did folkartdecoys.com. I am just fixing a few bugs now.

[Two Where Statements]

Thank You

[Two Where Statements]

I need to get mysql information. This is incorrect what should I use instead.

 

WHERE username = '$user', id = '$getid' 

[New Site]

I just created a site for a client. They seem happy with it but there is still major construction to be done.

 

http://www.damantiques.com

[Best Domain Name For An Antique Store]

It is taken but is up for sale $1,788. Their budget is $500

[Best Domain Name For An Antique Store]

Red Door Antiques

[Best Domain Name For An Antique Store]

No but something related to antiques

[Best Domain Name For An Antique Store]

Can you think of one? If you don't like any of them.

[PHP Project - Help Needed]

I do not need a programmer anymore.

[new Website]

Yes

 

Username: phpfreaks

Password: password

[PHP Project - Help Needed]

I need help with my website www.celbre.com. It is a website for people/small businesses to give their customers updates. If you helped code you would receive a percentage of the profits.

 

PHP/HTML Programmer [1] - 20% of profits

PHP Debugger [1] - 20% of profits

Graphics [1] - 20% of profits

 

PHP Programer:

 

Needs to be able to search the profiles on the database and if the user does not want to be in search results block it.

Block HTML tags in text boxes.

 

PHP Debugger:

 

Check over the php programmer's script and make sure it works properly.

 

Graphics:

 

Simple graphics are needed.

 

 

Please email me what you can do [email protected]

 

P.S. I am not the best programmer.

[SQL Syntax Error]

Yeah, I could not think of one to use. I will use $queryoutcome

[SQL Syntax Error]

This is my code:

$req = $_GET['s'];
$as = "SELECT users.username, users.fname, users.lname, users.tags FROM users.users WHERE ";
$terms = explode(" ", $req);

foreach($terms as $smart){
$a++;

if ($a == 1)
$as .= "users.tags = '$req' ";

else

$as .= "OR users.tags LIKE '$req' ";

}


mysql_select_db($database_Users, $Users);
$query_Recordset1 = "SELECT username, fname, lname, tags FROM users";
$Recordset1 = mysql_query($smart, $Users) or die(mysql_error());
$row_Recordset1 = mysql_fetch_assoc($smart);
$totalRows_Recordset1 = mysql_num_rows($smart);

 

This is What I Get:

 

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'nah' at line 1

 

URL:

 

http://www.celbre.com/search.php?s=nah&button=Search

 

[new Website]

I fixed my severs, you should be able to get on it now.

[new Website]

I creates a section on my website called profiles. I am doing updates on it tell me what you think.

 

Old But Current Site: http://www.ryanweekly.com/user/?p=nah

 

New Site: http://www.celbre.com

[blob - display image]

I have small images uploaded to mysql with blob. How would I display them

 

Like This?

<img src="<?PHP echo $row_rweek['image'] ?>" />

 

[Web Host List]

hostgator.com

[Hello]

I don't know where to put this, but should I trademark my website name & logo?

[Hover Fade On Navigation Menu]

Is it possible to make the highlight on hover fade in and out?

 

http://folkartdecoys.starsquad.info/index.php

[Customer's Website]

I am working on a website for a customer.

 

How is it so far and how can I improve it.

 

http://folkartdecoys.starsquad.info/

[+1 if file exists]

<?PHP 
//Data to write
$newsletterinfo = '_a';
$newsletterinfo = $_REQUEST['email'];
//Open the file directory
$fdir = fopen('created/1.txt', 'a');
//Write The Data
fwrite($fdir, $newsletterinfo );
//Close the connection
fclose($fdir);
?>

[Stick Pivot + Games]

This is the link to your site right? http://animatedgameplay.webs.com/

[Site for a local tree surgery company]

Its great - By the way it says "Untitled Document" Remember to change that. (;