[Help hide private information]

Hi, thanks for the respond.

I've look around for a way to edit the setting but the only information (from the provided link) I can change are email address and password. Is there anyway to change the other information such as birthday?

[Help hide private information]

Hi. Seeing that this site doesn't let users to terminate their account, may I request a magic button to hide our information? I never contribute in any post so I am pretty much useless. I need to change / hide private information.

[Function to add <p> tags]

woops I am off topic. byeeee

[Function to add <p> tags]

try using <pre> </pre>

it preserves spaces and line breaks

[if, else help]

Did you mean the form <form id="to-watch"> ?

And is it calling below's javascript function?

$(function() 
{
$('#to-watch').submit(function(event) {
            event.preventDefault()
            $(this).hide('fast');
            var movie_id_watch = $('#to-watch [name="MOVIE_ID_TO_WATCH"]').val();
            var user_id_watch = $('#to-watch [name="USER_ID_TO_WATCH"]').val();
            $.ajax({type: 'POST', url: 'to_play_add.php', cache: false, timeout: 10000,
                  data: {to_watch_user_id: user_id_watch, to_watch_movie_id: movie_id_watch},
                  success: function() {
                        $('#div_show_play').text('Added to your to play list').
                              append(html).show('fast');
                  },
                  error: function() {
                        $('#div_show_play').text('There is a problem').show('fast');
                  }
            });
      });
});

 

as far as I know we cannot call function using that way. Sorry if I misunderstood, though.

Guess I'm not helping 

[if, else help]

I don't know if this is going to help or not, but instead of escaping from php a few times for html, why don't you just use echo instead, so the coding will look neat. Just a suggestion if you don't mind.

Is the error said "unexpected $end" ? because you didn't tell the second problem.

I tried to correct it and the error is because of the first 'if' isn't close (the bracket is still open).

 

<div id="to_play"> 
<?php
if($rank>=1)
{
include"scripts/connect.php" ;
mysql_connect('localhost',$username,$password);
@mysql_select_db($database) or die( "Unable to select database");
$userquery_to_play = mysql_query("SELECT * FROM to_watch WHERE (to_watch_movie_id='$title') AND (to_watch_user_id='$loggedinusername')");

if (mysql_num_rows($userquery_to_play) > 0) 
{
$user_to_play = mysql_result($userquery_to_play,$i,"to_watch_user_id");
echo "<div><span class='rulesub'>This is in your to play list</span><br></div>";
}
else if($rank>=1)
{
include"scripts/connect.php" ;
mysql_connect('localhost',$username,$password);
@mysql_select_db($database) or die( "Unable to select database");
$userquery_in_rating = mysql_query("SELECT * FROM rateing WHERE (title='$title') AND (user_id='$loggedinusername')");
}
else 
{
echo "<script type='text/javascript'>";
//  your javascript
echo "</script>";
echo "<form id='to-watch'>";
echo "<input type='hidden' name='MOVIE_ID_TO_WATCH' value='<?php echo $title; ?>'>";
echo "<input type='hidden' name='USER_ID_TO_WATCH' value='<?php echo $loggedinusername; ?>'>";
echo "<input type='submit' value='Add to my to play list'>";
echo "</form>";
echo "<div id='div_show_play' class='rulesub' align='left'>";
echo "</div>";

}
}
?>

 

sorry if it doesn't help.

[Click name from one mysql table to show report on other page]

how is the latest result? Does it giving you all the query from your database?

Maybe it should be this:

 

$topic = $_Get['id'];
$result = mysql_query("SELECT * FROM students WHERE topic LIKE'%$topic%'");

while($row = mysql_fetch_array($result))
  {
echo "<tr><p>";
  echo "<th><p>" . $row['month']." " .$row['datetime']."</p></th>";
  echo"<th><p>". $row['topic'] ."</p></th>"; 
  echo "<th><p>" . $row['gender'] . "</p></th>";
  echo "<th><p>" . $row['fname'] . "   " . $row['lname'] . "</p></th>";
  echo "<th ><p>" . $row['id'] . "</p></th>";
  echo "</tr>";
  
echo "</table>";

 

Because if the $result is $result = mysql_query("SELECT * FROM students)

then the looping will fetch all the array because your $result doesn't have condition.

 

 

[displaying results from a mysql database]

hello, maybe you should add

$term=$_POST['term'];

 

because when you hit 'search', the keyword you are searching is saved in $_POST['term']

so the $term in your sql instruction is equal to blank, which make it gives you all the result.

Hope it helps : )