uppalakishore

April 15, 2013

I want to display the image when i use the tag

<img src="image.php?f=f3.jpg" alt="Image" />

Any help Wil be Appreciable...

April 8, 2013

Thank u @ trq and l0gic...
But i slightly confused...

I found a link http://michael.theirwinfamily.net/articles/csshtml/protecting-images-using-php-and-htaccess

I added the following .ht access files to Image directory and to main directory

.htaccess in main folder:




RewriteEngine on
RewriteCond %{HTTP_REFERER} ^$
RewriteCond %{SCRIPT_FILENAME} image\.php
RewriteRule (.*) image.php?onlyHappensFromHTACCESS=denied [QSA,L]

.htaccess in Images folder:


#Prevent directory listing
Options -Indexes
#Prevent images from being viewed
<Files *>
  deny from all
</Files>

image.php:

<?php
if (!isset($_GET['onlyHappensFromHTACCESS'])) {
   $_GET['f'] = "./Images/" . $_GET['f'];                            //my folder name="Images";
    $type = getFileType($_GET['f']);
    if (acceptableType($type)) {
        if (goodTiming()) {
            header("Content-type: $type");
         echo file_get_contents($_GET['f']);
            exit;
        }
    }
    header('HTTP/1.1 403 Forbidden');
    exit;
}
function getFileType($file) {
  if (function_exists("mime_content_type"))
    return mime_content_type($file);
  else if (function_exists("finfo_open")) {
    $finfo = finfo_open(FILEINFO_MIME_TYPE);
    $type = finfo_file($finfo, $file);
    finfo_close($finfo);
    return $type;
  }
  else {
    $types = array(
      'jpg' => 'image/jpeg', 'jpeg' => 'image/jpeg', 'png' => 'image/png',
      'gif' => 'image/gif', 'bmp' => 'image/bmp'
    );
    $ext = substr($file, strrpos($file, '.') + 1);
    if (key_exists($ext, $types)) return $types[$ext];
    return "unknown";
  }
}
function acceptableType($type) {
    $array = array("image/jpeg", "image/jpg", "image/png", "image/png", "image/gif");
    if (in_array($type, $array))
        return true;
    return false;
}
function goodTiming() {
    $n = time();
    session_start();
    if ($n - $_SESSION['lastcheck'] > 2 )
        return false;
    return true;
}
?>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<html>
<head>
  <meta http-equiv="Content-type" content="text/html; charset=utf-8" />
  <title>Image Denied</title>
  <style type="text/css" media="screen">
    body {
        background-color: #ccc;
        font-family: Helvetica, Arial;
    }
    #wrapper {
        margin: 30px auto;
        background-color: #ffffff;
        -moz-border-radius: 15px;
        -webkit-border-radius: 15px;
        border-radius: 15px;
        width: 800px;
        padding: 20px;
    }
  </style>
</head>
<div id="wrapper">
  <h3>Access Denied!</h3>
  You have tried to access an image, but due to security reasons, you cannot view the image.
  If you wish to use the image you requested, please contact me.
</div>
</html>

index1.php:

<?php session_start(); $_SESSION['lastcheck'] = time(); ?>
<html>
<head>
    <title>Page Title</title>
    <style type="text/css">
        .image {
            overflow: hidden;
            position: relative;
            float: left;
        }
        .image .cover, .image .cover img {
            position: absolute;
            top: 0px;
            left: 0px;
            width: 100%;
            height: 100%;
        }
    </style>
</head>
<body>
    <div class="image">
        <img src="image.php?f=f3.jpg" alt="Image" />
        <div class="cover"><img src="Transparent.gif" alt=""  /></div>
    </div>
</body>
</html>

I got the output as

"Image"(Means alt will be loaded)...
when i right click on it,and select View Image "Transparent.gif" will be displaying normally.

I can't understant what is the problem here...

April 6, 2013

The above code is working fine in case of a particular image like

freak_test.php?image=f3.jpg (The code is saved in a page "freak_test.php")

In case of,

<img src="freak_test.php?image=f3.jpg" width=200 height=300 />

It will not displaying the image

And when Right click on the image and click "View Image" it displays the following error

Deprecated: Function eregi() is deprecated in F:\xampp\htdocs\photo_gallery\User_data\User_details\freak_test.php

any Suggestions?

March 23, 2013

@ haku....

I tried and rename the directory as "Images" but i found it displaying the image path as it is and it will randomize the images in the directory when i refresh the page...

What i want is I want to hide the location/path of the image...

sum where i got some code i will try it...


<?php

 
  $imagedir = "Images/" ;

  $validprefixes = array (
    "http://localhost/photo_gallery/index.com",
    "localhost/photo_gallery/"
  ) ;

 
  $homepage = "index.php" ;

  function isreferrerokay ( $referrer, $validprefixes )
  {
    $validreferrer = 0 ;
    $authreferrer  = current( $validprefixes );
    while ($authreferrer) {
      if (eregi( "^https?://$authreferrer/", $referrer )) {
        $validreferrer = 1 ;
        break ;
      }
      $authreferrer = next( $validprefixes );
    }
    return $validreferrer ;
  }

  //----------------------- main program -----------------------

  $image = $_GET['image'] ;
  $referrer = getenv( "HTTP_REFERER" );

  if (isset($_GET['image'])) {

    if (empty($referrer) ||
      isreferrerokay( $referrer, $validprefixes )) {

      $imagepath = $imagedir . $image ;

      $imageinfo = getimagesize( $imagepath );
      if ($imageinfo[2] == 1) {
        $imagetype = "gif" ;
      }
      elseif ($imageinfo[2] == 2) {
        $imagetype = "jpeg" ;
      }
      elseif ($imageinfo[2] == 3) {
        $imagetype = "png" ;
      }
      else {
        header( "HTTP/1.0 404 Not Found" );
        exit ;
      }

      header( "Content-type: image/$imagetype" );
      @readfile( $imagepath );

    }
    else {

      if (isset($email)) {
        mail( $email, "Bandwidth Theft Alert",
           "WARNING:\n\n$referrer\ntried to access\n$image\n",
           "From: CHImageGuard <$email>" );
      }
      header( "HTTP/1.0 404 Not Found" );
    }
  }
  else {
    header( "Location: $homepage" );
  }

?>

March 22, 2013

Thank u @ haku....

I will try....

March 21, 2013

First of All Thanks For Reading...

I Want to hide Image/File path, mainly i want to hide the "image path" there by Logged in users only see the images.

1) My Problem is When a user Logged in and opend his personal photos, the image path will be "http://localhost/photo_gallery/User_data/Personal_photos/username/kicku.jpg" .

2)But when i entered the path in the browser without login the images keep displaying...

3)So i want to hide the image path for security purpose...

Any help, Appreciable...

March 19, 2013

Thanks For ur Reply @

Christian F...

I Solved it...as follows:


$mail=new PHPMailer();

$mail->IsSMTP();                   //Important b'coz by this stmt we sent mail using smtp
$mail->SMTPAuth = true;       // enable SMTP authentication
$mail->SMTPSecure = "ssl";  // sets the prefix to the servier
$mail->Host = "smtp.gmail.com"; // sets GMAIL as the SMTP server
$mail->Port = 465; // set the SMTP port for the GMAIL server
$mail->Username = "yourmail@gmail.com"; // GMAIL username
$mail->Password = "your mail password"; // GMAIL password

$mail->FromName = "PhotoGallery:Admin";
$mail->From = "from address@gmail.com";
$mail->AddAddress($to,$to_name);
$mail->Subject = $subject;

$mail->Body ="body of the message";
$result=$mail->Send();
    return $result;

March 1, 2013

When i run the following code,it will shows the error...

Mail error: The following From address failed: uppalakishore@hotmail.com : Called Mail() without being connected

<?php
require_once("./Includes/PHPMailer/class.phpmailer.php");
//	require_once("./Includes/PHPMailer/class.smtp.php");
define('GUSER', 'myname@gmail.com'); // GMail username
define('GPWD', 'mypassword'); // GMail password
function smtpmailer($to, $from, $from_name, $subject, $body) { 
	global $error;
	$mail = new PHPMailer();  // create a new object
	$mail->IsSMTP(); // enable SMTP
	$mail->SMTPDebug = 0;  // debugging: 1 = errors and messages, 2 = messages only
	$mail->SMTPAuth = true;  // authentication enabled
	$mail->SMTPSecure = 'ssl'; // secure transfer enabled REQUIRED for GMail
	$mail->Host = 'smtp.gmail.com';
	$mail->Port = 465; 
	$mail->Username = GUSER;  
	$mail->Password = GPWD;           
	$mail->SetFrom($from, $from_name);
	$mail->Subject = $subject;
	$mail->Body = $body;
	$mail->AddAddress($to);
	if(!$mail->Send()) {
		$error = 'Mail error: '.$mail->ErrorInfo; 
		return false;
	} else {
		$error = 'Message sent!';
		return true;
	}
}
if (smtpmailer('myname@gmail.com', 'uppalakishore@hotmail.com', 'PHotoGallery', 'test mail message', 'Hello World!')) {
	// do something
}
if (!empty($error)) echo $error;
?>

Thanks in Advance For Watching...

February 23, 2013

OK Thanks...

I Will Start Learning...

February 23, 2013

Thank You Christian F...

I had simple client and server socket programs, the client sends a message to server, then the server reverses the string(sent by client) and send it to server.

Client.php

[bR]

<?php
$host = "127.0.0.1";
$port = 80;

[color=#ff0000][b]$message ="Hello world";[/b][/color]
echo "<br>\nMessage To server :".$message."\n";
// create socket
$socket = socket_create(AF_INET, SOCK_STREAM, 0) or
die("Could not create socket\n");
if($socket)echo "<br>Client Socket Created\n";
//
//// connect to server
$result = socket_connect($socket, $host, $port) or
die("Could not connect to server\n");
if($result)echo "<br>Socket Connected to Server : $host on Port : $port\n";
//
//while(1){
// send string to server
echo "<br>Sending Data to the Server...\n";
sleep(1);
socket_write($socket, $message, strlen($message)) or
die("Could not send data to server\n");
//
// get server response
echo "<br>Getting Responce From the Server...\n";
sleep(1);
$result = socket_read ($socket, 1024) or die("Could
//not read server response\n");
echo "Reply From Server :".$result;
//}
// close socket
socket_close($socket);

?>

Server.php

[bR]

<?php
// set some variables
$host = "127.0.0.1";
$port = 80;
// don't timeout!
set_time_limit(0);
// create socket
$socket = socket_create(AF_INET, SOCK_STREAM, 0) or
die("Could not create socket\n");
if($socket)echo "<br>Socket Created\n";
// bind socket to port
$result = socket_bind($socket, $host, $port) or die("Could not bind to socket\n");
if($result)echo "<br>Socket Binded\n";
// start listening for connections
$result = socket_listen($socket, 3) or die("Could not
set up socket listener\n");
if($result)echo "<br>Socket Listening Connections....\n";
// accept incoming connections
// spawn another socket to handle communication
$spawn = socket_accept($socket) or die("Could not
accept incoming connection\n");
if($spawn)echo "<br>Socket Accepted Incoming Connections...\n";
//while(1){
// read client input
echo "<br>\nReading Input...\n";
sleep(1);
$input = socket_read($spawn, 2048) or die("Could not
read input\n");

// clean up input string
$input = trim($input);
echo "<br>Client Message : ".$input;
// reverse client input and send back
$output = strrev($input) . "\n";
echo "<br>\nResponce...\n";
sleep(1);
socket_write($spawn, $output, strlen ($output)) or
die("Could not write output\n");
//}
// close sockets
socket_close($spawn);
socket_close($socket);
?>

The program is executed, the problem is i want to enter that message into database using server program...I can't get any idea how to do that...

Thanks in Advance...

February 7, 2013

Thank you @Christian F. for your responce...

The person is my Teacher...even i told the complexity u explained here to him...he didn't convinced...

any way Thanks For your Preceious Responce...

February 7, 2013

Thanq @trq for your responce...

But i need Socket programming in php that will enter the Form Field Values(entered Values) into database...

Means as follows:

$val=$_GET['name'];

Then how can i enter '$val' value into database using socket,that is my problem...

anyway THANKS...

February 5, 2013

ofcourse @trq...

but somebody asked insert and retrieve data by using sockets.....that's why...

February 5, 2013

Suppose i had a Registration Form with multiple fileds(like first name,last name etc).And i want to enter the entered values into MySql using Sockets...

I need the example showing inserting data into Mysql using sockets.Bcoz i learned something about php sockets but i don't have the basic idea how to implement them...Even i tried so many examples but i tired of having so many complexities like socket_bind,socket_accept,socket_listen errors...

THANKS IN ADVANCE...

October 4, 2012

CTRL + Q to Enable/Disable GoPhoto.it

I think, the Problem might be here:

session_start();
if (isset($_POST['disciplines'])) $_SESSION['dis']=$_POST['disciplines'];

[code]
<html>
<body>
 <a href="home.php" align="left" style="text-decoration:none;font:verdana;color:red;padding: 5px;margin-left:40px;"><button class="btn" onclick="javascript:location.href='home.php'" class="btn" style="font-weight: bold;">Home Page</button></a>
 <button class="btn" onclick="history.go(-1);return true;">Go Back</button>

 <?php
//					 // Make sure that PATH_INFO is set, and not ORIG_PATH_INFO as some hosts seem to use.
//					 if (isset ($_SERVER['ORIG_PATH_INFO']) && $_SERVER['ORIG_PATH_INFO'] != $_SERVER['PHP_SELF']) {
//					 $_SERVER['PATH_INFO'] = $_SERVER['ORIG_PATH_INFO'];
//					 }
//
//					 // Security measure, to avoid XSS exploit.
//					 if (!empty ($_SERVER['PATH_INFO']) && strrpos ($_SERVER['PHP_SELF'], $_SERVER['PATH_INFO'])) {
//
//
//
//					 $_SERVER['PHP_SELF'] = substr ($_SERVER['PHP_SELF'], 0, -(strlen ($_SERVER['PATH_INFO'])));
//					 }

session_start();
 if (isset($_POST['disciplines'])) $_SESSION['dis']=$_POST['disciplines'];
				 include('db_connect.php');
				 // how many rows to show per page
				 $rowsPerPage = 4;
				 // by default we show first page
				 $pageNum = 1;
				 // if $_GET['page'] defined, use it as page number
				 if(isset($_GET['page']))
				 {
					 $pageNum = $_GET['page'];
				 }
				 // counting the offset,example we want 5 rows per page,offset=(1-1)*5=0(means 0 to 5 rows on first page,(2-1)*5=5(5 to 5 on second page)
				 $offset = ($pageNum - 1) * $rowsPerPage;
				 $result=mysql_query("select * from student_master where Disciplines='" . mysql_real_escape_string($_SESSION['dis']) . "' LIMIT $offset,$rowsPerPage") or die('Error : '. mysql_error());
				 $result2=mysql_query("select count(*) from student_master where Disciplines='".mysql_real_escape_string($_SESSION['dis'])."'");
					 echo "<table align='right'><tr><td><fieldset border='1' class='fieldmoz'>Total ".mysql_real_escape_string($_SESSION['dis'])." Students = <font color='red' ><b>".mysql_result($result2,0)."</fieldset></b></font></td></tr></table>
							 <center><h2 align='center' class='spl_heading'><font color=green>".mysql_real_escape_string($_SESSION['dis'])."</font> Students Details : </h2></center>
								 <table width='70%' cellpadding='2' cellspacing='2' border='1' align='center'>
							 <tr class='fade_bg' align='center'>
							 <td class='spl_bgcolor'>Enrollment No</td>
							 <td>Name</td>

							 <td>Discipline</td>

							 <td>Year</td>

							 <td>Photo</td>
							 </tr>";
					 while($row=mysql_fetch_row($result))
					 {
						 echo " <tr class='sp_table_row'>
								 <td class='span' width='16%' align='center'><a class='underline' href='all_click_details.php?En_no=$row[0]'>$row[0]</a></td>
								 <td width='20%'>$row[1]</td>

								 <td align='center' width='10%'>$row[4]</td>

								 <td width='10%' align='center'>$row[7]</td>

								 <td width='6%' align='center'><img src='upload/$row[9]' alt='$row[1]' title='$row[1]' align='center' style='-moz-border-radius:4px;' class='magnify' data-magnifyduration='800' width='90' height='110'></td>

						 </tr>";
					 }
						 echo "<tfoot><tr><td colspan=10><marquee behavior='alternate' scrollamount='3' align='center' class='yellow'>Click on Image to Enlarge & Resize</marquee></td></tr></tfoot>
							 </table><br>
							 ";

							 // how many rows we have in database
							 $result1=mysql_query("select count(Disciplines) from student_master where Disciplines='".mysql_real_escape_string($_SESSION['dis'])."'");
							 $row=mysql_fetch_row($result1);
							 $numrows=$row[0];
						 // how many pages we have when using paging?
						 $maxPage = ceil($numrows/$rowsPerPage);
						 // print the link to access each page
						 $self = $_SERVER['PHP_SELF'];
						 $nav = '';
						 for($page = 1; $page <= $maxPage; $page++)
						 {
							 if ($page == $pageNum)
							 {
								 $nav .= " <span class='bgc'><b> $page </span> |</b>"; // no need to create a link to current page
							 }
							 else
							 {
								 $nav .= " <a href=\"$self?page=$page\">$page</a> <b>|</b>";
							 }
						 }
						 // ... still more code coming
						 if ($pageNum > 1)
						 {
							 $page = $pageNum - 1;
							 $prev = " <a href=\"$self?page=$page\">[Prev]</a> <b>|</b>";
							 $first = " <a href=\"$self?page=1\">[First Page]</a>";
						 }
						 else
						 {
							 $prev = ' '; // we're on page one, don't print previous link
							 $first = ' '; // nor the first page link
						 }
						 if ($pageNum < $maxPage)
						 {
							 $page = $pageNum + 1;
							 $next = " <a href=\"$self?page=$page\">[Next]</a> <b>|</b>";
							 $last = " <a href=\"$self?page=$maxPage\">[Last Page]</a>";
						 }
						 else
						 {
							 $next = ' '; // we're on the last page, don't print next link
							 $last = ' '; // nor the last page link
						 }
						 // print the navigation link
						 echo "<div class='pager'><center>".$first . $prev . $nav . $next . $last."</center></div>";
						 echo "<center><br><button onclick='javascript:window.print()' value=''class='btn' style='width:100;height:25;'>Print</button></center>";
						 // and close the database connection
						 mysql_close();

					 ?>
</body>
</html>

When i run the above code it will give correct results in one system,when i run it on my laptop it won't produce the same result....i think there might be an error in passing SESSION VARIABLES to the next page.(B'Coz when i click on next page it will display empty page with table headers ony...

I can't understand whether it is coding problem or my Laptop OS Problem(b'coz it will run correctly on other system)....

September 27, 2012

I tried the following code by applying SESSION (Some times working properly) but i got the Error,Means it will executed in one system and it won't work in other system

session_start();
if (isset($_POST['disciplines'])) $_SESSION['dis']=$_POST['disciplines'];
include('db_connect.php');
$rowsPerPage =4;

// by default we show first page
$pageNum = 1;

// if $_GET['page'] defined, use it as page number
if(isset($_GET['page']))
{
$pageNum = $_GET['page'];
}

// counting the offset
$offset = ($pageNum - 1) * $rowsPerPage;

$result=mysql_query("select * from student_master where Disciplines='" . mysql_real_escape_string($_SESSION['dis']) . "' LIMIT $offset,$rowsPerPage");
if(mysql_num_rows($result)>0)
{
echo "
".mysql_real_escape_string($_SESSION['dis'])." Students Details :












";
while($row=mysql_fetch_row($result))
{
echo "










";

}
echo "

Enrollment No    Name    Father's Nname    Address    Discipline    Semester    Year    Email    Mobile Number    Photo
$row[0]    $row[1]    $row[2]    $row[3]    $row[4]    $row[5]    $row[7]    $row[6]    $row[8]    Upload Image
Click on Image to Enlarge & Resize



";
// how many rows we have in database
$query = "SELECT COUNT(En_no) AS numrows FROM student_master where Disciplines='".mysql_real_escape_string($_SESSION['dis'])."'";
$result1 = mysql_query($query) or die('Error, query failed');
$row = mysql_fetch_array($result1, MYSQL_ASSOC);
$numrows = $row['numrows'];

// how many pages we have when using paging?
$maxPage = ceil($numrows/$rowsPerPage);

// print the link to access each page
$self = $_SERVER['PHP_SELF'];
$nav = '';

for($page = 1; $page <= $maxPage; $page++)
{
if ($page == $pageNum)
{
$nav .= "  $page  "; // no need to create a link to current page
}
else
{
$nav .= " $page ";
}
}

// ... still more code coming
if ($pageNum > 1)
{
$page = $pageNum - 1;
$prev = " [Prev] ";

$first = " [First Page]";
}
else
{
$prev = ' '; // we're on page one, don't print previous link
$first = ' '; // nor the first page link
}

if ($pageNum < $maxPage)
{
$page = $pageNum + 1;
$next = " [Next] ";

$last = " [Last Page]";
}
else
{
$next = ' '; // we're on the last page, don't print next link
$last = ' '; // nor the last page link
}

// print the navigation link
echo "
".$first . $prev . $nav . $next . $last."
";
echo "
To search again,Click here . . .
";
}
else
{
echo "
Error Occured. Try Again . . .

";
}


?>

When i Run the above code i got that the error was in the following line....

"select * from student_master where Disciplines='" . mysql_real_escape_string($_SESSION['dis']) . "' LIMIT $offset,$rowsPerPage"

And Thanks In Advance...

September 20, 2012

I'm sory :shy: to say this...i don't know how to avoid $_SERVER['PHP_SELF'],and it is linked with Overall pages.....

// print the link to access each page
                        $self = $_SERVER['PHP_SELF'];
                        $nav  = '';

                        for($page = 1; $page <= $maxPage; $page++)
                        {
                        if ($page == $pageNum)
                        {
                            $nav .= "  <span class='bgc'><b> $page </b></span> "; // no need to create a link to current page
                        }
                        else
                        {
                            $nav .= "  <a href=\"$self?page=$page\">$page</a> ";
                        }
                        }

                        // ... still more code coming
                        if ($pageNum > 1)
                        {
                        $page  = $pageNum - 1;
                        $prev  = "  <a href=\"$self?page=$page\">[Prev]</a> ";

                        $first = "  <a href=\"$self?page=1\">[First Page]</a>";
                        }
                        else
                        {
                        $prev  = ' '; // we're on page one, don't print previous link
                        $first = ' '; // nor the first page link
                        }

                        if ($pageNum < $maxPage)
                        {
                        $page = $pageNum + 1;
                        $next = "  <a href=\"$self?page=$page\">[Next]</a> ";

                        $last = "  <a href=\"$self?page=$maxPage\">[Last Page]</a>";
                        }
                        else
                        {
                        $next = ' '; // we're on the last page, don't print next link
                        $last = ' '; // nor the last page link
                        }

                        // print the navigation link
                        echo "<div class='pager'><center>".$first  .  $prev  .  $nav  .  $next  .  $last."</center></div>";

Will Please tell me how :confused: to do it......There by pagination will work fine......////////First page works fine but when i click on next page nothing will come.....

when i use session_start(), it shows error headers already sent...

Thanks For Your Reply....

September 19, 2012

Actually i'm New here...

And i think the error might be here(following):

////////////// Main Query to get Students belongs to a Particular Department(discipline) /////////

$dis=$_POST['disciplines'];

@session_start();

$_SESSION['dis']=$_POST['disciplines'];

$result=mysql_query("select * from student_master where Disciplines='".$_SESSION['dis']."' LIMIT $offset,$rowsPerPage");

if(mysql_num_rows($result)>0)

{

//print some table headings

while($row=mysql_fetch_row($result))

{

//print some table rows

}

// how many rows we have in database to print for PAGINATION

include('db_connect.php'); //to establish database connection

$query = "select COUNT(Disciplines) AS numrows FROM student_master where Disciplines='".$_SESSION['dis']."'";

$result2 = mysql_query($query) or die('Error, query failed');

$row = mysql_fetch_array($result2,MYSQL_ASSOC);

$numrows = $row['numrows'];

//place some pagination links

}

else

{

echo "Error Occurd"

}

When i run the program first page working fine...when i click on next page it will show msg "Error Occurd"(which is showd in blue color as a else stmt)...i think it may be a session variable problem but i don't know how to rectify it...

THANKS FOR UR REPLY

September 18, 2012

I want to display 4 records per page by using pagination on clicking "showdetails2.php"...Everything will be working fine but when i click on next page...it shows error.....

Simply what i want is i want to display 4 records per page(menas 4 students of each department)

///////////////////////////////////////////////

<?php

include('db_connect.php');

$rowsPerPage =4;

// by default we show first page

$pageNum = 1;

// if $_GET['page'] defined, use it as page number

if(isset($_GET['page']))

{

$pageNum = $_GET['page'];

}

// counting the offset

$offset = ($pageNum - 1) * $rowsPerPage;

@session_start();

$_SESSION['dis']=$_POST['disciplines'];

$result=mysql_query("select * from student_master where Disciplines='".$_SESSION['dis']."' LIMIT $offset,$rowsPerPage ");

if(mysql_num_rows($result)>0)

{

echo "

<h2 align='center' class='spl_heading'><font color=green>".$_SESSION['dis']."</font> Students Details : </h2>

<td class='spl_bgcolor'>Enrollment No</td>

<td>Father's Nname</td>

<td>Address</td>

<td>Discipline</td>

<td>Semester</td>

<td>Email</td>

<td>Mobile Number</td>

<td>Photo</td></tr>";

while($row=mysql_fetch_row($result))

{

echo " <tr class='sp_table_row'>

</tr>";

}

echo "<tfoot><tr><td colspan=10><marquee behavior='alternate' scrollamount='3' class='yellow'>Click on Image to Enlarge & Resize</marquee></td></tr></tfoot>

</table><br>

";

// how many rows we have in database

$query = "SELECT COUNT(En_no) AS numrows FROM student_master where Disciplines='".$_SESSION['dis']."'";

$result1 = mysql_query($query) or die('Error, query failed');

$row = mysql_fetch_array($result1, MYSQL_ASSOC);

$numrows = $row['numrows'];

// how many pages we have when using paging?

$maxPage = ceil($numrows/$rowsPerPage);

// print the link to access each page

$self = $_SERVER['PHP_SELF'];

$nav = '';

for($page = 1; $page <= $maxPage; $page++)

{

if ($page == $pageNum)

{

$nav .= " <span class='bgc'><b> $page </b></span> "; // no need to create a link to current page

}

else

{

$nav .= " <a href=\"$self?page=$page\">$page</a> ";

}

// ... still more code coming

if ($pageNum > 1)

{

$page = $pageNum - 1;

$prev = " <a href=\"$self?page=$page\">[Prev]</a> ";

$first = " <a href=\"$self?page=1\">[First Page]</a>";

}

else

{

$prev = ' '; // we're on page one, don't print previous link

$first = ' '; // nor the first page link

}

if ($pageNum < $maxPage)

{

$page = $pageNum + 1;

$next = " <a href=\"$self?page=$page\">[Next]</a> ";

$last = " <a href=\"$self?page=$maxPage\">[Last Page]</a>";

}

else

{

$next = ' '; // we're on the last page, don't print next link

$last = ' '; // nor the last page link

}

// print the navigation link

echo "<div class='pager'><center>".$first . $prev . $nav . $next . $last."</center></div>";

echo "<center>To search again,Click <a href='search_decipline.php' class='btn'><blink><b>here</b></blink></a> . . .</center>";

}

else

{

echo "<br><center>Error Occured. <a href='search_decipline.php' class='btn'><blink>Try Again</blink></a> . . . </center>";

}

?>

Solve it For me And THANKS IN ADVANCE ....

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