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michelle1404

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Posts posted by michelle1404

    Searching and Calculating Minimum Years of experience

    in MySQL Help

    Posted

    I am trying to select all the employees who have Minimum average years of experience of 3 years.

    If an employee worked for 24 years  in 3 companies the average years of experience is 8 years. For this i got result by doing like this  

    SELECT AVG(DATEDIFF( IF(leaving_date is null or leaving_date = '' or leaving_date='0000-00-00', CURRENT_DATE(), leaving_date), joining_date )) AS Days FROM employee_deatils WHERE eemp_id=? 

    Now while searching of those employees who have worked minimum 3 years (avg) in a company, i am not able to get the results. When i run this query in phpmyadmin, 

    SELECT e.fname, e.lname, ROUND(SUM(DATEDIFF( IF(ed.leaving_date is null or ed.leaving_date = '' or ed.leaving_date='0000-00-00', CURRENT_DATE(), ed.leaving_date), ed.joining_date ))/365,0) AS Diff from employees e INNER JOIN employee_deatils ed ON e.id=ed.eemp_id group by ed.eemp_id

    it shows 2 records one with 0 and 3 years. But how to compare this with entered minimum years i am not getting. 

    Not getting where to put Where condition with =3 years

    Display MQTT data on php page without refreshing the page.

    in Javascript Help

    Posted

    @Barand

    Thanks, the logic worked but i have used this code. 

    Now i want to get the data to variable in php thru javascript instead of displaying it based on id. 

    as i do this  

     <script>
  var res = "helloo";
</script>

<?php $variable = "<script>document.write(res)</script>"; 

echo $variable; ?>

    it works. so as the same if it inside  

    function onMessageArrived(r_message){
        out_msg="Message received "+r_message.payloadString+"<br>";
        out_msg=out_msg+"Message received Topic "+r_message.destinationName;
        //console.log("Message received ",r_message.payloadString);
        console.log(out_msg);
        document.getElementById("messages").innerHTML =out_msg;
        var topic=r_message.destinationName;
       
        if(topic=="house/outside-light")
        {
        document.getElementById("outside-light").innerHTML =r_message.payloadString;
        }
        if(topic=="house/outside-temperature")
        {
            var ot = r_message.payloadString;
        //document.getElementById("outside-temp").innerHTML =r_message.payloadString;
        }
        }



<?php $test="<script>document.write(ot)</script>"; 
echo $test; ?>

    it won't work. 

    Basically i want to get the data into a php variable.

    where i am going wrong, please suggest.

    fetch and display json array data stored in database

    in PHP Coding Help

    Posted

    I am storing a json data which come from server as a message for every 10 seconds. While displaying the data i have to separate it by its type. For single message i have done it but for multiple messages i am not getting how to separate each json message.

    i have attached the sql dump 

    messages.txt

     

    Here is my code to print for single message

    include('includes/Connection.php');
      

    $l1 = $con->prepare("SELECT msg, title FROM messages ORDER BY id DESC limit 1");
$l1->execute();
$cntmsg = $l1->rowCount();
foreach($l1 as $r1)
{
    $m1 =  $r1['msg'];
$someJSON = $m1; 
$someArray = json_decode($someJSON, true);
  
  $pr1 = $someArray["data"]["commsettings"];
  foreach($pr1 as $MyIndex => $MyValue){

 echo $MyValue["name"];  
  }
}

    It is working. But i should display for all the messages like this 

    $l1 = $con->prepare("SELECT msg, title FROM messages ORDER BY id DESC limit 4");
$l1->execute();

    It wont work with my logic. How can i separate the array , i am not getting.

    Display MQTT data on php page without refreshing the page.

    in Javascript Help

    Posted

    I am developing a script for my client where i should be displaying data continuously coming from MQTT and my script is in PHP. Now i can publish and subscribe to topics but only after refreshing i can see the published data in my page. Do i need to use any script for this or how is it?

    Here is my subscribe page 

    <?php

require('phpMQTT.php');


$server = 'localhost';     // change if necessary
$port = 1883;                     // change if necessary
$username = '*****';                   // set your username
$password = '******';                   // set your password
$client_id = 'MyClient'; // make sure this is unique for connecting to sever - you could use uniqid()

$mqtt = new Bluerhinos\phpMQTT($server, $port, $client_id);
if(!$mqtt->connect(true, NULL, $username, $password)) {
	exit(1);
}

$mqtt->debug = true;

$topics['xf/printservice/registration'] = array("qos"=>0, "function"=>"procmsg"); 

$mqtt->subscribe($topics,0);
$start_time = time(); 
$done = 0; 
while (!$done && !hasTimedout() && $mqtt->proc()) {  } 
$mqtt->close(); 
function procmsg($topic,$msg) 
{ 

global $done; 
$done = 1; 
echo "Msg Recieved: ".date("r")."\nTopic:{$topic}\n$msg\n"; } 

function hasTimedout() { global $start_time; return (time() - $start_time > 10); }

    I am running this in localhost.

    How to keep displaying data without refreshing the page . is there any tutorial/script available ? please suggest.

    Refreshing the page after uploading files to folder using dropzone

    in PHP Coding Help

    Posted

    i am using dropzone to upload files to folder as well as database. It is working properly but after uploading page is not getting refreshed . I want to refresh the page. Not getting where to add the option.

    this is my form 

    <form action="file_upload.php" class="dropzone">
			<div>
				<strong>Drop files here or click to upload.</strong>
				
			</div>
            
		</form>

    And here are the options in dropzon.js 

     Dropzone.prototype.defaultOptions = {
      url: null,
      method: "post",
      withCredentials: false,
      parallelUploads: 2,
      uploadMultiple: false,
      maxFilesize: 256,
      paramName: "file",
      createImageThumbnails: true,
      maxThumbnailFilesize: 10,
      thumbnailWidth: 120,
      thumbnailHeight: 120,
      filesizeBase: 1000,
      maxFiles: null,
      params: {},
      clickable: true,
      ignoreHiddenFiles: true,
      acceptedFiles: null,
      acceptedMimeTypes: null,
      autoProcessQueue: true,
      autoQueue: true,
      addRemoveLinks: false,
      previewsContainer: null,
      hiddenInputContainer: "body",
      capture: null,
      renameFilename: null,
      dictDefaultMessage: "Drop files here to upload",
      dictFallbackMessage: "Your browser does not support drag'n'drop file uploads.",
      dictFallbackText: "Please use the fallback form below to upload your files like in the olden days.",
      dictFileTooBig: "File is too big ({{filesize}}MiB). Max filesize: {{maxFilesize}}MiB.",
      dictInvalidFileType: "You can't upload files of this type.",
      dictResponseError: "Server responded with {{statusCode}} code.",
      dictCancelUpload: "Cancel upload",
      dictCancelUploadConfirmation: "Are you sure you want to cancel this upload?",
      dictRemoveFile: "Remove file",
      dictRemoveFileConfirmation: null,
      dictMaxFilesExceeded: "You can not upload any more files.",
      accept: function(file, done) {
        return done();
      },
      init: function() {
        return noop;
      },
      forceFallback: false,

    not getting where can i put the function 

    location.reload()

     

    Access Level with user and page level

    in PHP Coding Help

    Posted · Edited by michelle1404

    My Query return 

    query.PNG.db482e53a7c3bbee080824dacfc0bbb6.PNG

    This is how it displays 

    <!DOCTYPE html>
<html lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<meta name="generator" content="PhpED 19.5 (Build 19523, 64bit)">
<meta name="author" content="Barand">
<meta name="creation-date" content="08/11/2021">
<title>Example</title>
<style type='text/css'>
    li {
        padding: 8px;
    }
    .li0 {
        margin-left: 8px;
    }
    .li1 {
        margin-left: 28px;
    }
    .li2 {
        margin-left: 48px;
    }
</style>
</head>
<body>
    <ul>
<li class='li0'><a href='#'> Sales </a>
</li>
<li class='li0'><a href='#'> Finance </a>
</li>
</ul>
</body>
</html>

    As it joins with the mid page_id from modules and module_access respectively, it wont display those ids which is not there in module_access table . So it is not getting displayed, as module_access table has only 1,3 ids which matches with mid from modules table. 

    Access Level with user and page level

    in PHP Coding Help

    Posted

    @Barand I tried the same  

    <?php
		  //$items = array();

$res = $con->prepare("SELECT mid, mod_name, parent_id, link FROM modules m JOIN module_access ma ON m.mid=ma.page_id WHERE ma.user=? ORDER BY m.mid");
$res->execute([$uID]);
$mods = [];
foreach ($res as $row) {
    $mods[$row['parent_id']][] = $row;
}

function showMenu(&$arr, $parent = 0, $level = 0) 
{
    if (!isset($arr[$parent])) return;
    echo "<ul>\n";
    foreach($arr[$parent] as $rec) {
        echo "<li class='li$level'><a href='{$rec['link']}'> {$rec['mod_name']} </a>\n";
        if (isset($arr[$rec['mid']]))
            showMenu($arr, $rec['mid'], $level+1);
        echo "</li>\n";
    }
    echo "</ul>\n";
}
 showMenu($mods, 0);

?>

    But it shows only module names, not the sub-items under that.

    Access Level with user and page level

    in PHP Coding Help

    Posted

    I have a small php script for crm. i have designed it by module wise. Admin can grant access to each module and sub-items under that modules. 1st step: admin will select modules(Sales, Purchase, Finance) for which he has to give access to a particular user and save the module ids in module_access table. 2nd step : only selected module's sub-items will display to admin , in which he can select to give access

    1st step is done. but in 2nd step i am not able to display only selected modules with the sub-items.

    Here is the table where i stored my data.

    module table 

    mid | mod_name | parent_id  | link
1   | Sales    | 0          | #
2   | Purchase | 0          | #
3   | Finance  | 0          | #
4   | Clients  | 1          | clients.php
5   | Quotes   | 1          | quotes.php
6   | Vendors  | 2          | vendors.php
7   | POs      | 2          | pos.php
8   | Invoices | 3          | invoices.php
9   | Taxes    | 3          | taxes.php
10  | Expense  | 3          | expenses.php

    module_access table 

    id| page_id | user 
1 | 1       | 1
2 | 3       | 1
3 | 4       | 1
4 | 9       | 1
5 | 10      | 1

    user is from another table users where i store user info

    In this example i want to display like this 

    Sales
   Clients (with a checkbox)
Finance
   Taxes   (with a checkbox)
   Expense (with a checkbox)

    I tried like this 

    <?php
          $items = array();

$res = $con->prepare("SELECT m.mid, m.mod_name, m.parent_id, ma.id, ma.page_id, ma.user FROM modules m INNER JOIN module_access ma ON m.mid=ma.page_id WHERE ma.user=? ORDER BY m.mid");
$res->execute([$uID]);
foreach($res as $row) {
 $items[$row['parent_id']][] = $row;
}
function showMenu($items, $parent = null) {

 $index = $parent == null ? '0' : $parent;

 if (empty($items[$index])) {
 
  return;
 }

 echo '<ul', $parent == null ? ' id="subitems" ... ' : '', '>';

 foreach ($items[$index] as $child) {
  echo '<li rel="', $child['mid'], '">', htmlentities($child['mod_name']);
  showMenu($items, $child['mid']);
  echo '</li>';
 }

 echo '</ul>';
}

showMenu($items);
?>

    But it displays like this 

    Sales
Finance

    I am not getting how to query this from database.

    failed form submission with filled data and success message in different division tags

    in PHP Coding Help

    Posted

    I am adding line items in my invoice script, while adding i validate the data. if validation fails, it will display error message with entered data filled in the form. If it clears the validation, data gets submitted to database and displays the same . Here i can add many line items, so this process should keep repeating.

    Everything is working fine. But when the form submits it should display error in one place and display the submitted data in other place.

    Here is my form

      

    <form action="" method="post">
                                        <div class="form-row">
                                            <div class="col-md-4 mb-30">
                                                <label for="validationDefault01">Select Customer</label>
                                            <select name="customer" class="form-control" id="validationDefault01" required>
                                            <option value=""></option>
                                            <?php $c1 = mysqli_query($con, "SELECT * FROM customers WHERE status='Active'") or die (mysqli_error($con));
                                            while($c2 = mysqli_fetch_array($c1))
                                            {
                                                ?>
                                           
                                            <option value="<?php echo $c2["cid"]; ?>" <?php if($c2["cid"] == $_POST['customer'] ) { echo "selected"; }  ?> ><?php echo $c2["name"]; ?></option>
                                            <?php } ?>
                                            </select>    
                                            </div>

 
  <div class="col-md-4 mb-30">
  <label for="validationDefault02">Date</label>
 <input type="text" class="form-control" name="edate" id="datepicker" value="<?php echo isset($_POST["edate"]) ? $_POST["edate"] : $today; ?>" required />  
  </div>
  </div>                               
<!-- line item -->                               
                               <div class="table-responsive">
                             <table class="table table-active table-bordered table-sm">
                             <thead class="thead-active">

                              <tr>
                             <th>Name</th>
                            <th>Description</th>
                            <th>UOM</th>    
                            <th>Price</th>
                            <th>Stock</th>
                            <th>Qty</th>  
                            </tr>
                           </thead> 
                            <tr> 
  <td><input type="text"  id="productname" name="productname" value="<?php echo isset($_POST["productname"]) ? $_POST["productname"] : ''; ?>" required ></td> 
                               <input type="hidden"  id="productcode" name="productcode" value="<?php echo isset($_POST["productcode"]) ? $_POST["productcode"] : ''; ?>"  />
                                <td><textarea id="description" name="description"><?php echo isset($_POST["description"]) ? $_POST["description"] : ''; ?></textarea></td>
                                
                           
                                <td><select name="uom" id="uom">
                               
                                <?php $su1 = mysqli_query($con, "select * from uom");  while($su2 = mysqli_fetch_array($su1)) { 
                   
                                ?>
                                <option value="<?php echo $su2["uom_name"]; ?>" <?php if($su2["uom_name"] == $_POST['uom'] ) { echo "selected"; }  ?> ><?php echo $su2["uom_name"]; ?></option>
                                
                                <?php
                                }  
                                ?>
                                </select>
                               
                               </td> 
                               
                             <td><input type="text" required id="price" name="price"   value="<?php echo isset($_POST["price"]) ? $_POST["price"] : ''; ?>" /></td>
                             
              <td><input type="text" readonly id="stock" name="stock" value="<?php echo isset($_POST["stock"]) ? $_POST["stock"] : ''; ?>" /></td>            
                    
                   <td><input type="text"  required id="quantity" name="quantity" value="<?php echo isset($_POST["quantity"]) ? $_POST["quantity"] : ''; ?>" /></td>  
                                                       
</tr>  </table> 

<!-- line item ends--->
 <div class="form-row">
<div class="col-md-4 mb-30">
 <input name="add" class="btn btn-success" type="submit" value="Add" />
</div>
</div>                                            
</form>

    form submission 

    <?php
 if(isset($_POST['add']))
 {
   
   
$customer = $_POST['customer'];
$edate1 = $_POST['edate'];
$edate = date('Y-m-d', strtotime((str_replace('/','-',$edate1))));
	                                            
$pname = $_POST['productname'];
$pcode = $_POST['productcode'];
$uom = $_POST['uom'];
$price = $_POST['price'];
$quantity = $_POST['quantity'];

$pc = mysqli_query($con, "SELECT min_price FROM items WHERE item_id=".$pcode."") or die (mysqli_error($con));
$prow = mysqli_fetch_array($pc);

   // This error part should be displayed inside <div id="error"></div> which is above the form 
if($price<$prow['min_price'])
{
echo  '<div class="alert alert-inv alert-inv-danger alert-wth-icon alert-dismissible fade show" role="alert">
                                        <span class="alert-icon-wrap"><i class="zmdi zmdi-bug"></i></span> Price should not be lesser than minimum price defined.
                                        <button type="button" class="close" data-dismiss="alert" aria-label="Close">
                                            <span aria-hidden="true">×</span>
                                        </button>
                                    </div>';   
}
else
{
  //data gets inserted into invoice table and displays submited data in table format
  // this part should be displayed below the form inside <div id="success"></div>
  
  
}
                        }


    Here i am not getting how to define that displays. 

     

     

     

    how to post only user selected values in a form

    in Javascript Help

    Posted 

    <script type="text/javascript">
  $('#addnameform').on('submit', function(e){
e.preventDefault();
    
      var data = new FormData();
      var selects = e.target.querySelectorAll(".form-control");
      var values = [];
      for (var i = 0; i < selects.length; i++) {
        if (selects[i].value != 0) {
          values.push([selects[i].name, selects[i].value])
        };       
      };
      if (values.length) {
      values.forEach(function(val) {
        data.append(val[0], val[1], val[2], val[3], val[4], val[6])
        alert(val[0]);        
      })
      var request = new XMLHttpRequest();
      request.open("POST", "/echo/js/")
      request.onload = function() {
        values = [];
        console.log(data);
                
        for(prop of[...data]) {
          console.log(prop)
        
        }
      }
      request.send(data)
            
      }
    });
</script>

    is it right?

    now am not getting that error, but nothing is the output

    how to post only user selected values in a form

    in Javascript Help

    Posted

    I have a form with 6 <select> options. All <select> filed will have same values but with different names. Like this:

    <form action="" method="post">
<select name="var1" class="form-control">
<option value="0">0</option>
<option value="10">10</option>
<option value="20">20</option>
<option value="50">50</option>
<option value="100">100</option>
</select>

<select name="var2" class="form-control">
<option value="0">0</option>
<option value="10">10</option>
<option value="20">20</option>
<option value="50">50</option>
<option value="100">100</option>
</select>
<input type="submit" name="submit" value="Submit"/>
</form>
     <?php
if(isset($_POST['submit']))
{
    include ('connect.php') ;
include('admin_auth.php');
    $var1 = $_POST['var1'];
    $var2 = $_POST['var2'];
    
     $var3= $_POST['var3'];
// till $var6
    
$var11 = (mt_rand(1,3));
$var12 = rand(4,6);
$var13 = mt_rand(1,6);

// Here i should get only those variables n values which are greater than 0
}

    I am submitting these information to the same page, But before submit is it possible to filter those variables which are greater than 0? I want to POST only those variables which has value greater than 0. How can i do it?

     

    In the same page, i want to compare these values with the 3 random numbers which will generate when submit button is clicked.

     

    I tried doing like this using like this

    <script>
  var form = document.querySelector("form");
    form.addEventListener("submit", function(e) {
      e.preventDefault();
      var data = new FormData();
      var selects = e.target.querySelectorAll(".form-control");
      var values = [];
      for (var i = 0; i < selects.length; i++) {
        // if `select` `.value` is not `0`,
        // add to `values` array`
        if (selects[i].value != 0) {
          values.push([selects[i].name, selects[i].value])
        };       
      };
      // if `values` array contains items
      // append items to `FormData` object
      if (values.length) {
      values.forEach(function(val) {
        data.append(val[0], val[1])
         alert(val[0]);
      })
      var request = new XMLHttpRequest();
      request.open("POST", "/echo/js/")
      request.onload = function() {
        values = [];
        console.log(data);
        // log values posted
        for (prop of [...data]) {
          console.log(prop)
        }
      }
      request.send(data)
    
      }
    });
</script>

    But nothing is happening, i tried to debug with Firebug, it shows

    TypeError: form is null

form.addEventListener('submit', function(evt) {

    Can somebody help me in this?

     

     

     

     

    Storing dynamically generated felds values into database

    in PHP Coding Help

    Posted

    @ginerjm:

     

    Thank you, It got resolved!

     

    I did like this

    if(isset($_POST['submit']))
{
$stk = $_POST['stockid'];

$N = COUNT($_POST['chk']) ;
for($i=0; $i<$N; $i++)
{
$color = $_POST['Color'][$i];
$size = $_POST['Size'][$i];
$cost = $_POST['Cost'][$i];
$selling_price = $_POST['Selling_price'][$i];
$opening_stock = $_POST['Opening_stock'][$i];

$sql1 = "INSERT INTO itemarticles (stk_code, color, size, cost, selling_price, opening_stock) VALUES ('".$stk."', ".$color.", ".$size.", ".$cost.", ".$selling_price.", ".$opening_stock.")"; 	
$result = DB_query($sql1,$db);

    Storing dynamically generated felds values into database

    in PHP Coding Help

    Posted

    Hi,

    I am generating set of data input elements using json and jquery, But i am not able to add the counter to it, so that i can submit them into database.

    Here is my code

    echo '<form method="post" action="' . htmlspecialchars($_SERVER['PHP_SELF'],ENT_QUOTES,'UTF-8') . '" >';
    echo '<div>';
    echo '<input type="hidden" name="FormID" value="' . $_SESSION['FormID'] . '" />';
    echo '<br />'; ?>


<p> 
                    <input type="button" value="Add Attributes" onClick="addRow('dataTable')" /> 
                    <input type="button" value="Remove Attributes" onClick="deleteRow('dataTable')"  /> 
                    <p>(All acions apply only to entries with check marked check boxes only.)</p>
                </p>
 <table id="dataTable" class="selection">
                  <tbody>
                    <tr>
                      <p>
                        <td><input type="checkbox" required="required" name="chk[]" checked="checked" /></td>

                         <td>
                            <label for="Color">Select Color</label>
                            <select id="Color" name="Color[]" required="required">
                                <?php $sql = "SELECT * FROM itemcolor";
                                $result = DB_query($sql,$db);
                                while($myrow = DB_fetch_array($result))
                                { ?>
                                <option value="<?php echo $myrow['color_id']; ?>"><?php echo $myrow['color']; ?></option>
                                <?php } ?>
                            </select>
                         </td>
                          <td>
                            <label for="Size">Select Size</label>
                            <select id="Size" name="Size[]" required="required">
                                <?php $sql = "SELECT * FROM itemsizes";
                                $result = DB_query($sql,$db);

                                while($myrow = DB_fetch_array($result))
                                { ?>
                                <option value="<?php echo $myrow['size_id']; ?>"><?php echo $myrow['size']; ?></option>
                                <?php } ?>
                            </select>
                         </td>


                        <td>
                            <label>Cost Price</label>
                            <input type="text" required="required" name="Cost[]">
                         </td>
                         <td>
                            <label for="Sale">Selling Price</label>
                            <input type="text" required="required"  name="Selling_price[]">
                         </td>
                         <input type="hidden" name="stockid" value="<?php echo $stockID; ?>" />
                          <td>
                            <label for="Stock">Opening Stock</label>
                            <input type="text" required="required"  name="Opening_stock[]">
                         </td>


                            </p>
                    </tr>
                    </tbody>
                </table>
                <div class="clear"></div>


<?php
    echo '<br /><div class="centre"><input type="submit" name="submit" value="' . _('Accept') . '" /><input type="submit" name="Cancel" value="' . _('Cancel') . '" /></div>';

    echo '</div>
          </form>';

    After submitting

    if(isset($_POST['submit']))
{
$stk = $_POST['stockid'];
foreach ($_POST['chk'] as $k) { 

$color = $_POST['Color'][$k];
$size = $_POST['Size'][$k];
$cost = $_POST['Cost'][$k];
$selling_price = $_POST['Selling_price'][$k];
$opening_stock = $_POST['Opening_stock'][$k];

$sql1 = "INSERT INTO itemarticles (stk_code, color, size, cost, selling_price, opening_stock) VALUES ('".$stk."', ".$color.", ".$size.", ".$cost.", ".$selling_price.", ".$opening_stock.")";   
$result = DB_query($sql1,$db);       
          if($result)
          {
          header("location:StockAttributes.php?Success=1");
          }
}          
 }

    But to put like ,

    foreach ($_POST['chk'] as $k)  

    <input type="text" required="required"  name="Opening_stock[$counter]">

    In script,

    function addRow(tableID) {
    var table = document.getElementById(tableID);
    var rowCount = table.rows.length;
    if(rowCount < 30){                          // limit the user from creating fields more than your limits
        var row = table.insertRow(rowCount);
        var colCount = table.rows[0].cells.length;
        for(var i=0; i<colCount; i++) {
            var newcell = row.insertCell(i);
            newcell.innerHTML = table.rows[0].cells[i].innerHTML;
        }
    }else{
         alert("Maximum Attributes per Item is 30.");

    }
}

function deleteRow(tableID) {
    var table = document.getElementById(tableID);
    var rowCount = table.rows.length;
    for(var i=0; i<rowCount; i++) {
        var row = table.rows[i];
        var chkbox = row.cells[0].childNodes[0];
        if(null != chkbox && true == chkbox.checked) {
            if(rowCount <= 1) {                         // limit the user from removing all the fields
                alert("Cannot Remove all the Attributes.");
                break;
            }
            table.deleteRow(i);
            rowCount--;
            i--;
        }
    }
}

    Can someone please guide me in doing this please

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