Outlawpd

Thanks so much for your help and time. I tried and it did not work. HEhe, I hope you don't give up on me. Any other ideas?

I added troubleshooting code as you suggested. As you can see below, the first two pics I can see the path to the file and filename. The third one however, is missing the filename, yet I can't figure out why. b/admin/client_pics/84/athena2.gif /b/admin/client_pics/82/angie1.gif /b/admin/client_pics/85/ This is my latest code: [code]<?php $result = mysql_query("SELECT clients_name, id FROM clients_info WHERE city='$city' AND $category='x'group by clients_name"); while ($row = mysql_fetch_array($result, MYSQL_NUM)) {   $filename="/data/11/0/77/86/729738/user/744719/htdocs/b/admin/client_pics/$row[1]/";   if (file_exists($filename))   {     $dir = "/data/11/0/77/86/729738/user/744719/htdocs/b/admin/client_pics/$row[1]/";     $dh  = opendir($dir);     while (false !== ($filename = readdir($dh)))     {       $files[]=$filename;     $Exten = substr($filename, -3);     if ($Exten=="jpg" || $Exten=="gif") $files[]=$filename;       //echo "filename: $filename : filetype: " . filetype($dir . $filename) . "\n";     }   $PicCount = count($files); // Count number of files found   } if ($PicCount >2)// this is how you know there are pics and not just directories   {     $PictNum = rand(2, $PicCount); // choose random picture     print "<TR><TD><img src=/phpThumb/phpThumb.php?src=/b/admin/client_pics/$row[1]/$files[$PictNum]&w=100>/b/admin/client_pics/$row[1]/$files[$PictNum]</TD></TR>";   }   else {       echo "This client has no pictures";   }   print("<TR><TD><center>"); /*    <img src=/phpThumb/phpThumb.php?src=/b/admin/client_pics/$row[1]/$files[2]&w=100></br> */     print ("<a href=view_profile.php?id=$row[1] target=frame3>$row[0]</a></br></TD></TR>"); unset($files); // Clear previous users pictures } mysql_free_result($result); ?>[/code]

Thanks a lot to everyone for their help. UNSET is what I was looking for all this time. Firemankurt, I modifed script according to your comments. It works, however, sometimes it will display one, two, or even three broken images, then again it may display all of them correctly? It might have something to do with random image selection. When I right click on one of the broken images I see the following: http://mywebsite.com/bella/admin/client_pics/84/    <-- notice missing pic info Any ideas?

Thanks. I see what you are saying, but doesn't file_exists function scan the folder for any files? If there are files then it returns TRUE, if not then FALSE. This would be a bit easier if I knew the name of the file which I could do by renaming the file on the upload. But that is whole another thing. I believe that the problem is in the loop. It does show me the first image (xxx1.jpg) but then the second and third fail because it is still looking for xxx1.jpg in other directories. I gues some kind of reset for an array, to clear it so that it pulls correct pic at the begining of each loop. Any ideas?

Good Day all, I have an issue where I can't seem to get pictures displayed properly from a particular directory when using file_exist function. First let me explain a little bit about what I am trying to do. I have users upload pictures using a form, then pictures are stored under that particular users #id folder/directory, for example: 89099887/whatever.jpg. The picture is not renamed, it keeps its original name. Now each user is categorized, so for example when clicked on Miami, it will display a list of all users who are under that category. It should display the thumbnail picture and users name right under, in that order for each user. See below: USER #1 PICTURE USER #1 NAME USER #2 PICTURE USER #2 NAME USER #3 PICTURE USER #3 NAME Here is my code: [code]<?php $result = mysql_query("SELECT clients_name, id FROM clients_info WHERE city='$city' AND $category='x'group by clients_name"); while ($row = mysql_fetch_array($result, MYSQL_NUM)) {   $filename="/data/11/0/77/86/729738/user/744719/htdocs/bella/admin/client_pics/$row[1]/";   if (file_exists($filename))   {     $dir = "/data/11/0/77/86/729738/user/744719/htdocs/bella/admin/client_pics/$row[1]/";     $dh  = opendir($dir);     while (false !== ($filename = readdir($dh)))     {       $files[]=$filename;        //echo "filename: $filename : filetype: " . filetype($dir . $filename) . "\n";     }      print "<TR><TD><img src=/bella/admin/client_pics/$row[1]/$files[2]></TD></TR>";   }   else {       echo "This client has no pictures";   }   print("<TR><TD><center>"); /*    <img src=/phpThumb/phpThumb.php?src=/bella/admin/client_pics/$row[1]/$files[2]&w=100></br> */     print ("<a href=view_profile.php?id=$row[1] target=frame3>$row[0]</a></br></TD></TR>"); } clearstatcache (); mysql_free_result($result); ?>[/code] Now the above code works partially, it displayes the very first pictures called janedoe.jpg. Then it tries to look for exact same picture in other users directory. Of course it does not find it and it returns broken image. See below: USER #1 PICTURE <- OK USER #1 NAME USER #2 PICTURE <- BROKEN IMAGE USER #2 NAME USER #3 PICTURE <- BROKEN IMAGE USER #3 NAME Any ideas? I hope you understand what I am trying to do, if you can help me I would appeciate it very much.