mantsali
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Posts
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Everything posted by mantsali
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wow thanks its working, just needed the external script. You were right
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escape all values? but thats the part that is working, here is the sample code ive been working with <!DOCTYPE HTML> <html> <head> <script> $(function () { $('#track-link').click(function () { alert('holla'); alert('This is the track: ' + $(this).data('track')); }); }); </script> </head> <body> <?php $con=mysqli_connect("localhost","root","","mnjush"); $result = mysqli_query($con,"SELECT * FROM music"); while($row = mysqli_fetch_array($result)) { echo $row['artist'] ; ?> <a id="track-link" href="<?php echo $row['trackLoc']; ?>" download="<?php echo $row['trackLoc']; ?>" data-track="<?= htmlspecialchars($row['trackLoc'], ENT_QUOTES, 'UTF-8') ?>">Download</a> <?php echo "<br>"; } mysqli_close($con); ?> </body> </html>
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this is what my link looks like <a id="track-link" href="<?php echo $row['trackLoc']; ?>" download="<?php echo $row['trackLoc']; ?>" data-track="<?= htmlspecialchars($row['trackLoc'], ENT_QUOTES, 'UTF-8') ?>">Download</a> the track does download but thats all that happens
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tried all your examples and the javascript function is never called. the issue is, i have to download the track and send the track to a different page and im retrieving the track name from a mysql database.
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Help I am trying to pass a php variable into a javasript function. Here is my code. <a href="<?php echo $row['track']; ?>" download="<?php echo $row['track']; ?>" onclick="myhit(<?php echo $row['track']; ?>)">Download</a> <script> function myhit(top){ alert(top); } </script> the javascript function is never called