Sykat
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Everything posted by Sykat
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Why File's metadata is only showing in firsf file only of a file list?
Sykat replied to Sykat's topic in PHP Coding Help
here is the file http://www40.zippyshare.com/v/6xsc3zFZ/file.html -
It is hard to explain the situation.. Better have a look at the attatchment.. run the sccript and add some mp3 file in music folder. now browse the script and you will find something like this Why the metadata only added in first file? Something Helpful: * id.php is used to extract metadata like Album, Artist etc. * Line 168-177 is the loop for mp3 file. * I on't nee to show metadata in download page. I only want to show metadata of every file on the loop.
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How can I Generate a page using jquery Dynamic form field..
Sykat replied to Sykat's topic in PHP Coding Help
<html> <head> <title> Dynamically create input fields- jQuery </title> <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.min.js"></script> <script type="text/javascript"> $(function() { var addDiv = $('#addinput'); var i = $('#addinput p').size() + 1; $('#addNew').live('click', function() { $('<p><input type="text" id="p_new" size="40" name="p_new_[' + i +']" value="" placeholder="I am New" /><input type="text" id="p_new2" size="40" name="p_new_2[' + i +']" value="" placeholder="I am New 2" /><a href="#" id="remNew">Remove</a> </p>').appendTo(addDiv); i++; return false; }); $('#remNew').live('click', function() { if( i > 2 ) { $(this).parents('p').remove(); i--; } return false; }); }); </script> </head> <body> <h2>Dynammically Add Another Input Box</h2> <form action="gen.php" method="post"> <div id="addinput"> <p> <input type="text" id="p_new_[1]" size="40" name="p_new" value="" placeholder="Input Value" /><input type="text" id="p_new2" size="40" name="p_new_2[1]" value="" placeholder="Input Value" /><a href="#" id="addNew">Add</a> </p> </div> <input type="submit" /> </form> </body> </html> SO you mean this? It makes p_new_[1], p_new_2[1]; p_new_[2], p_new_2[2];... But <?php foreach($_POST['p_new_'] as $k => $v){ $cleanv = strip_tags($v);//its a users input so I wouldn't trust it as is - use some form of checking here echo ''. $k - $cleanv .''; } ?> this is not working... output:
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I am trying to create a dynamic form using Jquery but don't know how to post those data using $_POST. The page <html> <head> <title> Dynamically create input fields- jQuery </title> <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.min.js"></script> <script type="text/javascript"> $(function() { var addDiv = $('#addinput'); var i = $('#addinput p').size() + 1; $('#addNew').live('click', function() { $('<p><input type="text" id="p_new" size="40" name="p_new_' + i +'" value="" placeholder="I am New" /><input type="text" id="p_new2" size="40" name="p_new_2' + i +'" value="" placeholder="I am New 2" /><a href="#" id="remNew">Remove</a> </p>').appendTo(addDiv); i++; return false; }); $('#remNew').live('click', function() { if( i > 2 ) { $(this).parents('p').remove(); i--; } return false; }); }); </script> </head> <body> <h2>Dynammically Add Another Input Box</h2> <form action="gen.php" method="post"> <div id="addinput"> <p> <input type="text" id="p_new" size="40" name="p_new" value="" placeholder="Input Value" /><input type="text" id="p_new2" size="40" name="p_new2" value="" placeholder="Input Value" /><a href="#" id="addNew">Add</a> </p> </div> </form> </body> </html> Here is live example.. A Pen by Captain Anonymous Whatever, The new fields got an unique name="" value as p_new_1, p_new_21 for first new field, p_new_2, p_new_22 for second new field ...... ...... Now, I know I can display inserted data using <?php echo $_POST["p_new_1"]; ?> and similar way like this... But as a growing field, this form can have unlimited input field. How can I display all of those data in the page gen.php? It must be something like this example: <html> <body> <div class="header">Generated content<div> <p><a href="inserted data of first field of default row">inserted data of second field of default row</a></p> <p><a href="inserted data of first field of first new row">inserted data of second field of first new row</a></p> <p><a href="inserted data of first field of 2nd new row">inserted data of second field of 2nd new row</a></p> <p><a href="inserted data of first field of 3rd new row">inserted data of second field of 3rd new row</a></p> <p><a href="inserted data of first field of 4th new row">inserted data of second field of 4th new row</a></p> And list go on according to submitted form.... </div></body></html> I actually lake of knowledge of PHP and no idea about array or something named loop. Can someone do it for me? What I have to do in gen.php?
