prohybe

Are you still refering to the 1st question? In the findNumber? Because the program for it is still not working. I'm going to try and fix the function then!

@cronix i changed the $found thing! @ginerjm i'm sorry but i'm not totally getting the error checking. I pasted ur signature just like ini_set('display_erros'... are we supposed to take the " ' " off? anyway i did already check without it

I will do that, thank you. Just one last thing, I'm back to the original code and moved return False; outside the loop. So should this give me some output on the browser? Because I am not getting any. (I commented the whole 2nd question) <h1>Class number 3 </h1> <h2>Arrays</h2> <h3>1. Determine whether or not your number is contained within an array.</h3> <?php function findNumber($arr, $num) { $size = count($arr); $i = 0; while ($i < $size) { if ($arr[$i] == $num) { return TRUE; } else { i++; } } return FALSE; } $arr = array(3, 8, 5, 1, 6, 7); $num = 6; if (findNumber($arr, $num)) { echo "Value $num belongs to the array.<br/>"; } else { echo "Value $num does not belong to the array.<br/>"; } ?> /* <h3>2. Determine the average of an array.</h3> <?php function avgArr($arr) { $size = count($arr); $sum = 0; for ($i = 0; $i < $size; $i++) { $sum = $sum + $arr[$i]; } return $avg = $sum / $size; } $myArray = array(1, 2, 3, 4, 5); echo "The average of your array is: " . avgArr($myArr); ?> */

Thank you both for your help! It currently is like this (not working still): <h1>Class number 3 </h1> <h2>Arrays</h2> <h3>1. Determine whether or not your number is contained within an array.</h3> <?php error_reporting(E_ALL); ini_set('display_errors', '1'); function findNumber($arr, $num) { $size = count($arr); $i = 0; $found = false; while ($i < $size) { if ($arr[$i] == $num) { $found = true; } else { i++; } } return $found; } $arr = array(3, 8, 5, 1, 6, 7); $num = 6; findNumber($arr); if ($found == true) { echo "Value $num belongs to the array.<br/>"; } else { echo "Value $num does not belong to the array.<br/>"; } ?> <h3>2. Determine the average of an array.</h3> <?php error_reporting(E_ALL); ini_set('display_errors', '1'); function avgArr($arr) { $size = count($arr); $sum = 0; for ($i = 0; $i < $size; $i++) { $sum = $sum + $arr[$i]; } return $avg = $sum / $size; } $myArray = array(1, 2, 3, 4, 5); echo "The average of your array is: " . avgArr($myArr); ?>

So sorry, understood it the wrong way! I pasted your error checking code under the "<?php" line of code and refreshed the browser but nothing happened. About the while loop and don't really know if it has anything to do with the position of the "i++".

Not going to argue.

Thank you! It works with that function, but in this stage i wanted to know what I have got wrong just to learn how to type the code!

We get 30 minute lectures with some code on a PowerPoint just presenting the variables and loops. No examples, nothing. I had try again and again for this. Just coded this myself and i did in fact look for the correct usage of the while loop. And no, i did not hear about the error checking until just now.

We're supposed to learn with searches and stuff. I did my code alone, just can't find the mistake. I don't know what's wrong. I tried previewing it on a browser but nothing appears.

Hello! I just started learning php at school and I tried to complete our first assignment but couldn't make it. The professor wasn't very helpful too. So this consists of two questions. I can't get any of them to work. Tried commenting both but none of them seem to work. I could really use some help! <h1>Class number 3 </h1> <h2>Arrays</h2> <h3>1. Determine whether or not your number is contained within an array.</h3> <?php function findNumber($arr, $num) { $size = count($arr); $i = 0; while ($i < $size) { if ($arr[$i] == $num) { return TRUE; } else { i++; } return FALSE; } } $arr = array(3, 8, 5, 1, 6, 7); $num = 6; if (findNumber($arr, $num)) { echo "Value $num belongs to the array.<br/>"; } else { echo "Value $num does not belong to the array.<br/>"; } ?> <h3>2. Determine the average of an array.</h3> <?php function avgArr($arr) { $size = count($arr); $sum = 0; for ($i = 0; $i < $size; $i++) { $sum = $sum + $arr[$i]; } return $avg = $sum / $size; } $myArray = array(1, 2, 3, 4, 5); echo "The average of your array is: " . avgArr($myArr); ?>