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azra

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About azra

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  1. 1. HTML FORM #for user to enter the data <html> <title>reg</title> <style type="text/css"> body { background-color: rgb(200,200,200); color: white; padding: 20px; font-family: Arial, Verdana, sans-serif;} h4 { background-color: DarkCyan; padding: inherit;} h3 { background-color: #ee3e80; padding: inherit;} p { background-color: white; color: rgb(100,100,90); padding: inherit;} </style> <form method="POST" action="login_back.php" enctype="multipart/form-data"></br> &nbsp<font color="DarkCyan"> Choose a user name:</font> <input type="text" name="username"> </br></br> &nbsp<font color="DarkCyan"> First name:</font> <input type="text" name="firstname"/> </br></br> &nbsp<font color="DarkCyan"> Last name:</font><input type="text" name="lastname"/> </br></br> &nbsp<font color="DarkCyan"> File: <input type="file" name="image"></font> </br></br> <input type="submit" value="Save and Proceed"> </form> </html> ---------- 2 STORING IN DATABASE #backend processing to store and retrieve data from db <?php #echo "<body style='background-color:rgb(200,200,200)'>"; session_start(); if( isset($_POST['username']) && isset($_FILES['image']) ) { $_SESSION['username']=$_POST['username']; $_SESSION['firstname']=$_POST['firstname']; $lastname=$_POST['lastname']; $file=$_FILES['image']['tmp_name']; $image_size=getimagesize($_FILES['image']['tmp_name']); if(!isset($file)) echo"please select an image"; else { $image_name=$_FILES['image']['name']; //grabing image name $image_size=getimagesize($_FILES['image']['tmp_name']); //getting image size } echo "</br>"; #connection to db mysql_connect("localhost","root","")or die(mysql_error()); mysql_select_db("wordgraphic")or die(mysql_error()); #checking the available username $query = mysql_query("SELECT * FROM userdata WHERE username = '" . $_SESSION['username'] . "'" ); $ans=mysql_num_rows($query); if ($ans > 0) { echo "Username already in use please try another."; } else if($image_size==FALSE) { echo"That's not an image."; } else { #Insert data into mysql #1.Inserting user name & image into db $sql="INSERT INTO userdata(username, firstname, lastname, image)VALUES('" . $_SESSION['username'] . "', '" . $_SESSION['firstname'] . "', '$lastname','$image')"; $result1=mysql_query($sql); if($result1) { echo "</br>"; echo "Registration successful"; echo "</br>"; //displaying image $lastid=mysql_insert_id();//get the id of the last record echo "uploaded image is :"; echo "<img src='get.php?id=".$lastid."'>"; > this command has some mistake }#if insertion into db successful else { echo "Problem in database operation"; } }# else block of unique username n img }#end of isset ?> ---------- 3. GET.PHP #additional file that retrieve image from database <?php #connection to db mysql_connect("localhost","root","")or die(mysql_error()); mysql_select_db("wordgraphic")or die(mysql_error()); if(isset($_REQUEST['id']) ) > this block of code is not runninng { $mid=(int)($_REQUEST['id']); $image=mysql_query("SELECT * FROM userdata WHERE id=$mid") or die("Invalid query: " . mysql_error()); $image=mysql_fetch_assoc($image); $image=$image['image']; header("Content-type: image/jpeg"); echo $image; } else { echo"error"; } ?>
  2. 1.m new on online discussing i will try n repost sorry fr d inconvenience caused. 2.i know the command has some mistake because user name, image first name, last name are getting stored in db seamlessly but when m trying to display image from database i am facing prob and in the third segment of code isset() segment is not running hence, data is not getting transfered between pages . 3. else has only one statement under it i.e. echo so skipping {} will do as with most other languages. 4. turned on error reporting. thank you
  3. 1. HTML FORM #for user to enter the data <html> <title>reg</title> <style type="text/css"> body { background-color: rgb(200,200,200); color: white; padding: 20px; font-family: Arial, Verdana, sans-serif;} h4 { background-color: DarkCyan; padding: inherit;} h3 { background-color: #ee3e80; padding: inherit;} p { background-color: white; color: rgb(100,100,90); padding: inherit;} </style> <form method="POST" action="login_back.php" enctype="multipart/form-data"></br> &nbsp<font color="DarkCyan"> Choose a user name:</font> <input type="text" name="username"> </br></br> &nbsp<font color="DarkCyan"> First name:</font> <input type="text" name="firstname"/> </br></br> &nbsp<font color="DarkCyan"> Last name:</font><input type="text" name="lastname"/> </br></br> &nbsp<font color="DarkCyan"> File: <input type="file" name="image"></font> </br></br> <input type="submit" value="Save and Proceed"> </form> </html> ---------- 2 STORING IN DATABASE #backend processing to store and retrieve data from db <?php error_reporting(0); #echo "<body style='background-color:rgb(200,200,200)'>"; session_start(); #if( isset($_POST['username']) && isset($_FILES['image']) ) #{ $_SESSION['username']=$_POST['username']; $_SESSION['firstname']=$_POST['firstname']; $lastname=$_POST['lastname']; $file=$_FILES['image']['tmp_name']; $image_size=getimagesize($_FILES['image']['tmp_name']); if(!isset($file)) echo"please select an image"; else { #$image=$_FILES['image']['tmp_image']; //grabing the file content $image_name=$_FILES['image']['name']; //grabing image name $image_size=getimagesize($_FILES['image']['tmp_name']); //getting image size } echo "</br>"; #connection to db mysql_connect("localhost","root","")or die(mysql_error()); mysql_select_db("wordgraphic")or die(mysql_error()); #checking the available username $query = mysql_query("SELECT * FROM userdata WHERE username = '" . $_SESSION['username'] . "'" ); $ans=mysql_num_rows($query); if ($ans > 0) { echo "Username already in use please try another."; } else if($image_size==FALSE) { echo"That's not an image."; } else { #Insert data into mysql #1.Inserting user name & image into db $sql="INSERT INTO userdata(username, firstname, lastname, image)VALUES('" . $_SESSION['username'] . "', '" . $_SESSION['firstname'] . "', '$lastname','$image')"; $result1=mysql_query($sql); if($result1) { echo "</br>"; echo "Registration successful"; echo "</br>"; //displaying image $lastid=mysql_insert_id();//get the id of the last record echo "uploaded image is :"; echo "<img src='get.php?id=".$lastid."'>"; > this command has some mistake }#if insertion into db successful else { echo "Problem in database operation"; } }# else block of unique username n img }#end of isset ?> ---------- 3. GET.PHP #additional file that retrieve image from database <?php #connection to db mysql_connect("localhost","root","")or die(mysql_error()); mysql_select_db("wordgraphic")or die(mysql_error()); if(isset($_REQUEST['id']) ) > this block of code is not running { $mid=(int)($_REQUEST['id']); $image=mysql_query("SELECT * FROM userdata WHERE id=$mid") or die("Invalid query: " . mysql_error()); $image=mysql_fetch_assoc($image); $image=$image['image']; header("Content-type: image/jpeg"); echo $image; } else echo"error"; ?>
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