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ruben0123

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  1. I found it, after the hint from Dale, I replaced the code with: if (!(isset($errors))) { and now it workls like a charm. Topic can be closed.
  2. Thanks dale, you are right, there was a descrepancy between local and remote code. Remote code had the line if isset(!$errors) { in it on line 20 because I was trying to get rid of an other error message being: Notice: Undefined variable: errors in /public/sites/www.studiovsf.nl/contact.php on line 20 And as far as I understood that should be fixed by using the isset(xxxxx) method. For the record, I'm a software programmer, but I'm not really into PHP, that's just for my hobby website. :-) Any thoughts on the above issue? Thank in advance. Ruben
  3. Hi all, I hope someone can pinpoint hte problem for me because I have stared myself blind and can't find it. I get the following error: Parse error: syntax error, unexpected 'isset' (T_ISSET), expecting '(' in /public/sites/www.studiovsf.nl/contact.php on line 20 So I know that somewhere around linw 20 < if (!$errors) { > there is a '(' missing in the code. but how much I try I cant find where it needs to go. The code is listed under here. Any help would be greatly appreciated. <?php //Retrieve form data. //GET - user submitted data using AJAX //POST - in case user does not support javascript, well use POST instead $name = ($_GET['name']) ? $_GET['name'] : $_POST['name']; $email = ($_GET['email']) ?$_GET['email'] : $_POST['email']; $comment = ($_GET['comment']) ?$_GET['comment'] : $_POST['comment']; //flag to indicate which method it uses. If POST set it to 1 if ($_POST) $post=1; //Simple server side validation for POST data, of course, you should validate the email if (!$name) $errors[count($errors)] = 'Please enter your name.'; if (!$email) $errors[count($errors)] = 'Please enter your email.'; if (!$comment) $errors[count($errors)] = 'Please enter your comment.'; //if the errors array is empty, send the mail if (!$errors) { //recipient - replace your email here $to = 'info@studiovsf.nl'; //sender - from the form $from = $name . ' <' . $email . '>'; //subject and the html message $subject = 'Message from ' . $name; $message = 'Name: ' . $name . '<br/><br/> Email: ' . $email . '<br/><br/> Message: ' . nl2br($comment) . '<br/>'; //send the mail $result = sendmail($to, $subject, $message, $from); //if POST was used, display the message straight away if ($_POST) { if ($result) echo 'Dank u wel! We hebben uw bericht ontvangen.'; else echo 'Sorry, er ging iets fout. Probeer het later nog eens.'; //else if GET was used, return the boolean value so that //ajax script can react accordingly //1 means success, 0 means failed } else { echo $result; } //if the errors array has values } else { //display the errors message for ($i=0; $i<count($errors); $i++) echo $errors[$i] . '<br/>'; echo '<a href="contact.html">Back</a>'; exit; } //Simple mail function with HTML header function sendmail($to, $subject, $message, $from) { $headers = "MIME-Version: 1.0" . "\r\n"; $headers .= "Content-type:text/html;charset=iso-8859-1" . "\r\n"; $headers .= 'From: ' . $from . "\r\n"; $result = mail($to,$subject,$message,$headers); if ($result) return 1; else return 0; } ?>
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