BlueM

I understand the security risks but the script is somewhat protected. That kind of data can not be stored in the database

This is the original output for the php code [ {"id":"1","name":"Rae Sremmurd"}, {"id":"2","name":"Tyga"}, {"id":"3","name":"Luke Christopher"}, {"id":"4","name":"Tink"}, {"id":"5","name":"Lil Herb"}, {"id":"6","name":"Lil Durk"}, {"id":"7","name":"Mac Miller"}, {"id":"8","name":"Kidd Kidd"}, {"id":"9","name":"Sage The Gemini"}, {"id":"10","name":"Blac Youngsta"}, {"id":"11","name":"John River"}, {"id":"12","name":"Migos"}, {"id":"13","name":"Danny Seth"}, {"id":"14","name":"Soulja Boy"}, {"id":"15","name":"Dave East"}, {"id":"16","name":"King Los"}, {"id":"17","name":"Wiz Khalifa"}, {"id":"18","name":"Lil Bibby"}, ]

not sure if I am using it right but now its escaping all the special characters but i need them in order to have the script run correctly.

Thanks for your input benanamen but i'm looking for a solution for the while loop not a solution for connecting to and pulling the data from the database. The script works without the last comma being echoed out.

I have a php script that generates a javascript code. [ <?php $conn=@mysql_connect("localhost","root",""); $select=mysql_select_db("dripp",$conn); $lalala=mysql_query("SELECT * FROM typo"); while ($display=mysql_fetch_assoc($lalala)){ $one='{"id":"'; $display['id']; $two='","name":"'; $display['name']; $three='"},'; echo $all=$one.$display['id'].$two.$display['name'].$three; ?> <?php } ?> ] The problem with this code is that it in the output the final comma is messing with the script. I've searched everywhere for a solution but I can not find a way to remove the last comma without removing them all. Please help

Hey guys, I am looking for someone who can design an audio player that can also play a playlist for a website. The player I am looking for needs certain details. 1) Needs to hide src of file 2) Needs to have controls including attractive progress bar 3) Needs to read from mysql database. I am a bit of a programmer myself so I will be tweaking it but the skeleton must be there. Obviously willing to pay for your time please contact back.

Hey guys this is pretty simple i guess but i need some help. I am trying to output both information from the arrays but without doing the loop twice. this is my output: applefruit appleveggie appletree carrotfruit carrotveggie carrottree pinefruit pineveggie pinetree but I would like to have an output like : applefruit carrotveggie pinetree here is my code <?php $first="apple,carrot,pine"; $second="fruit,veggie,tree"; $array1=explode(",", $first); $array2=explode(",", $second); foreach($array1 as $number1) { foreach($array2 as $number2) { echo $number1.$number2."</br>"; }} ?>

I got it to work with an update query instead. I should be doing that because I need to append to the data that is already there. Thanks for the printf tip

When I run ip_add($user_ip); this is the output.... THE QUERY IS 'INSERT INTO media(ip) VALUES ('::1') WHERE id=51' im so lost, I dont know why it wont run

$user_ip =$_SERVER['REMOTE_ADDR']; ip_add($user_ip); and $realid is a number that corresponds to the id collum in my table $url=$_SERVER['REQUEST_URI']; $realid=trim(strstr($url, '.'),'.'); and yeah i clicked on the link but i still dont understand... if (!mysqli_query($query_run, "SET ip=1")) { printf("Errormessage: %s\n", mysqli_error($query_run)); } that gives me a bunch of errors.

$i is just supposed to be a placeholder for when i actually run the function and $realid is a value taken from the url. I'm not quite sure how i would be able to use the mysqli_error() function. I'm a newb :s

Hey guys, I have been trying to figure out what is wrong with my unique hit counter on my site. With a lot of trouble shooting i have figured out that the function to add the ip to the table is not working. Can anyone help me out? function ip_add($i){ global $con; global $realid; $query_run=mysqli_query($con,"INSERT INTO media(ip) VALUES ('$i') WHERE id=".$realid); }

It's the space!!!! I've been stuck on this for days!! I changed RewriteRule .* -[L] to RewriteRule .* - [L] and it works fine. Thanks for your help. I've struggling so hard and i lost my password for my other account so i had to create a new one. Worth it. Thanks again

I should clarify, with the .htaccess file and parse.php, everything works but I can not see the images. I does not give me a 403 but instead the image path gives me this

Ok I've removed it. The .htaccess looks like this now Options -Indexes RewriteEngine On RewriteCond %{REQUEST_FILENAME} -f [OR] RewriteCond %{REQUEST_FILENAME} -d RewriteRule .* -[L] RewriteRule ^(.*)$ parse.php And yeah the files exist in the path. If i remove the .htaccess file and the parse.php file the images appear. But with the files in place it does not display. If i try and access the file path in the browser it gives me this error.