samowns

May 13, 2022

Ok bro i create telegram bot and i want to response to connect or response the bot through php ..please find the solution

May 12, 2022

sir any solution?

May 12, 2022

use mysqli

//your  must include your database file

$q="SELECT * FROM table_name  ";
$ok=mysqli_query($con,$q);

while($raq=mysqli_fetch_array($ok)){


<td><?php echo  $raq[0];?></td>//Here u want to echo any row
<?php }?>//Loop Close here

May 12, 2022

Hello member's please check my code i set weebhook aleady but bot didnt respond

<?php
$input= file_get_contents('php://input');
$update= json_decode($input);
$message=$update->message;
$chat_id=$message->chat->id;
$text=$message->text;
$token='key';
 file_get_contents("https://api.telegram.org/bot$token/sendMessage?chat_id=$chat_id&text=$text");










?>

May 4, 2022

24 minutes ago, Barand said:

The only condition you have for not inserting is if the reason has an error.

You should prevent insertion if there are any errors.

i figure out Thanx

elseif (!$_POST["name"] or ["name"] == '0' ){

$sq1=mysqli_query($a,$sq);
   echo "Not Please Select Name Please";


}

May 4, 2022

Please Tell me how am new to php

May 4, 2022

Hello Guys My code runs fine but value null is inserting if some one dint select any list name . So wot i want if some one did not select any option query did not run $error shows

Here is my code please check and figure it out

<?php
	$error="";
	
include "db.php";
if(isset($_POST['bt'])){

$date=Date("Y-m-d H:i:s");

$b=$_POST['name'];
$res=$_POST['res'];


if(!$_POST["res"]){

 }

if(!$_POST["name"]){

 }


 // Declare variable

    if(!$_POST["name"]  or ["name"] == '' ) {
        $error .= "Must select the name.<br />";// If not selected, add string to error message
   


     }
if(!$_POST["res"]  ){
        $error .= "Must Enter the Reason.<br />"; // If not Enter, add string to error message
       
 
     }
     
     else{
        
        $sq="insert into att(name,date,res)values('$b','$date','$res')";
$sq1=mysqli_query($a,$sq);
	echo "Ok";         // 
     }
}



?>

<!DOCTYPE html>
<html>
<head>
	<meta charset="utf-8">
	<meta http-equiv="X-UA-Compatible" content="IE=edge">
	<title></title>
	<link rel="stylesheet" href="">
</head>
<body>
	<form action="pres.php" method="post" accept-charset="utf-8">
		 <select name="name" >
    <option value="" >Choose...</option>
    <option value="mandeep" >Maneep</option>
    <option value="sahiba" >Sahiba</option>
</select>

    
  </select>
	<input type="text" name="res">
	
	
	<input type="submit" name="bt" value="Ok">

<br>
<?php echo"". $error;?>
		</form>
</body>
</html>

User Bann Script · April 30, 2022

	 i want to embed Bann Script or user deactive or active 
	<?php
session_start();
$message="";
?>
	<?php
include "db.php";
$msg='';
if(isset($_POST['sb']))
{
	  $time=time()-30;
  $ip_address=getIpAddr();
	$name = mysqli_real_escape_string($a, $_POST['eml']);
$pass = mysqli_real_escape_string($a, $_POST['pass']);
	
$query=mysqli_query($a,"select count(*) as total_count from loginlogs where TryTime > $time and IpAddress='$ip_address'");
 $check_login_row=mysqli_fetch_assoc($query);
  $total_count=$check_login_row['total_count'];
  //Checking if the attempt 3, or youcan set the no of attempt her. For now we taking only 3 fail attempted
  if($total_count==3){
    $msg="To many failed login attempts. Please login after 30 sec";
  }else{
    //Getting Post Values
   
	$result=mysqli_query($a,"SELECT * FROM admin WHERE eml='$name' and pass= '$pass'");
	$row  = mysqli_fetch_assoc($result);
$row=mysqli_num_rows($result);
//ban user
if($row==1)
{
  $_SESSION['user_name'] =$name;
  header("location:wel.php?msg=Scuessfull eml");
mysqli_query($a,"delete from loginlogs where IpAddress='$ip_address'");
}
	     
	
           else{
      $total_count++;
      $rem_attm=4-$total_count;
      if($rem_attm==0){
        $msg="To many failed login attempts. Please login after 40 sec";
      }else{
        $msg="<b>Please enter valid login details.<br/>$rem_attm attempts remaining <b>";
      }
	      $try_time=time();
      mysqli_query($a,"insert into loginlogs(IpAddress,TryTime) values('$ip_address','$try_time')");
      
    }
}}
if(isset($_SESSION['user_name']) ){
  header("location:wel.php?msg=Scuessfull ");
?>
	<?php
}
	
?>
	
<form  class="login-form" action="adminscure.php" method="post" >
<div class="message"><?php if($message!="") { echo $message; } ?></div>
<body id="LoginForm">
<div class="container">
	
<div class="main-div">
 <div class="panel">
 
   <h2>Admin Login</h2>
   
   <p>Please enter your email and passwords</p>
   </div>
    <form id="Login">
<div class="form-group">
	
            <input type="name"  name="eml" class="form-control"  id="eml"  placeholder="name">
	        </div>
	        <div class="form-group">
	            <input type="password" name="pass" class="form-control" id="pass" placeholder="Password">
            
	        </div>
        <div>
<input type="submit" name="sb" class="btn btn-primary">
 <div id="result"><?php echo $msg?></div>
	</div>
</form>
<?php
	function getIpAddr(){
    if (!empty($_SERVER['HTTP_CLIENT_IP'])){
       $ipAddr=$_SERVER['HTTP_CLIENT_IP'];
    }elseif (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])){
       $ipAddr=$_SERVER['HTTP_X_FORWARDED_FOR'];
    }else{
       $ipAddr=$_SERVER['REMOTE_ADDR'];
    }
   return $ipAddr;
}?>

December 8, 2019

I want to know that if i login as admin wel.php open

and if i want to login as mod so mod.php open

programs runs fine but when i login as admin or mod same session work i want different page scure

December 8, 2019

<!DOCTYPE html>
<html>
<head>
	<style type="text/css" media="screen">
		.ss
		{
			border-width: 1px;
			border-style:solid;
			width: 100px;
			height: 100px;

	</style>
	<meta charset="utf-8">
	<meta http-equiv="X-UA-Compatible" content="IE=edge">
	<title></title>
	<link rel="stylesheet" href="">
</head>
<body>
	<form action="index.php" method="post">

	<table align="center" class="ss">
		<tr>
			<td>Name<input type="text" name="name">
</td>
		</tr>
		
		<tr>
			<td>Pass&nbsp:<input type="password" name="pass">

</td>
		</tr>
		<tr>
			<td>Email<input type="text" name="eml">
</td>
<tr>
			<td><input type="submit" name="sb">
</td>
	</table>
	
		

	</form>
	
</body>
</html>
<?php 
include "db.php";
session_start();
if(isset($_POST['sb']))
{
	
	$name=mysqli_real_escape_string($con, $_POST['eml']);
	$pass=mysqli_real_escape_string($con, $_POST['pass']);
	$usr=mysqli_real_escape_string($con,'user');
    
	$std='std';
	$type='admin';
	$qer="select * from users where eml='$name' AND pass='$pass' AND type='$type'";
	$sql=mysqli_query($con,$qer);

	$qer=" select * from users where eml='$name' AND pass='$pass' AND type='$std'";
	$sql1=mysqli_query($con,$qer);

	$qer=" select * from users where eml='$name' AND pass='$pass' AND type='$usr'";
	$sql3=mysqli_query($con,$qer);


	$fe=mysqli_fetch_array($sql);
	if(is_array($fe)) {
		$name=$name;
		$pass=$pass;

        {

	
	header("location:wel.php?msg=Scuessfull login");

	
}
echo "Admin of this site";

}

else if($fe=mysqli_fetch_array($sql1)){

	if(is_array($fe)) 
	
		$name=$name;
		$pass=$pass;
echo "Moderator of the site";
{ 
	
	
	header("location:mod.php?msg=Scuessfull login");

	
}

}

else if($fe=mysqli_fetch_array($sql3)){

	if(is_array($fe)) 
		$name=$name;
		$pass=$pass;
			$_SESSION['eml'] =true;
			header("location:sim.php?msg=Scuessfull login");
echo "Simple user this site";
}



else
{
	echo "invalid pass";
   }
       }
?>

March 16, 2017

Hello guys am using mysql . login admin panel works fine .but when i use password=1' or '1' = '1 its also working some one please help me i want to safe admin panel here is my code

if(isset($_POST['sb']))
{

$result = mysql_query("SELECT * FROM admin WHERE eml='" . $_POST["eml"] . "' and pass= '". $_POST["pass"]."'");
$row  = mysql_fetch_array($result);
if(is_array($row)) {
$_SESSION["eml"] = $row['eml'];
hash($_SESSION["pass"] = $row['pass'];

} else {
$message = "<font color='#FF0000'>"."Invalid Username or Password!"."</font>";
}
}
if(isset($_SESSION["eml"])) {
header("Location:./useradmin.php");
}

November 13, 2015

ok

November 13, 2015

query runs f9 but sir instead of 1 n 0. i want if 1 fees pending .if 0 no fees pending

November 13, 2015

here is loginact.php

i just want if user login see the profile restriction means if admin login they can change ..i think i need to put one field 'type' admin or user..plz somone figure out..am new to sql this code is running

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
 <link href="css/style.css" rel="stylesheet">
<head>
<style>
.red
{ color:#F00;
font-size:15px;
}


</style>

<?php include "header.php";?>
<?php

include ("db.php");
$error="";
?>


<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head><?php session_start();


?>

<?php
if(isset($_POST['sb']))
{

$a=$_POST ['eml'];
$b=$_POST['pass'];

$c="select * from users where eml='$a' && pass='$b'";
$s=mysql_query ($c);
$row=mysql_num_rows($s);


if($row==1    )
{
    $_SESSION['eml']=$a;

    header("location:fetch.php?msg=Scuessfull login");
    
}
else{

    $error= "Invalid Email or  Password *";
}

    



}



?>
</head>

<body><?php
if(isset($_GET['logout']))
{
       session_unregister('eml');
}




?>
<h3>Admin Login </h3>

<div class="usr">

<form action="loginact.php" method="post" required="required">
<div class="col-lg-6"><div class="input-group">
Email id<input type="text" class="form-control" name="eml"  required="required"/>
<br />
<div  class="red"><?php if($error!="") { echo $error; } ?></div>
Password<input type="password" class="form-control" name="pass" required="required"/><br />

<input style="width:100px;" class="btn-success k"  type="submit" name="sb" value="Login"/>
</form>
</div>

</body>

</html>

November 13, 2015

if you r using skype so logout skype n hide then ur server ill show green light .i was having same problem

November 12, 2015

sir fees based on monthly charges....

November 12, 2015

tnx bro i can implement ur code <3

November 12, 2015

i got ur point sir...wot should i do ..u i need one table more? name fees history...plz help i got your point sir..

November 12, 2015

sir i use tigger for updating fees...i jus want in my admiin area to flash those users with there pending fees. suposse id 1 simran..join date 7-10-2015

after 7-11-205 auto reminder in admin area 'id 1 simran fees is pending'

November 12, 2015

hello guyz am newbie in mysql php..i want if any user register. in my admin area there is reminder of fees .like id 1 simran join date 7-10-2015 after 30 days in my admin area reminds simran's fees is pending..any one plz help me ...thnxx in advance

here is table name users

November 5, 2015

Hello guyz am new here .. i love php am biginner in php so i find this forum

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samowns

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