funsutton

Hey, here is a separate string, similar to the other, however it has no F or C to denote the actual temperatures. How hard would it be to modify your preg_replace to only change the ones that are temps...and not the ones that are actual dates and times? mpdData['HMhour'].hour['0']=new mpdHMHrObj(new Date('2008','7','31','0','0','0'),'11','Few Showers','74','74','30','69','87','From S 2 mph'); The trick is, in this section "'Few Showers','74','74','30','69','87','From S 2 mph'", only the 74,74,69 are temps, and the others are percents.

I actually didn't see the difference, so I switched it out. Thanks man.

Yeah, it does work. I didn't realize that 86 was 30.....so, but cool. Then I actually accomplished something myself. Well, with the code you gave me.

I might be wrong....it might actually be working, and my testing be wrong.

Actually, I do think this works....but it's converting all of the numbers. I want it to only convert the one's with an s, not an F or C. $string = preg_replace('/\b(\d+)(s){1}\b/ei', "floor($1 * .1) * 10 . (($2 == 's') ? 's' : '')", $string);

Well, I was trying to use your code to do something a little different. I decided to make the phrase "Tomorrow's high will be in the 36s" to "Tomorrow's high will be in the 30s" So, my query looked like this: $unit = "m"; $string = "mpdData['narr'].day['1']=new mpdNDObj(new Date('2008','7','30'),'1','A few isolated thunderstorms developing during the afternoon. High 86F. Winds light and variable. Chance of rain 30%.','Tomorrow hights will be in the 90s'');"; if ($unit == "m") { $string = preg_replace('/\b(-?\d+)([a-z]){1}\b/ei', "round(($1 - 32) / 1. . (($2 == 's') ? 's' : (($2 == 'F') ? 'C' : ''))", $string); $string = preg_replace('/\b(-?\d+)(s){1}\b/ei', "floor($1 * .1) * 10 . ($2 == 's') ? 's'", $string); echo $string; } else { echo $string; } But, it's failing. Basically I am trying to round down to the nearest 10, the ones that have an "s" beside them, so that it makes more sense.

That worked, tested it on a fake string. Thanks!

DarkWater, I was wondering, what happens if there is a negative F value denoted with a - sign?

Hey man, that's awesome. Very clear now. Check your pm in a minute.

So do you mind explaining it if it's not too much trouble?

Wow, that works like a champ. Converts every singe one of them. Again, thanks.

If you would, that'd be awesome. In the actual string I am using, it's more complicated in that it has brackets [], single quotes '....in fact, here's an example of the actual string. mpdData['narr'].day['1']=new mpdNDObj(new Date('2008','7','30'),'1','A few isolated thunderstorms developing during the afternoon. High 86F. Winds light and variable. Chance of rain 30%.','Tomorrow'); mpdData['narr'].day['2']=new mpdNDObj(new Date('2008','7','30'),'1','Isolated thunderstorms in the evening. Fair skies overnight. Low 67F. Winds light and variable. Chance of rain 30%.','Tomorrow night'); mpdData['narr'].day['3']=new mpdNDObj(new Date('2008','7','31'),'2','Times of sun and clouds. Highs in the low 80s and lows in the mid 60s.','Sunday'); Not sure if this changes anything....but I have a feeling it will. So far I haven't gotten any output....

wow man....you make that look really easy. I would have never come up with that...at least like that. now to figure out what you did Thanks!

I am having trouble with putting this together in my head. Instead of explaining outright, I'm just going to give it to you by example. $string = "Today the high is 72F and the low is 36F. Tomorrow will be in the 60s." I want to convert each number there to Celsius based on an indicator from the url. I need to extract each number, convert each number, and replace each number back in the string. I figure it's going to have extract into an array, and it will require regex to find the different numbers and account for the F and s when searching. I can handle the actual conversion to Celsius, however I am not sure how to extract and replace the numbers.