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About Revolutsio

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  • Birthday 10/15/1969

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  1. Sorry Barand the second reply wasn't for you Thank you for your code the second one works for me
  2. The code did work my question was how do I put the results in a table
  3. Sorry for the late reply I have tried the code and I get an error in line 3 Call to undefined function pdoConnect() Here is my loggin code called 'dbh.php' <?php $dbServername = "localhost"; $dbUsername = "root"; $dbPassword = ""; $dbName = "csv_db"; $conn = mysqli_connect($dbServername, $dbUsername, $dbPassword, $dbName); ?>
  4. I have copied this from a youtube video, I have a good grasp of html. I want a search my database and be able to edit the details on my webpage so I went looking for help and found this code that did search my database and print the results to the screen and this worked. but when I tried to add my css file and other bits from my site i get errors.
  5. I have now got a search engine to work, but it only show in normal text, could someone help me get into a table, I have a CSS file but cannot get the search page to print in my table. <div id="main"> <table> <thead> <tr> <th>ID</td> <th>GAME</td> <th>PLATFORM</td> </tr> <thead> <?php $output = NULL; if(isset($_POST['submit'])) { //Connect to database $mysqli = NEW MySQLi ("localhost","root","","***.**"); $search = $mysqli->real_escape_string($_POST{'search'}); //Query the database $resultSet = $mysqli->query("SELECT * FROM games WHERE GAME LIKE '$search%'"); if($resultSet->num_rows >0){ while($rows = $resultSet->fetch_assoc()) { $id = $rows['ID']; $gn = $rows['GAME']; $pf = $rows['PLATFORM']; $od = $rows['Owned'];?> } <tr> <td><?php $output .= $id; ?></tr>; <!-- Game: $gn<br /> Platform: $pf<br /> Owned: $od<br /><br />";--> <form method="POST"> <input type="TEXT" name="search" /> <input type="SUBMIT" name="submit" value="Search" /> </form> </table> </body> </html> Also how can i use my connect file instead of having the connect to database in this file?
  6. Thank you all the replys. What should i do to make a search, edit and insert form to my database
  7. Thank you for your reply this is not my code I found this on youtube I put this as an example of what i tried to do to get a search field on my screen
  8. Could somebody help me with a little problem I am having, I havew spent the last two weeks trying different ways to search my database without success. What I want to do is have an input field that I can search only one column of my database. (it is a game collection) for example I want to search the game 'Medal of Honor' i type this in the search field and click submit button and it should find all the entries with that name in the database. I have tried a few online tutorials and nothing works. here is some code that i tried. <?php $host = "localhost"; $user = "root"; $password =""; $database = "csv_db"; $id = ""; $game = ""; $year = ""; $platform = ""; mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT); // connect to mysql database try{ $connect = mysqli_connect($host, $user, $password, $database); } catch (mysqli_sql_exception $ex) { echo 'Error'; } // get values from the form function getPosts() { $posts = array(); $posts[0] = $_POST['id']; $posts[1] = $_POST['game']; $posts[2] = $_POST['year']; $posts[3] = $_POST['platform']; return $posts; } // Search if(isset($_POST['search'])) { $data = getPosts(); $search_Query = "SELECT * FROM games WHERE id = $data[0]"; $search_Result = mysqli_query($connect, $search_Query); if($search_Result) { if(mysqli_num_rows($search_Result)) { while($row = mysqli_fetch_array($search_Result)) { $id = $row['ID']; $game = $row['GAME']; $year = $row['YR']; $platform = $row['PLATFORM']; } }else{ echo 'No Data For This Id'; } }else{ echo 'Result Error'; } } // Insert if(isset($_POST['insert'])) { $data = getPosts(); $insert_Query = "INSERT INTO `games`(`Game`, `YR`, `PLATFORM`) VALUES ('$data[1]','$data[2]',$data[3])"; try{ $insert_Result = mysqli_query($connect, $insert_Query); if($insert_Result) { if(mysqli_affected_rows($connect) > 0) { echo 'Data Inserted'; }else{ echo 'Data Not Inserted'; } } } catch (Exception $ex) { echo 'Error Insert '.$ex->getMessage(); } } // Delete if(isset($_POST['delete'])) { $data = getPosts(); $delete_Query = "DELETE FROM `games` WHERE `ID` = $data[0]"; try{ $delete_Result = mysqli_query($connect, $delete_Query); if($delete_Result) { if(mysqli_affected_rows($connect) > 0) { echo 'Data Deleted'; }else{ echo 'Data Not Deleted'; } } } catch (Exception $ex) { echo 'Error Delete '.$ex->getMessage(); } } // Edit if(isset($_POST['update'])) { $data = getPosts(); $update_Query = "UPDATE `games` SET `GAMES`='$data[1]',`YR`='$data[2]',`PLATFORM`=$data[3] WHERE `ID` = $data[0]"; try{ $update_Result = mysqli_query($connect, $update_Query); if($update_Result) { if(mysqli_affected_rows($connect) > 0) { echo 'Data Updated'; }else{ echo 'Data Not Updated'; } } } catch (Exception $ex) { echo 'Error Update '.$ex->getMessage(); } } ?> <!DOCTYPE Html> <html> <head> <title>PHP INSERT UPDATE DELETE SEARCH</title> </head> <body> <form action="php_insert_update_delete_search.php" method="post"> <input type="number" name="id" placeholder="ID" value="<?php echo $id;?>"><br><br> <input type="text" name="game" placeholder="Game" value="<?php echo $game;?>"><br><br> <input type="text" name="year" placeholder="Year" value="<?php echo $year;?>"><br><br> <input type="number" name="platform" placeholder="Platform" value="<?php echo $platform;?>"><br><br> <div> <!-- Input For Add Values To Database--> <input type="submit" name="insert" value="Add"> <!-- Input For Edit Values --> <input type="submit" name="update" value="Update"> <!-- Input For Clear Values --> <input type="submit" name="delete" value="Delete"> <!-- Input For Find Values With The given ID --> <input type="submit" name="search" value="Find"> </div> </form> </body> </html> and here is the error i get. Fatal error: Uncaught mysqli_sql_exception: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '' at line 1 in H:\xampp\htdocs\php_insert_update_delete_search.php:41 Stack trace: #0 H:\xampp\htdocs\php_insert_update_delete_search.php(41): mysqli_query(Object(mysqli), 'SELECT * FROM g...') #1 {main} thrown in H:\xampp\htdocs\php_insert_update_delete_search.php on line 41 can anybody help me do I search engine for my database
  9. That worked, now it is printing the date like this '13 03, 2008' is there a way to get the date of completed games date in this format '13 March 2018' please And thank you for all you help.
  10. could tell me why i should put this bit of code please
  11. Hi I cannot upload anything but a pictures or videos
  12. what file extension would you like?
  13. with the code i put in i get the 30 November -0001 i tried to use phpmyadmin to use the select command from your reply and i get all blank when echo finished
  14. $date = $row['FINISHED']; IF($date == '0000-00-00') { $date=''; } else { $parts = explode('-',$date); $date = date('d-m-Y', mktime(0,0,0,$parts[1],$parts[2],$parts[0])); } I have tried this code and i get 30 November -0001
  15. Thank you i will try this. Now with the date query, when i show the page with items that have not been completed i get the date '0000-00-00' how do i change this , i searched on here and found the same problem but it did not work with my code. How do i make this date blank if 'FINISHED' = '0000-00-00' if (FINISHED='0000-00-00', '', FINISHED) as FINISHED i have tried this but get '01 January 1970' and if I put a space in the second quotes I get today's date , a little bit confused
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