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About Revolutsio

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  • Birthday 10/15/1969

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    Manchester, UK
  1. <?php include('dbh.php'); ?> <?php $sql= "SELECT * FROM games WHERE completed=1 ORDER BY Game_Name;"; $result = mysqli_query($conn, $sql) or die("Bad Query: $sql"); while ($row = mysqli_fetch_assoc($result)):?> <?php $output = ''; for ($i=1; $i<=28; $i++) { $output .= $row['Game_Name']; $i; } ?> <?php endwhile; ?> <!DOCTYPE html> <html lang="en" dir="ltr"> <head> <meta charset="utf-8"> <link rel="stylesheet" type="text/css" href="https://unpkg.com/purecss@1.0.1/build/base-min.css"> <link rel="stylesheet" type="text/css" href="table.css"> <title>My Collection</title> </head> <body> <h1 align:center>#</h1> <div class="grid"> <?= $output ?> </div> </body> </html> As you can see I have added the database entries, but only get the last entry in the database printed horizontal with no spaces, is this correct for a start?
  2. Yes that is what I want This is the way i would like to do it how would i put in the select query into the code?
  3. <table> <thead> <tr> <th>Game</th> <th>Date Finished</th> </tr> </thead> <?php $sql= "SELECT * FROM games WHERE completed=1 ORDER BY Game_Name;"; $result = mysqli_query($conn, $sql) or die("Bad Query: $sql"); $num_rows = mysqli_num_rows($result);?> <?php $counter = 1; while ($row = mysqli_fetch_assoc($result)): ?> <tr> <!-- <td style="text-align:center"><?php echo $row['ID']; ?></td> --> <td style="text-align:center"><?php echo $row['Game_Name']; ?></td> <!-- <td style="text-align:center"><?php echo date ('d F Y', strtotime($row['Date_Finished'])); ?></td> --> <?php $counter++;?> </tr> <?php endwhile; ?> </body> </table> </html>
  4. At the moment the field are displaying downwards and I want to display horizontal
  5. I am currently displaying in a table and no css also there will be 5 across and 28 in total
  6. I want my mysql database to be displayed across the screen similar to the below Entry 1 Entry 2 Entry 3 Entry 4 Entry 5 eventually with a image above the name, but for now just as above. How would I go about this?
  7. Once again @Barand you come to me rescue thanks again
  8. $num1 = (5); $num2 = (2); $num3 = (1); $num4 = (3); echo "<br />"; if ($num1 = 5 echo $names[4]); i have tried this but get an error unexpedted echo
  9. I have five names in an array and also numbers 5,2,1,3 and what i want to do is php to look at the numbers and print out the name that corresponds to the number. so for my example the name it should echo out is 'Lee' $names = array ("Stan", "John", "Dean", "Sam", "Lee"); here are the five names. The idea is to learn php with making a little fixture list with these five names. The problem i have is to make php read the number and then look up the array for the name that corresponds to the number. I hope this explains what I would like to do?
  10. Sorry Barand the second reply wasn't for you Thank you for your code the second one works for me
  11. The code did work my question was how do I put the results in a table
  12. Sorry for the late reply I have tried the code and I get an error in line 3 Call to undefined function pdoConnect() Here is my loggin code called 'dbh.php' <?php $dbServername = "localhost"; $dbUsername = "root"; $dbPassword = ""; $dbName = "csv_db"; $conn = mysqli_connect($dbServername, $dbUsername, $dbPassword, $dbName); ?>
  13. I have copied this from a youtube video, I have a good grasp of html. I want a search my database and be able to edit the details on my webpage so I went looking for help and found this code that did search my database and print the results to the screen and this worked. but when I tried to add my css file and other bits from my site i get errors.
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