Wal-Wal-2
-
Posts
6 -
Joined
-
Last visited
Posts posted by Wal-Wal-2
-
-
ginerjm - Thank you. I am not sure why the {}'s are around the array ( {$row['link']} ) code. I am really interested in learning. If you can, and it is appropriate here, can you explain it to me? I am new to the forum so not sure what the protocol is. Thanks again.
-
requinix - I have been working on this for a couple of days. I have researched and tried many many options to no avail. I just saw Barand's latest post with an updated corrected code. Thank you for following up.
I tried Barand's code and it worked great. I never thought about putting it in the code there.
-
Barand - I know the syntax of the standard <a> tag but I have not been able to figure out how to include it in the echo "<a href='".$row[link]."'>♦ ".$row[title]."</a><br>"; code. Maybe you know how to do that?
-
I have researched the subject and found a few 'solutions' for my problem but cannot get it to work (I looked at ones in this forum).
I have php while loop that uses variables for db values and wrapped inside <a></a> tags that work as desired. What I want to have the link open in a new tab.
Here is the code I am working with:
<?php //loop to collect and output db data as hyperlink with target="_blank" while($row = mysqli_fetch_assoc($result)) { //output data from each row echo "<a href='".$row[link]."'>♦ ".$row[title]."</a><br>"; } ?>
-
I have an array of data in which I want to display in a table with the first row of data to not be formatted. In the second row of data, I want it formatted with the CSS class of "success". When I run this code, I do not get any formatting of any rows in the table. I have tried various different options without success. Any help would be greatly appreciated.
<?php
$counter = 0;
while($row = mysql_fetch_array($query)) {
if($counter % 2 == 0) {
//output data from each row of data with no class of "success"
echo "<tr class='text-left'>";
if (empty($row[endDate])) {
echo "<td>".$row[startDate]."</td>"; /* only one date */
} else {
echo "<td>".$row[startDate].'-'.$row[endDate]."</td>"; /*date range */
}
echo "<td>".$row[rideName]."</td>";
echo "<td>".$row[rideDesc]."</td>";
echo "<td>".$row[location]."</td>";
echo "<td><a href='".$row[link]."'>".$row[source]."</a></th>";
echo "</tr>";
$counter++;
} else {
//output data from each row
echo "<tr class='text-left success'>";
if (empty($row[endDate])) {
echo "<td>".$row[startDate]."</td>";
} else {
echo "<td>".$row[startDate].'-'.$row[endDate]."</td>";
}
echo "<td>".$row[rideName]."</td>";
echo "<td>".$row[rideDesc]."</td>";
echo "<td>".$row[location]."</td>";
echo "<td><a href='".$row[link]."'>".$row[source]."</a></th>";
echo "</tr>";
$counter++;
} /* end if else */
} /* end while */
?>
Audio files controls not working on android and iPhones
in PHP Coding Help
Posted
I have php code that uses mp3 audio files stored in a database for the user to listen to. The page loads and the audio controls work and the files play on a desktop and laptop just fine. When trying to play a file on an android or IPhone, when you press the play (or any other control) nothing happens. It acts like the page is static. There is a home button on the webpage and it works so I know the page is interactive. Below is the code. I would appreciate any help. Thank you.
<?php
$sermons = $database->select("sermon","*");;
foreach( $sermons as $sermon )
{
$audio_file = 'http://xxxxxxx.com/sermons/'.$sermon['file_name'];
$player = "<audio id='sermon_'$sermon[id] controls>
<source src='$audio_file' type='audio/mpeg'>
<source src='$audio_file' type='audio/mp3'>
Your browser does not support the audio element.
</audio>";
echo "<tr>
<td>$sermon[sermon_date]</td>
<td>$sermon[title]</td>
<td>$sermon[speaker]</td>
<td>$player</td>
</tr>";
}
?>