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slotegraafd last won the day on June 4

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  1. // Form Fields Arrays: Field Title, Field Name, Field Type $display_form = array( array( "type" => "text", "name" => "first_name", "value" => "", "label" => "First Name" ), array( "type" => "text", "name" => "last_name", "value" => "", "label" => "Last Name" ), array( "type" => "email", "name" => "email", "value" => "", "label" => "Email" ), array( "type" => "number", "name" => "extension", "value" => "", "label" => "Extension" ), ); foreach ($display_form as $key =
  2. Oh so I’m using the array that I have in my code there. (I’m really bad with arrays if you couldn’t tell) I thought that each one in the array corresponded to a number no matter what type of arrays
  3. @benanamen Ah I see, Notice: Undefined offset: 2 in C:\XAMPP\htdocs\Webd3201\salesperson.php on line 83 though do you know what this error means?
  4. Hey, So I'm doing a school assignment and my professor wants us to use an array to display forms and I have no idea how to do that. He wants us to create an array of arrays like this: display_form( array( "type" => "text", "name" => "first_name", "value" => "", "label" => "First Name" ), array( "type" => "text", "name" => "last_name", "value" => "", "label" => "Last Name" ), array( "type" => "email", "name" => "email", "value" => "", "label" => "Email" ), array( "type" => "number", "name" => "ex
  5. because i am trying to get it from the database my issue however is what do I do once i get that information
  6. I know the answer is to check if the input is the right combination but I'm asking how you do that
  7. I dont' know what to try because I was certain this was the right code which it obviously isnt, I retrieved it from the data as in the code in the if statement but it doesnt check to see if the input is the right combination that is why I am asking for help because I do not know what to do with this
  8. I'm required to use pgadmin, this is an assignment for school, all I am focusing on right now is trying to get it to login
  9. Hello, I am once again desperately asking for your help, I am working on a simple login page and I am having trouble actually getting it to login. I display error messages for if the user doesn't enter anything but I can't seem to get it to work for if the credentials are wrong. It logs the user in whether the information is right or not and i dont even know what to do now This is the code any suggestions would be greatly appreciated <?php /* Name: Deanna Slotegraaf Course Code: WEBD3201 Date: 2020-09-22 */ $file = "sign-in.php"; $date = "
  10. HI, Sorry the question title is really bad. But I'm currently making a simple php login page for school(well it should be simple anyway) and I'm having trouble getting the user to actually login. So Everything else on my page works fine. I have the login form and then I have error messages that displays an error if the user didnt enter any information or if the information is incorrect. So when I try to login with information from the database that should let me login and take me to the dashboard page it still says it is incorrect. Now at the top of my page I am getting an error that says: syn
  11. lol yes I did I already fixed it,
  12. Oh well, I am currently using MYSQL im not even using phpmyadmin and i wouldnt know how to use the pdo you suggested im more familiar with mysql
  13. Didn't you say you werent going to help me?
  14. It only has one row of data I entered a test one just to well test. cuz its only supposed to be checking for one because I don't want users with duplicate usernames
  15. First things first dont friggen attack me okay? I am NEW TO PROGRAMMING i know nothing! Hense the reason why the program that I am creating is so stupid and doesnt work and all the other insults you gave me. I wasnt against the idea of using the error reporting because I did and IT SHOWED ME NOTHING. I was simply asking for other suggestions. So if you arent gonna be helpful then leave me the hell alone. And yes I do have a lot of damn attitude.
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