Timmyhavoc

HI there I have the following array: $x[$y][] = array('a' => $a, 'b' => 'b', 'c' => $c); And i would like to print all the results for $c so they read something like: $c[0] = 'toaster' $c[1] = 'baked potato' $c[2] = 'tuesday' (This way i can convert the values to flash varialbes later on) Ive looked at all the basic Array tutorials but have found nothing that matches what Im looking for. Please help!

Amazing! that certainly got rid of those warnings. thanks! what seems obvious to you can slip past my eyes so easily. As for versions Its pretty hard for me to keep up, php is only one of the things i do at work. I generally have to source old scripts ive used in the past to save time. One other thing which is probably also related to PHP versions, my .htaccess isnt working anymore and its needed to redirect all the include files. It looks like this: [code]php_value include_path ".;\"my_server_directory"\htdocs\ebshop\;\"my_server_directory"\htdocs\ebshop\library\; \"my_server_directory"\htdocs\ebshop\include\"[/code] Am i using old code again or am i getting the syntax wrong?

Hi I recently upgraded our site to PHP version 3.4 and now alot of my scripts arent working and i get this notorious and dredded error message: Notice: Only variable references should be returned by reference in /homepages/20/d158757983/htdocs/ebshop/library/database.php on line 9 Notice: Only variable references should be returned by reference in /homepages/20/d158757983/htdocs/ebshop/library/database.php on line 25 I know this is to do with changing versions but im not the most PHP skilled person so can't see where the errors are, can someone shed some light? The code producing the error reads like this: [code]1 - <?php 2 - require_once 'config.php'; 3 - 4 - $dbConn = mysql_connect ($dbHost, $dbUser, $dbPass) or die ('MySQL connect failed. ' . mysql_error()); 5 - mysql_select_db($dbName) or die('Cannot select database. ' . mysql_error()); 6 - 7 - function &dbQuery($sql) 8 - { 9 -    return mysql_query($sql); 10 - } ... 23 - function &dbFetchAssoc($result) 24 - { 25 -     return mysql_fetch_assoc($result); 26 - }[/code] Id appreciate any help!