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Everything posted by chriscloyd
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i get this error Parse error: parse error, unexpected T_VARIABLE in C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\includes\porfolio_getfunctions.php on line 3 [CODE] <?php class getproject { var $id = $_GET['project']; //project name function name() { if ($result = mysql_query("SELECT `title` FROM projects WHERE id = '{$this->id}'")) { if (mysql_num_rows($result) > 0) { $row = mysql_fetch_assoc($result); return $row['name']; } } } } ?> [/CODE]
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so if i do it the way u show i can call it up like this [CODE] <?php $project = new getproject(); echo $project->p_name(); ?> [/CODE]
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ya but how do u do the things like $project = new getproject i have looked for tutorials but cant find any
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how about u try $_SESSION['member'] or $_SESSION['nonmember']
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would this be how to start a class if im trying to get an id from a url say if my url is index.php?project=3 <=== that 3 is the id how do i echo the class to get the $p_name [code] <?php class getproject { var $id = $_GET['project']; function p_name { $get_name = mysql_query("SELECT * FROM projects WHERE id = '$id'") or die(mysql_error()); $p = mysql_fetch_assoc($get_name); $p_name = $p['name']; } } ?> [/code]
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my function is not displaying anything okay heres my function [code] <?php function get_project($i) { $get_project = mysql_query("SELECT * FROM projects WHERE id = '$i'") or die(mysql_error()); $p = mysql_fetch_assoc($get_project) or die(mysql_error()); $p_name = $p['title']; $p_type = $p['type']; $p_startdate = $p['startdate']; return $p_type; return $p_name; return $p_startdate; if ($p['status'] != 'Completed') { $p_status = 'In Progress'; return $p_status; } else { $p_status = 'Completed'; $p_enddate = $p['enddate']; return $p_status; return $p_enddate; } } ?> [/code] heres my code calling the function [code] <?php session_start(); include("config.php"); include("includes/porfolio_getfunctions.php"); if (isset($_GET['project'])){ $id = $_GET['project']; get_project($id); echo $p_name; echo $p_type; } ?> [/code]
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no sorting at all
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Im trying to make a link where people can order their mysql query from heres my links [code] <a href="?sort=id">ID</a> <a href="?sort=first, last">Name</a> <a href="?sort=position">Position</a> <a href="?sort=email">Email</a> <a href="?sort=level">Level</a> - <a href="?type=ASC">ASC</a> <a href="?type=DESC">DESC</a> [/code] heres my code [code] <?php if ($_GET['sort']) { $sort = $_GET['sort']; } else { $sort = 'id'; } if ($_GET['type']) { $type = $_GET['type']; } else { $type = 'ASC'; } $get_all_staff = mysql_query("SELECT * FROM users WHERE level IN('admin','support','sales','staff') ORDER BY '$sort' '$type'"); ?> [/code]
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how do i make like a percent bar say if we have 33 task to do on a project and we have 21 done how could i go about making a bar show that its 63% complete i have the whole rest of the project management script done im just having trouble with makeing the image
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see i have that and it works fine but the problem im getting is saving all of them in one variable so i can add it to the database
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yes but when i go to enter it into a database will it have them all under the variable value
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i just dont see how i can get each of the selctions into one variable
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yes i know that im not missing the point i understand that now im trying to do the foreach loop [code] <?php if(isset($_POST['test'])){ $a = $_POST['test[]']; foreach ($a) { $services .= $a.'<br />'; } } ?> [/code]
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no its printitng out three i choose its shoing the Array ( [test] => Array ( [0] => 1 [1] => 4 [2] => 5 ) [Submit] => Submit ) that on my tes form but i want it to show the info like this 1 4 5
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how do i make it print so its not like this Array ( [test] => 6 [Submit] => Submit ) but like this Web Design Logo Design
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i tried that and i got this Array ( [test] => 6 [Submit] => Submit ) so how do i make it so it saves all of the things from the array in one var so i can save it into the database
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thats not the problem curtis its the services field how would i access it like an array
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heres my problem when i retrive the form with my php script its not showing multiple services from the services field so if i select more than one its not working it will only show the top one how do i fix it ? heres my form [code] <form id="form1" name="form1" method="post" action="includes/send_quote.php"> <table width="253" border="0" cellspacing="5" cellpadding="0"> <tr> <td valign="middle"><div align="right" class="style17">First Name</div></td> <td><div align="center" class="style17">*</div></td> <td><input name="FirstName" type="text" class="input2" id="FirstName" /></td> </tr> <tr> <td valign="middle"><div align="right" class="style17">Last Name </div></td> <td><div align="center" class="style17">*</div></td> <td><input name="LastName" type="text" class="input2" id="LastName" /></td> </tr> <tr> <td valign="middle"><div align="right" class="style17">Phone # </div></td> <td><div align="center" class="style17">*</div></td> <td><input name="PhoneNumber" type="text" class="input2" id="PhoneNumber" /></td> </tr> <tr> <td valign="middle"><div align="right" class="style17">Email</div></td> <td><div align="center" class="style17">*</div></td> <td><input name="EmailAddress" type="text" class="input2" id="EmailAddress" /></td> </tr> <tr> <td valign="middle"><div align="right" class="style17">Budget </div></td> <td><div align="center"><span class="style8"><span class="style8"><span class="style11"><span class="style19"></span></span></span></span></div></td> <td><span class="style17"> <label> <select name="budget" id="budget"> <option value="< $100">< $100</option> <option value="$100 - $200" selected>$100 - $200</option> <option value="$200 - $300">$200 - $300</option> <option value="$300 - $400">$300 - $400</option> <option value="$400 - $500">$400 - $500</option> <option value="$500 - $600">$500 - $600</option> <option value="$600 - $700">$600 - $700</option> <option value="$700 - $800">$700 - $800</option> <option value="$800 - $900">$800 - $900</option> <option value="$800 - $900">$800 - $900</option> <option value="$1000 - $2000">$1000 - $2000</option> <option value="$2000 - $3000">$2000 - $3000</option> <option value="$3000+">$3000+</option> </select> </label> </span></td> </tr> <tr> <td valign="middle"><div align="right" class="style17">URL</div></td> <td><div align="center"><span class="style8"><span class="style8"><span class="style11"><span class="style19"></span></span></span></span></div></td> <td><input name="url" type="text" class="input2" id="url" /></td> </tr> <tr> <td width="60" rowspan="2" valign="top"><div align="right" class="style17">Service</div> <span class="style17">Use Ctrl to select more than one</span></td> <td valign="top"><div align="center"><span class="style8"><span class="style8"><span class="style11"><span class="style19"></span></span></span></span></div></td> <td width="164" rowspan="2" valign="top"><span class="style17"> <select name="services" size="4" multiple="multiple" id="services"> <option value="Web Desgin">Web Desgin</option> <option value="Logo/Branding Design">Logo/Branding Design</option> <option value="Web Development">Web Development</option> <option value="Other">Other</option> </select> </span></td> </tr> <tr> <td valign="top"><div align="center"><span class="style8"><span class="style8"><span class="style11"><span class="style19"></span></span></span></span></div></td> </tr> <tr> <td valign="middle"><div align="right" class="style17">If Other </div></td> <td><div align="center"><span class="style8"><span class="style8"><span class="style11"><span class="style19"></span></span></span></span></div></td> <td><input name="other2" type="text" class="input2" id="other2" /></td> </tr> <tr> <td valign="middle"><div align="right" class="style17">Description</div></td> <td> </td> <td> </td> </tr> <tr> <td colspan="3"><div align="center" class="style17"> <textarea name="description" cols="25" rows="5" class="style21" id="description"></textarea> </div></td> </tr> <tr> <td><div align="right" class="style17">Refered By </div></td> <td> </td> <td><span class="style17"> <select name="refered"> <option value="">Select One</option> <?php $sales = mysql_query("select * from users where level in ('sales','admin') order by first, last asc"); while ($s = mysql_fetch_assoc($sales)) { echo '<option value="'.$s['id'].'">'.$s['first'].' '.$s['last'].'</option>'; } ?> </select> </span> </td> </tr> <tr> <td width="60"><input name="date" type="hidden" value="<?php echo date("n/j/Y g:i:s A"); ?>" /></td> <td width="9"><div align="center"><span class="style8"><span class="style8"><span class="style11"><span class="style19"></span></span></span></span></div></td> <td width="164"><span class="style17"> <label> <input name="Submit" type="submit" class="input" onClick="MM_validateForm('FirstName','','R','LastName','','R','PhoneNumber','','RisNum','EmailAddress','','RisEmail');return document.MM_returnValue" value="Get Quote" /> </label> </span></td> </tr> </table> </form> [/code]
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im trying to change the file permissions using chmod so i can unlink a file but how do i go ahead and do that this is the error i have with my code [code] <?php mysql_connect('localhost','www5965_chris','chriscloyd'); mysql_select_db('www5965_chris'); $id = $_GET['id']; $query = mysql_query("SELECT name, type, size, path FROM upload2 WHERE id = '$id'"); while($test = mysql_fetch_array($query)) { $ftp_user_name = 'www5965@christophercloyd.com'; $ftp_user_pass = '596511'; $ftp_root = '/'; $ftp_server = 'localhost'; $conn_id = ftp_connect($ftp_server); $login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass); chmod("upload_test/".$test['name'],0777); unlink("upload_test/".$test['name']); } ?> [/code] this is the error im getting Warning: chmod() [function.chmod]: No such file or directory in /usr/home/www/public_html/delete.php on line 13 Warning: unlink(upload_test/steam.exe) [function.unlink]: No such file or directory in /usr/home/www/public_html/delete.php on line 14
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this is my create mail class [code] <?php class cpmail{ var $cpuser; var $cppass; var $cpdomain; var $cpskin; function cpmail($cpuser,$cppass,$cpdomain,$cpskin='x'){ $this->cpuser=$cpuser; $this->cppass=$cppass; $this->cpdomain=$cpdomain; $this->cpskin=$cpskin; } function create($euser,$epass,$equota){ $path="http://".$this->cpuser.":".$this->cppass."@".$this->cpdomain.":2082/frontend/".$this->cpskin."/mail/doaddpop.html?quota=".$equota."&email=".$euser."&domain=".$this->cpdomain."&password=".$epass; $f = fopen($path,"r"); if (!$f) { return('Cannot create email account. Possible reasons: "fopen" function not allowed on your server, PHP is running in SAFE mode'); } while (!feof ($f)) { $line = fgets ($f, 1024); if (ereg ("already exists!", $line, $out)) { return('Such email account already exists.'); } } fclose($f); return "Email account created."; } } ?> [/code] im getting this error Warning: fopen(http://...@srxstudios.com:2082/frontend/X v2.6.0/mail/doaddpop.html?quota=20&email=******&domain=******&password=******) [function.fopen]: failed to open stream: HTTP request failed! HTTP/1.0 404 Not Found in /home/srxstud/public_html/test22/admin/cpmail_class.php on line 15 Cannot create email account. Possible reasons: "fopen" function not allowed on your server, PHP is running in SAFE mode heres my code that calls it [code] <?php include('cpmail_class.php'); $cpanel = new cpmail("*****","*******","*****","X v2.6.0"); echo cpanel->create($_POST['email'],$_POST['password'],"20"); ?> [/code] how could i take safe mode off if i dont ahve access to the php.ini
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would this work if i want to get three different types of rows from one column $get_staff = mysql_query("SELECT * FROM users WHERE level = ('admin','staff','sales')")
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Quick Question - DB not accessible from on server?
chriscloyd replied to Solarpitch's topic in PHP Coding Help
oh my bad i did not read the first part -
Quick Question - DB not accessible from on server?
chriscloyd replied to Solarpitch's topic in PHP Coding Help
[CODE] <?php $result = mysql_query($mysql_connect, $query) or die (mysqli_error($mysql_connect)); ?> [/CODE] or try this [CODE] <?php $result = mysql_query($query, $mysql_connect) or die (mysqli_error($mysql_connect)); ?> [/CODE] in ur original one u had an i after mysqli -
Quick Question - DB not accessible from on server?
chriscloyd replied to Solarpitch's topic in PHP Coding Help
$result = mysqli_query($query, $mysql_connect) or die (mysqli_error($mysql_connect));