blazing_bruce
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Everything posted by blazing_bruce
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@ProjectFear, I really thank you for your time & kind advices to improve my site. I have fixed that white popup on shared hosting listing pages. The price slider is being fixed. Again, Thanks a lot. Thank you my friend
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Hi., I am really glad to introduce my new hosting comparison & hosting search engine http://servergrabber.com to PHPFreaks Community. I am eagerly waiting for your reviews.
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Give url + try to use CDN if needed or move to cloud if it is related to "huge traffic". But before that, Give us an url
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footer area's contact us & other 2 links are not working.. Write something related to your website on <title>Tag it helps for SEO.
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Well yes too much <h1> is not a good. I am just trying to get contents inbetween tags.. I tried the following for <td> </td> . preg_match_all('/<td [^>]*>((?:<td.+?<\/td|.)*?)<\/td>/si', $sometable, $matches); It worked like charm
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Hello, I am learning regularexperssion. it is pretty awesome. Is it possible to make a pattern in preg_match_all to grab content of 6th or 7th h1 tag's text <h1 styles.. or any other attributes *>text</h1> <h1 styles.. or any other attributes *>text</h1> <h1 styles.. or any other attributes *>text</h1> <h1 styles.. or any other attributes *>text</h1> <h1 styles.. or any other attributes *>text</h1> The main objective here is.. I am trying to find a text of Nth occurance of <h1 and </h1> I was trying to use preg_match_all .. But unable to get it. Any help would be much appreciated . Im sorry if it is a silly question
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getting combinations of array index or elements
blazing_bruce replied to blazing_bruce's topic in PHP Coding Help
i writtened an algorithm for it myself :) $checked[0] = 1; $checked[1] = 3; $checked[2] = 4; $checked[3] = 6; $checked[4] = 7; if you want to get all posiblities of array elements (with out repeating) like this 0 1 2 4 0 1 2 3 0 1 3 4 0 2 3 4 1 2 3 4 PHP code follows [code]for($n=0;$n<=$total_checked;$n++) { unset($new); $j=0; //echo("N=$n<br>"); $value = $total_checked-$n; //echo("value = $value<br>"); for($b=0;$b<$total_checked;$b++) { if($b==$value) { // echo("Entered condition"); $notaccepted = $checked[$b]; continue; } $new[$j]=$checked[$b]; echo($j); //Change here if you want that combination of array values echo("$new[$j]"); $j++; } if($n==0) { continue; } // print_r($new); echo("<BR>"); } [/code] Thank you, Karthi keyan -
getting combinations of array index or elements
blazing_bruce replied to blazing_bruce's topic in PHP Coding Help
if you know the outline of an algorithm, then you are welcome. please help me. -
Hello all, i have an array named $checked; $checked[0] = 1; $checked[1] = 3; $checked[2] = 4; $checked[3] = 6; $checked[4] = 7; i want to make combinations like array index 0 1 2 3 means $checked[0]; $checked[1]; $checked[2]; $checked[3]; 0 1 2 4 0 1 3 4 0 2 3 4 1 2 3 4 . . . . like this manner. it should find all the possible combinations. here i said the sizeof array is five. but it may be 7 , 8 or 3 . if the size of array is 'n' then i want combinations in size of 'n-1' . is it possible? please help me. Thank you,
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**SOLVED** mysql table searching. harder a bit.
blazing_bruce replied to blazing_bruce's topic in PHP Coding Help
Thank you Mr.Barand. your query is working now. -
hello all, i have a table named rest RID CID 1 | 2 1 | 3 1 | 4 2 | 2 2 | 3 3 | 2 3 | 4 4 | 2 4 | 3 i want to list records which accepts the cards (CID). first i have 4 check boxes in search.php for($i=1;$i<=$total_cards;$i++) { $fetch = mysql_fetch_row($pass_cards); $id=$fetch[0]; $name = $fetch[1]; echo("<input type='checkbox' name='card[]' value='$id' />$name"); } in list.php i want to show the list of records based on check box's value getting post values by $checked = $HTTP_POST_VARS['card']; now i want to list all the records which having all the CID values. if i checking the check box 2 and 3 (which is CID) then list.php will show 1,2,4 (RID) i have tried in many ways, but no use. this is wil be a simple MySQL query. please help me.
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hello, now we are using $_POST['id']; like this . i want to use $_POST['$id']; help me. i want to place a php variable inside of $_POST[] please help me. Thank you, Karthi keyan.
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first try to check is it set on your system. try to use if(isset($_COOKIE['policyusername'])) or empty($_COOKIE['policyusername']) . try to check with junk data it is $username = "try this data"; and setcookie(policyusername, $username); and then chck it. if it shows "try this data" in browser then there is a problem in query or empty data returend by mysql. Try all the things i told Thank you, Karthikeyan.
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i think cookies are not setting in your pc. make sure that your browser allows to set cookies Thank you, Karthi keyan.
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[!--quoteo(post=356919:date=Mar 21 2006, 05:39 PM:name=gk20)--][div class=\'quotetop\']QUOTE(gk20 @ Mar 21 2006, 05:39 PM) [snapback]356919[/snapback][/div][div class=\'quotemain\'][!--quotec--] I have a table called item with fields category and item. I can display all distinct categories but I want to display them as links on my home page, so that when u click a category it displays all items in that category on a new page? Here my code for displaying each individual category: <?php include 'db.inc.php'; $cats = @mysql_query("SELECT DISTINCT category from item ORDER BY category"); echo '<b>  Category List<br></b>'; while ($row = mysql_fetch_array($cats)) { echo '<font color=red size="4">'; echo ' '; echo $row['category'] . '<br/>'; echo '</font>'; } ?> Can anyone help? [/quote] if you are trying to link them then add two more echos inside of the while that is while ($row = mysql_fetch_array($cats)) { //like file is $link = "$row['category'] "."php" echo '<font color=red size="4">'; echo ' '; echo '<a href='$link'>'; echo $row['category'] . '<br/>'; echo '</a>'; echo '</font>'; } i hope this will work as per your needs. Thank you, Karthikeyan
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hello, Not just You are logged in as <?php $_COOKIE["policyusername"] ?>. it will be You are logged in as <?php echo $_COOKIE["policyusername"] ?>. [a href=\"http://in2.php.net/manual/en/function.setcookie.php\" target=\"_blank\"]http://in2.php.net/manual/en/function.setcookie.php[/a] Thank you, Karthikeyan
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will you please show that db connectivity codes? like mysql_connect and are you sure that the port(which is used by mysql )is opened. show your code here plz. Thank you Karthi keyan
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header("Location: http://domain.com"); not working.
blazing_bruce replied to blazing_bruce's topic in PHP Coding Help
Hello, i fixed this problem now. by embedding simple java script lines. like ?> <script language="javascript" type="text/javascript"> <!-- Newsite= window.open("<?php echo("$rediurl"); ?>","newsite"); // --> </script> <? Thank you friends and PHP Freaks. Thank you, Karthi keyan. -
hello, The error Can't connect to ... normally means that there is no MySQL server running on the system or that you are using an incorrect Unix socket filename or TCP/IP port number when trying to connect to the server. for more reference about these type of probs [a href=\"http://www.oscommerce.info/kb/osCommerce/General_Information/Common_Problems/69\" target=\"_blank\"]http://www.oscommerce.info/kb/osCommerce/G...mon_Problems/69[/a] Thank you, Karthi keyan.
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header("Location: http://domain.com"); not working.
blazing_bruce replied to blazing_bruce's topic in PHP Coding Help
Great Prismatic, Thanks :) Really it is redirecting me. but one problem. i am using that redirecting line inside <iframe> tag so redirect url's content is showing inside of that iframe. if you are not clear with me then have a look at [a href=\"http://karthi.livesoft.info\" target=\"_blank\"]http://karthi.livesoft.info[/a] i want to load redirection page fully in browser atleast open in new window. Please help me, Thank you, Karthi keyan. -
hello, mysql_pconnect(); function for connecting mysql server. if you are using a simple database on your website then use mysql_connect(); it is enough. Thank you, Karthi keyan.
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header("Location: http://domain.com"); not working.
blazing_bruce replied to blazing_bruce's topic in PHP Coding Help
then how can i redirect to $rediurl? i want to redirect by based on some conditons. Please help me. Thank you, Karthi keyan. -
hello, i am using a script named work.php for two purpose . 1. displaying banner image 2. checking remote address and putting clicks and hits informations in tables 2.1 after making these data base operations, redirecting browser to the $rediurl by using header(); $rediurl = // my url header("Location:$rediurl"); i spliting my script by two separate if conditions. 1st condition for displaying image by echo("<center><a href=\"$hrf\"><img src=\"$banurl\"> <br> </a></center>"); in second condition i am checking ip and date values, after that trying to redirect. by: mysql_close($connection); echo("until db Close "); // this is for debugging process header("Location: $rediurl"); i can get dbclose acknowledgement too. the header line didn't executed. Pleaese help me.
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[!--quoteo(post=356294:date=Mar 19 2006, 06:01 AM:name=Barand)--][div class=\'quotetop\']QUOTE(Barand @ Mar 19 2006, 06:01 AM) [snapback]356294[/snapback][/div][div class=\'quotemain\'][!--quotec--] echo("<center><a [!--coloro:#FF6666--][span style=\"color:#FF6666\"][!--/coloro--]herf[!--colorc--][/span][!--/colorc--]=\"$hrf\"><img src=\"$banurl\"> <br> </a></center>"); try "HREF" or "href" instead of "herf" [/quote] Ohh what a minor mistake i did :( . Thanks a lot Mr.Barand.
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I am doing a banner exchange script. this is the banner tag "<!-- Banner code begin --> <CENTER>'<IFRAME SRC= 'http://domainname.com/subfolder/work.php?ID=$check' width=300 height=400 marginwidth=0 marginheight=0 hspace=0 vspace=0 frameborder=0 scrolling='no'></IFRAME><p> </p></CENTER> <!-- Banner code end -->"; inside work.php $hrf = "http://domainname.com/subfolder/work.php?who=$check&redi=$rediurl"; echo("<center><a herf=\"$hrf\"><img src=\"$banurl\"> <br> </a></center>"); image was perfectly displayed. but i cannt make a link. please help me. Thankyou, Karthikeyan.