gabenut

Thank you very much! The errors have disappeared but now this is displayed: GIF87a?
 I took the comments away from the header, just to check, and the original error comes up.

Thanks very much for your help. The errors I got were these: Warning: mysqli_fetch_row() expects exactly 1 parameter, 2 given in survey.php on line 10 Warning: mysqli_num_rows() expects exactly 1 parameter, 2 given in survey.php on line 17 Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in survey.php on line 22 GIF87a?
 I'm not sure what these mean, so again, any help would be much appreciated. Thank you!

Hello, I have been doing some work on making a survey with PHP and MySQL. I am having a problem displaying the image for the graph. I have been using the imagecreate() function in PHP. The error displayed is: [b]The image "survey.php" cannot be displayed, because it contains errors.[/b] Here's the coding: [code]<?php session_start(); Header("Content-Type: image/gif"); $query = "SELECT count(question_id) FROM final WHERE QuestionID=1"; $result = mysqli_query ($dbc, $query); $row = mysqli_fetch_row($result); $nTotalVotes=$row[0]; $query = "SELECT final.answer_id, answers.answer as tx, count (final.answer_id) as ct FROM final, answers WHERE final.answer_id = answer.answer_id AND final.question_id =1 GROUP BY final.answer_id"; $result = mysqli_query ($dbc, $query); $xDim = 400; $yDim = 15+(mysqli_num_rows($result)*15); $im = ImageCreate($xDim, $yDim); $backg = ImageColorAllocate($im, 255,255,200); $blue = ImageColorAllocate($im, 0, 0, 255); $nY = 0; while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {     $percVote = round(($row['ct']/$nTotalVotes)*100,2);     $percWidth = ($percVote * $xDim / 100) - 10;     ImageFilledRectangle($im, 0, $nY+1, $percWidth, $nY+10, $blue);     ImageString($im,2,$percWidth + 5, $nY+1, $row['tx'] . " " . $percVote . "%", $blue);     $nY=$nY+15; } ImageGIF($im); ?>[/code] Any help would be greatly appeciated, thank you!