Soy un corredor

Any ideas?

[code]$fname = $_SERVER['SCRIPT_FILENAME'];[/code] This includes the file name AND the directory where it's located. Perhaps it'll be best if I explain my overall goal here... My web host allows subdomains, but there are only "aliases" of directories. Meaning, [i]subdomain.site.com = site.com/subdomain[/i]. If a user goes to the address [i]site.com/subdomain/file.php[/i] I want them to be redirected to [i]subdomain.site.com/file.php[/i]. I hope that clears things up. Here is the code that I've been working with: [code]<?php $domain = 'site.com'; $wwwdomain = 'www.site.com'; $url = ''.$_SERVER['HTTP_HOST']; $root = ''.$_SERVER['PHP_SELF']; $file = basename($root); if ( $domain == $url ) { header("Location: http://subdomain.site.com/$file"); exit; } elseif ( $wwwdomain == $url ) { header("Location: http://subdomain.site.com/$file"); exit; } ?>[/code] THIS CODE WORKS GREAT BUT not when the address is [i]site.com/subdomain/file.php?[b]id=5[/b][/i] (for example). They will just be redirected to [i]site.com/subdomain/file.php[/i]. Any ideas? Thanks!

Sorry to post back so soon, but I have a follow-up question regarding my script [above]. Let's say, for example, that the file was [i]view.php?id=3[/i] The above code will only display [i]view.php[/i] . How do I resolve this?

I added the basename() function to my current code and came up with this: [i]$php_self = ''.$_SERVER['PHP_SELF']; $file = basename($php_self);[/i] Works now ;) [b]¡Gracias a todos![/b]

Hello. I'm having a little trouble here. For the sake of simplicity, I'll give an example. Say I have a php file and the location of the file is: [i]http://www.site.com/foldera/folderb/file.php[/i] Each time I try to display [b]just[/b] the file name, I get this: [i]/foldera/folderb/file.php[/i] How can I get just: [i]/file.php[/i] Thanks!