ramu_rp2005
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Hi php gurus, I'm having a problem in accessing the values of the variable from the previous form. The previous form variable is defined below: [code]if(isset($pstreamname)) { ?> <tr> <td valign=top align=right><tt><b>Stream Name</b></td> <td valign=top><input type="text" name="streamname" size="30"><br></td> </tr> <? }[/code] and accessing the above variable is as below. [code]$streamname=@$_REQUEST['streamname']; echo "Streamname is $streamname"; [/code] but its not echoing anything.can anyone tell me why and wht to do? I've added the error reporting also at the top.no errors,plz help. [code]<?php error_reporting(E_ALL); ini_set('display_errors', 1); ?>[/code]
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I've a readonly text with a line of text stored in variable $query1, to be passed to next page on click of a button.How do i do it. I've already done the following to no use. creating readonly text box as below: [code]echo "<input readonly name=\"query1\" value=$query1 size=$qsize >"; [/code] I'm passing the value of query1 as: [code] <input type="hidden" value="$query1" /> <input type="submit" value="Run" > [/code] and i'm accessing in next page as, [code] $query1= $_REQUEST[query1]; echo "-------- Query1 is $query1-------"; [/code] but i'm unable to access the variable query1.don't the reasong.any help?
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I've got a line as below. How can i pass this line of text to the next page on click of a button. [code]streamname,resolution,videopid,pcrpid,audiopid,audiotype,videotype,samplerate [/code] I've stored the above line in a variable $query1.
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Hi all, I'm displaying a query result of 1000+ rows in a table containing 10 columns and after executing the query on click of a button it displays only around 30 rows. Not able to figure out the problem. Any help would be appreciated. Thank you all.
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Passing values from combo box to another form
ramu_rp2005 replied to ramu_rp2005's topic in PHP Coding Help
i'm a newbee to php plz tell me exactly in a little more detail. -
Hi guys, i've a combo box and the value or the item changed in it should be passed to another form.their r no buttons.how do i do that??
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What does setcookie do in My function??
ramu_rp2005 replied to ramu_rp2005's topic in PHP Coding Help
ok.where will that visitors cookie file be stored.the location id used here is not assigned any value.this is my first form of the web page,so from where the $locationid value come from. -
hi guys, i've a function: [code]if ( isset ($LocationID) ) { ob_start(); setcookie("HostLocationID",$LocationID); ob_end_flush(); //echo "===$LocationID===="; }[/code] Now, wht does this setcookie function do over here.does it pass any value to another form.
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I've a code like this below: <BODY background=images/ltgray_lines1.gif text=000000> <br><br><br><br><br><font size=2 face="Garamond"> <FORM method=GET name="searchform"><center> <table> <tr><td>Search</td> <td><select name="pattern" > <option value="streamtype">Type</option> <option value="streamname">Name</option> <option value="videopid"> Vid Pid</option> <option value="audiopid">Aud Pid</option> <option value="pcrpid">Pid</option> <option value="clockrate">Clock Rate</option> <option value="videotype">ideo type</option> <option value="ac3bitrate">A3 Bit</option> <option value="ac3mod">A3 Mod</option> <option value="samplerate">Sam Rate</option> <option value="resolution">Res</option> <option value="profile">Prof</option> </select></td></tr><br><br> </table> <br><br> <input type="button" value="Search" onclick=selectstr()> </center> </FORM> </font> </BODY> Now my doubt is how can i take the value of the combo and submit it to another form.My friend gave the cod e below. but can anyone explain what does it mean.the code is below: wht does "str=str=" mean. function selectstr() { frm=document.searchform str=str = frm.pattern.options[frm.pattern.selectedIndex].value location.href="setstring.php?string="+str }
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i've sent a value from one page to another,as <a href="browsedirectory.php?typeid=<? echo $id ?>" target=main><font size=2 face="Tahoma"><? echo $name ?></font></a> Now,how to obtain and use the value of typeid in browsedirectory.php . if i use echo typeid; in browsedirectory.php it shows nothing is their.so how do i obtain this value.
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no.this is not working.page is displaying empty!!1
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no its not working.the page is empty!! <html> <body> <?php //echo gethostbyaddr($_SERVER['REMOTE_ADDR']); $db = mysql_connect("localhost", "root", "ramki"); $test=mysql_select_db("streamware"); if($test) echo "successful"; else echo "unsuccessful"; ?> </body> </html> this is my altered code.
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hi, i have executed the following lines of code in my php file to connect to mysql but the page is empty MySQL is installed and the password is ramki. <html> <body> <?php $db = mysql_connect("localhost", "root", "ramki"); if($db) echo "conn successful"; else echo "conn not successful"; ?> </body> </html> the if condition, it is not displaying if or else part. wht do i do now?is there any probem with php connecting to mysql.how do i test it.