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mayu_bt

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  1. Hi Friends, I have a query... a bit complex I think. I currently have a webbased LAN browser application which is build in PHP 4 This application is used to track day-to-day data transactions of few workers in here. It is running quite well. Now I need to extend this to record few telephonic conversations from the workers... This should be another filed like thing captured in .WAV or .WMV file to server & only the path stored in the database. Am running this application on, ----------------------------- Windows 2000 professional, Apache server, PHP, My SQL, Can you please help me with this? Thanks, Mayu
  2. Hi Gurus, I want to use GD2 with JPgraph to have graphs and charts for my data. Below are my PHP and other details. Operating system: Windows server 2000 Webserver: Apache 4.0.15 Script: PHP 4.3.3 relavent Contents of PHP.ini : doc_root = e:\Program Files\Apache Group\Apache2\htdocs extension_dir = "./" extension=php_gd2.dll I have removed ";" GD: I have a folder by name gd-2.0.33 with .C files JPGraph: JPgraph 1.20.3 I have a webapplication running sucessfully with the above php.ini settings, I need to use GD2 so please help me to configure GD2 and use it in my scripts Thanks in advance, mayu_bt
  3. Hi kenrbnsn, What is that AJAX programming? is it a new concept or a new language? plese tell me how and where to get more information on that to get my current problem solved..
  4. Hi Gurus, Please tell me what to do when its needed to run PHP server scripts in the condition statements of JAVA script.. When I enter any PHP script in the body of a function of javascript and want that to run only when some conditions are met, its not happening... it runs whether the condition is met or not... I mean the if statement is simply not being checked!!.. eg: <script-javascript> function start(){ if(document.option.blah blah..) { <?PHP ech "Hi Mayu"; ?> } } . . . . .
  5. Hi Peoples, Am unable to unset OR reset OR destroy $_GET variables, that is the ones which are passed to a php file from java script functions. I cannot afford to destroy the whole session variables as I need to have $_SESSION variables for user authentication and other stuffs. I have used unset() function but it failes to unset them! Please help me..
  6. Thanks a ton HITMAN!! I guess the scripts are just a piece of cake to you!! :)
  7. Hi team, I am stuck in a huge problem..and need HELP!! please help me..I have generated an application to track the daily transaction of workers in my Office. But now I am very badly in need to track their break timings as well and hence want to include a dropdown some where in the page above the table view. This drop down should have list of break types like "coffee", "Lunch" etc.. and next to this drop down should be two buttons one called ‘start’and one called ‘end’.. when the user clicks ‘start’ the start datetime at this should be captured in a variable and when user clicks ‘end’ button the dtatetime at this point should be captured and the difference that is the break time should be recorded in separate table along with start and end time. And also initially the ‘end’ button should be disabled and when the user selects the breaktype from dropdown and clicks start button.. the ‘end’ button should be enabled and ‘start’ button should be disabled.. PLEASE HELP.... toplay: Edited title to be more meaningful.
  8. Hi Learned people, I am using the below syntax to have popup window popping up when I select the option in the dropdown. echo "<select onchange=\"window.open('breaktype.php?username= ', 'Edituser', 'width=500,height=400,scrollbars=1')\">"; echo "<option>--Select--</option>"; echo "<option value='C'>Coffee</option>"; echo "<option value='F'>Fag</option>"; echo "<option value='L'>Lunch</option>"; echo "<option value='O'>Others</option>"; echo "</select>"; How to pass the value selected from the drop down to the popup in the above syntax? if I mention this.option it takes the valuse as "this.option" itself!! but not the value selected in the dropdown... PLEASE HELP.... POPUP window is popping up fine with the above syntax.. the problem is passing the value selected in the dropdown....
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