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tarun

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Posts posted by tarun

    Cannot modify header information

    in PHP Coding Help

    Posted

    Ive Already Asked For Help About This But...

     

    Heres My New Code

    <?PHP $host = $_SERVER['HTTP_HOST']; ?>
<?PHP INCLUDE("http://$host/header.php"); ?>
<DIV CLASS="contentheaderdiv">Home</DIV>
<DIV CLASS="maincontentdiv">
Welcome To TPatel<BR>We Hope You Enjoy Our Site
<?PHP
if(!isset($changestyle)){
echo'<BR><BR>Please Choose A Style For The Site:<BR>
<FORM ACTION="index.php" METHOD="POST">
<SELECT NAME="changestyle"> 
<OPTION>Blue</OPTION>
<OPTION>Green</OPTION>
<OPTION>Brown</OPTION>
</SELECT>
<INPUT TYPE="SUBMIT" VALUE="Change Style">
</FORM>';
exit;
}
$newstyle = $_POST['changestyle'];
htmlentities($newstyle);
if($newstyle ==  Blue)
{
setcookie("style", "blue", TIME()+3600);
echo 'The Style Was Successfully Changed';
}
elseif($newstyle ==  Green)
{
setcookie("style", "green", TIME()+3600);
echo 'The Style Was Successfully Changed';
}
elseif($newstyle ==  Brown)
{
setcookie("style", "brown", TIME()+3600);
echo 'The Style Was Successfully Changed';
}
else
{
echo 'The Style Could Not Be Changed';
}
?>
</DIV>
<?PHP INCLUDE("http://$host/footer.php"); ?>

     

     

    Why Do I Get This Error When Submitting The Form

    "Warning: Cannot modify header information - headers already sent by (output started at *****/header.php:10) in /home/www/*****/index.php on line 33"

    [SOLVED] Parse error: parse error, unexpected T_IF in ****** on line 21

    in PHP Coding Help

    Posted

    Okay This Is My Code:

     

     

    <?php $host = $_SERVER['HTTP_HOST']; ?>
<?php INCLUDE("http://$host/header.php"); ?>
<DIV CLASS="contentheaderdiv">Home</DIV>
<DIV CLASS="maincontentdiv">
Welcome To TPatel<BR>We Hope You Enjoy Our Site
<?php
if(!isset($changestyle)){
echo'<BR><BR>Please Choose A Style For The Site:<BR>
<FORM ACTION="index.php" METHOD="POST">
<SELECT NAME="changestyle"> 
<OPTION>Blue</OPTION>
<OPTION>Green</OPTION>
<OPTION>Brown</OPTION>
</SELECT>
</FORM>';
exit;
}
$newstyle = $_POST['changestyle'];
htmlentities($newstyle)

if($newstyle ==  Blue)
{
setcookie("style", "blue", TIME()+3600);
echo 'The Style Was Successfully Changed'
}
elseif($newstyle ==  Green)
{
setcookie("style", "green", TIME()+3600);
echo 'The Style Was Successfully Changed'
}
elseif($newstyle ==  Brown)
{
setcookie("style", "brown", TIME()+3600);
echo 'The Style Was Successfully Changed'
}
else
{
echo 'The Style Could Not Be Changed'
}
?>
</DIV>
<?php INCLUDE("http://$host/footer.php"); ?>

     

     

    But Why Do I Get This Error:

     

    "Parse error: parse error, unexpected T_IF in ****** on line 21"

    (Obviously The Stars Are Just To Hide The Location Of The File)

     

     

    Thnx,

    Tarun

    fwrite problems..

    in PHP Coding Help

    Posted

    I Cant Find Exactly What's Wrong But

    You Could Mayby Build It Around This

     

    $filename = "text.txt";

    $filecontent = "The Content Of The File"

    $file_pointer1 = fopen("$filename", "w");

    fwrite($file_pointer1, "$filecontent");

    fclose($file_pointer1);

    [SOLVED] DIV ALIGN Help

    in HTML Help

    Posted

    This Is My Basic Layout For My Guestbook

    <CENTER>
<DIV ALIGN="LEFT"><a href="mailto:">Tarun</a></DIV>
<DIV ALIGN="RIGHT">10/02/07 | 14:08pm</DIV>
<DIV ALIGN="LEFT">GUESTBOOK MSG</P>
</CENTER>

     

    But...

    The Bit Where It Says "10/02/07 | 14:08pm" Is On A New Line

     

    AnyHelp

     

    Thnx,

    Tarun

    Array - How To Change Values

    in PHP Coding Help

    Posted

    I Had Help With This Yesturday And Now I Need Some More

    This Is My Example Code

    $friendList = array();
$friendList["Lisa"] = "offline";
$friendList["Jack"] = "online";
$friendList["Ryan"] = "offline";
$friendList["Rachel"] = "offline";
$friendList["Grace"] = "online";

foreach( $friendList as $key => $value){
echo "Friend: $key, Status: $value";
}

     

    How Would I Change The Values (offline, online etc.)?

     

    Thnx,

    Tarun

    Array - Adding and Removing

    in PHP Coding Help

    Posted

    Okay Heres My Code

    $friendList;
$friendList["Lisa"] = "offline";
$friendList["Jack"] = "online";
$friendList["Ryan"] = "offline";
$friendList["Rachel"] = "offline";
$friendList["Grace"] = "online";

foreach( $friendList as $key => $value){
echo "Friend: $key, Status: $value";
}

     

    How Would I Add And Remove Friends?

     

    Thnx,

    Tarun

    [SOLVED] Single .php file vs many .php files

    in PHP Coding Help

    Posted

    Personally, i like to have smaller php files that link to each other, like i have header.php, footer.php, menu.php. in this way, when i edit one php file, all the other pages get updated, and this saves both space and time when designing your pages.

    but thats my opinion.

    Ted

     

     

    I Agree This Is A Much Easier Way Of Editing Content Like Navigation Menus

    Form Validation

    in Javascript Help

    Posted

    Well Ive Been Looking Around For You And Ive Found This:

    Simple But Does The Job - And It Can Easily Be Changed To Suit Your Needs

    Hope Ive Helped,

    Tarun

     

     

    <style>
.error {
color: red;
display:none;
}
</style>
  
<script>
function checkForm() {
user = document.getElementById("user").value;
pass = document.getElementById("pass").value;
  
if (user == "") {
hideAllErrors();
document.getElementById("userError").style.display = "inline";
document.getElementById("user").select();
document.getElementById("user").focus();
return false;
}else if (pass == "") {
hideAllErrors();
document.getElementById("passError").style.display = "inline";
document.getElementById("pass").select();
document.getElementById("pass").focus();
return false;
}
return true;
}

function hideAllErrors() {
document.getElementById("userError").style.display = "none"
document.getElementById("passError").style.display = "none"
}
</script>
  
<form onSubmit="return checkForm();" action='login.php' method='post'>
Username: <input type='text' name='user'><br>
<div class='error' id='userError'><br>Required: Please Enter Your Username<br></div><br>
Password: <input type='password' name='pass'><br>
<div class='error' id='passError'><br>Required: Please Enter Your Password<br></div><br>
<input type='submit' name='submit'>
</form>

    Different Title Depending On URL

    in PHP Coding Help

    Posted

    I Need Some Help

    I Want To Have A Different Page Title (<title>) Depending On The URL

    Ive Got This But I Know That Its Wrong

    <?PHP
if $_SERVER['PHP_SELF'] == "index.php"{
echo "<title>HomePage</title>";
}
if $_SERVER['PHP_SELF'] == "chat.php"{
echo "<title>ChatRoom</title>";
}
else{
echo "<title>PageNotFound</title>"
}
?>

     

    Thnx

     

    Tarun

    Title

    in PHP Coding Help

    Posted

    Ok Thnx

    But Could This Work

    if $_SERVER['PHP_SELF'] == "index.php"{
echo "<title>HomePage</title>";
}
else{
echo "<title>PageNotFound</title>"
}

    Just Remember Im A Bit Of A Newbie When It Comes To If and ElseIf

     

    Tarun

    Title

    in PHP Coding Help

    Posted

    I Want Some Thing Like

    Say If The Is index.php To Echo <TITLE>Tarun-Home</TITLE>

    And If It Is chat.php To Echo <TITLE>Tarun-Chat</TITLE>

    Im Not Sure How To Do It - Any Ideas?

     

    Thnx

    Tarun

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