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MsKazza

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  1. MsKazza
    MsKazza's post in If mysql field = yes how to display image? was marked as the answer   
    <? if ($vTakeout=='y') {?>
    <img src="takeoutyes.jpg">
    <? } elseif ($vTakeout=='n') { ?>
    <img src="takeoutno.jpg">
    <? } ?> 
     
    I was missing ; from after the two images.
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