scvinodkumar

Hi i have validate the URL in php. I am using the below regular expression to valdiate it...for some url its working but for few url its not working...could u plz help me this is the code i am using currently function isValidURL($url) { return preg_match('|^http(s)?://[a-z0-9-]+(.[a-z0-9-]+)*(:[0-9]+)?(/.*)?$|i', $url); } For example, if enter the invalid url, still it accepting, http://test

Thanks for your help. But its not working as per my example, but when i change double quote to single quote, it is converting to url. Could u please tell me how to rectify this problem?

Hi i searched google and found this function (http://zenverse.net/php-function-to-auto-convert-url-into-hyperlink). Its working fine until the url is not within double quotes. For example, $string = 'I have some texts here and also links such as "http://www.youtube.com" , www.haha.com and lol@example.com. They are ready to be replaced.'; When i call the function it is converting haha.com and lol@example.com only, not youtube.com. Please help me to solve this issue.. Thanks...

OK friends..thanks for your solutions...let me apply...

Yeah i can do like that, but its working in local system even with the same file name. Its not only working in the server....

@squiblo i uploaded through form. Please tell me the solution to display image with this type of filename

Hi Friends, I have uploaded a image with the file name (pics%20of-cute-girls.jpg). Its uploaded and displaying in the local system but not in the server. Could you please tell me what should be the reason for this? what setting does i need to change? For your reference i have attached that file [attachment deleted by admin]

$radiobuttonvalue = $_POST['radiobuttonvalue']; $query = "update tablename set fieldname = '".$radiobuttonvalue."' where primaryfieldname=value"; consider, your form will be like this, <input type="radio" name="radiobuttonvalue" value="1">Y <input type="radio" name="radiobuttonvalue" value="0">N

if(strtolower($firststring) == strtolower($secondstring)) echo "same letter"; or if (strcasecmp($firststring, $secondstring) == 0) echo "same letter";

the rand() which is used to display random numbers only, for that you need to use like this $pid = array_rand($products); echo $products[$pid];

change <? to <?php and try

Change your submit name like this, <form method="post"> <input type="submit" name="Submit1" value="SEND" /> <input type="submit" name="Submit2" value="SEND" /> <input type="submit" name="Submit3" value="SEND" /> </form> f(isset($_POST['Submit1'])) $Query = mysql_query( 'INSERT INTO `table` (`Submit`) VALUES ("' . $_POST['Submit1'] . '",)' ); f(isset($_POST['Submit2'])) $Query = mysql_query( 'INSERT INTO `table` (`Submit`) VALUES ("' . $_POST['Submit2'] . '",)' ); f(isset($_POST['Submit3'])) $Query = mysql_query( 'INSERT INTO `table` (`Submit`) VALUES ("' . $_POST['Submit3'] . '",)' ); Try this

You should use like this, echo "<a href='www.link1.com/index.php' title='link 1'>message 1</a>"; whenever you open quote, you need to close quote.

I think this code will produce an error while executing the query, so try like this $res = mysql_query($sql) or die(mysql_error()); and try to use php functions in small letters instead of caps, like mysql_query instead of MySQL_query

i think you have not pasted right code here, so please re-post that php code