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MasterACE14

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Posts posted by MasterACE14

    Session handler for multiple domains/subdomains

    in PHP Coding Help

    Posted

    Good Day,

     

    I'm using the following example script from http://php.net/manual/en/function.session-set-save-handler.php which I have placed in session-handler.php and is included at the top of my index.php file. I have multiple domain names for the same website, so naturally when a person logs into the site, I would like the session to be active across all the domains instead of them having to login again if say they go from mysite.com to mysite2.com.

     

    session-handler.php

    <?php

function open($save_path, $session_name)
{
  global $sess_save_path;

  $sess_save_path = $save_path;
  return(true);
}

function close()
{
  return(true);
}

function read($id)
{
  global $sess_save_path;

  $sess_file = "$sess_save_path/sess_$id";
  return (string) @file_get_contents($sess_file);
}

function write($id, $sess_data)
{
  global $sess_save_path;

  $sess_file = "$sess_save_path/sess_$id";
  if ($fp = @fopen($sess_file, "w")) {
    $return = fwrite($fp, $sess_data);
    fclose($fp);
    return $return;
  } else {
    return(false);
  }

}

function destroy($id)
{
  global $sess_save_path;

  $sess_file = "$sess_save_path/sess_$id";
  return(@unlink($sess_file));
}

function gc($maxlifetime)
{
  global $sess_save_path;

  foreach (glob("$sess_save_path/sess_*") as $filename) {
    if (filemtime($filename) + $maxlifetime < time()) {
      @unlink($filename);
    }
  }
  return true;
}

session_set_save_handler("open", "close", "read", "write", "destroy", "gc");

session_start();

?>

     

    The script above doesn't appear to be throwing any errors, and I can login like normal but it doesn't seem to be saving the sessions at all. So I still have to login to each separate domain.

     

    Any ideas?

     

    Thanks,

    Ace

    session across multiple domains

    in Miscellaneous

    Posted

    To solve #1, you must store the session data using a means that permits access by both domains/accounts. Using a database based custom session save handler would solve this problem.

    I'm thinking this may be the best way to go about it.

     

    Hmmm. In typing this, I just thought of something you might try (still requires rewriting part of your login code and then making sure that a hacker cannot exploit it.) When someone logs in and gets a sid (or you ever regenerate a sid), you would need to store the sid in the user's row in your user table and then momentarily redirect them to a (blank) page in the opposite domain with that sid on the end of the URL. The page you redirect to would take that sid from the URL, find the matching row in the user table (to identify the user/get his userid), and then start a session using that sid so that you set a session id cookie under that domain with that sid. You would set any session variables needed to satisfy you login script, the same as if they had just manually logged in under the opposite domain. You would then redirect back to the starting domain. I think that by making sure that the sid stored in the database is unique and then matching the sid passed on the end of the url with one in the database table, that this is as secure as manually logging in on the opposite domain. Perhaps add a timestamp check to the user table as well - if the redirect/sid check in the opposite domain doesn't occur within a short time of when the sid was assigned and stored in the user table, then don't setup the session/automatically log them in on the opposite domain.

    I can see how that'd work and is a good solution, however I will be adding more websites overtime, so redirecting to 3 or more 'blank' pages to setup a session probably won't be the best approach. For just the 2 domains that's a clever approach.

     

    Thanks for your wisdom and knowledge as always!

     

    Kind Regards,

    Ace

    session across multiple domains

    in Miscellaneous

    Posted

    Hello,

     

    I have two websites on the same server, but with two different domain names. I have it setup so you have a single account which you can log into either website. So if you're logged into one of the sites, you're automatically logged into the other website as well. This all works fine locally as it's the single domain http://localhost/ however on my website when you log into one, you have to then log into the other one as well because obviously the session saves to the one domain.

     

    After googling I found.... session_set_cookie_params(0, '/', '.crikeygames.com.au'); works fine for that domain and all subdomains, but I believe I can only use this function once? or atleast for only one domain.

     

    I have seen people saying you can append the session id to the URL when switching between the sites to maintain the session. I'm not sure if that's the most ideal way.

     

    Maybe it can be achieved with .htaccess? Or would session_set_save_handler() be the way to go?

     

    Thanks,

    Ace

    Placing a cron file somewhere it won't be accessible

    in Miscellaneous

    Posted

    Hi Guys,

     

    Haven't done this before so am I a bit lost. I log into my webserver via FTP, and have placed my cron.php file in the '/' directory, for clarity the same directory that contains the 'www' and 'public_html' directories. Now according to Cpanel my home directory is '/home/crikeyga' so I'm not exactly sure what the exact path to my cron.php is, or if I even have put it in the right location where it can't be accessed publicly?

     

    Thanks in advance,

    Ace

    assigning weapons to soldiers

    in PHP Coding Help

    Posted

    Or if you just want total damage and don't care about individual weapon stats:

     

    <?php

$total_power 	= 0;
$total_weapons 	= 0;
$soldiers 		= 100;

$q = mysql_query("SELECT `item_quantity`, `item_power` FROM `items` WHERE `owner_id` = " . intval($userid) . " ORDER BY `item_power` DESC");
while($row = mysql_fetch_assoc($q)) 
{
$row['item_quantity'] = intval($row['item_quantity']);

$total_weapons += $row['item_quantity'];
    if ($total_weapons > $soldiers)
    {
	$extra_weapons = $total_weapons - $soldiers;

	// trim the item_quantity so that it doesn't surpass how many soliders you have
	if ($row['item_quantity'] = ($row['item_quantity'] - $extra_weapons) != 0)
	{
		$total_power += $row['item_quantity'] * intval($row['item_power']));
	}
        break;
    }
$total_power += $row['item_quantity'] * intval($row['item_power']));
}

     

    that's done the trick! many thanks!

    assigning weapons to soldiers

    in PHP Coding Help

    Posted

    Your comment says "assign weapons to soliders" which is what my code does. I'm not sure what you're asking now, because your comments are conflicting.

    Sorry I just noticed the mistake I made in the comment in my first example, should of been $soldiers * item_power rather than item_power * item_quantity.

    assigning weapons to soldiers

    in PHP Coding Help

    Posted

    Maybe if you explained how soldiers are represented in your code you'd get a better answer.  $soldier = 100 doesn't convey any meaning.

    My apologies, $soldier = 100; is the total amount of soldiers the user has(usually comes from the database, 100 for the purpose of this thread).

     

    I'll try to explain my problem differently.

     

    If I have 100 soldiers, and say 3 records for weapons(items) this particular user has in the database containing...

     

    weapon -------- item_quantity ---------- item_power       

    1                      30                                25

    2                      50                                10

    3                      50                                5

     

     

    I want to determine the total power(damage) that this player has by essentially adding `item_power` * `soldiers`(from strongest item_power to lowest) until there is no more 'weaponless' soldiers or, there is not enough soldiers to virtually 'equip' the items.

     

    So in this scenario the total power of this user would be:

     

    first weapon: 30 * 25  (30 soldiers have the first weapon equipped)

    second weapon: 50 * 25 (50 soldiers have the second weapon equipped, 80 soldiers have weapons equipped in total now)

    third weapon: 20 * 5 (20 soldiers have the third weapon equipped, 100 soldiers have weapons equipped in total, 30 are weaponless)

     

    total power = (30 * 25) + (50 * 25) + (20 * 5)

     

    If in this scenario there was less weapons than soldiers, it would not equip anymore weapons once all the soldiers have weapons.

    assigning weapons to soldiers

    in PHP Coding Help

    Posted

    assigning weapons to soldiers is an explanation of what I'm theoretically trying to achieve, I'm not literally trying to assign an array of values to each individual soldier. As I commented within my example

    // assign weapons to soldiers and add `item_power` * `item_quantity`to $damage

     

    thinking something like...

    if($soldiers > $row['item_quantity']) {
  $damage += $row['item_power'];
} else // ...

    assigning weapons to soldiers

    in PHP Coding Help

    Posted

    Good Day Everyone!

     

    I'm having trouble figuring out how to assign weapons from a MySQL table to soldiers.

    Say I have the following...

    $soldiers = 100;
$damage = 0;
$q = mysql_query("SELECT `item_quantity`, `item_power` FROM `items` WHERE `owner_id`='".$userid."' ORDER BY `item_power` DESC");
while($row = mysql_fetch_assoc($q)) 
{
   // assign weapons to soldiers and add `item_power` * `item_quantity`to $damage
}

    I want to assign all the weapons until there's not enough soldiers to assign them to, and I want to assign them in order of `item_power` descending.

     

    I'm sure this is really simple, I just can't for the life of me get my head around it.

     

    Thanks in advance!

     

    Kind Regards,

    Ace

    php echo help

    in PHP Coding Help

    Posted 

    $statisctis = ("SELECT date_liked , COUNT(site_id) AS num_site_id FROM `liked` WHERE date_liked < CURDATE() AND date_liked > CURDATE() - INTERVAL 1 WEEK AND site_id='45' GROUP BY date_liked"); 
$result1 = mysql_query ($statisctis) or die(mysql_error());
echo "date_liked - num_site_id";
while($row = mysql_fetch_assoc($result1))
{
  echo $row['date_liked'] . " - " . $row['num_site_id'];
}

    Apply condition to the output based on the count value?

    in PHP Coding Help

    Posted 

    $match = array('W','W','L');
$getAwayR = "Group A";

if($getAwayR == "Group A"){
    $numWins = 0;
    for($i = 0; $i < count($match); i ++){
        if($match[$i] == "W" && $numWins < 3){
            // whatever else
            $numWins++;
        }
    }
}

    this is a much cleaner solution RON_ron, I'd just change one thing.

    $count = count($match);
for($i = 0; $i < $count; i ++){

    Apply condition to the output based on the count value?

    in PHP Coding Help

    Posted

    you need to use either an array or this...

    ${'match'.$matchWcounter}

    $match . $matchWcounter is appending their values, rather than the variable names.

     

    Personally I think an array is more appropriate.

    $match = array();
$match[1] = "W"
$match[2] = "W"
$match[3] = "L"
$getawayr="Group A";

if($getawayr=="Group A"){
for ( $matchWcounter = 1; $matchWcounter <= 3; $matchWcounter ++) {
$numOfWinsCount = 0;
if($match[$matchWcounter]=="W" and $numOfWinsCount <3){
$numOfWinsCount=$numOfWinsCount+1;
$matchresult . $matchWcounter = "Qualified for Quarter Finals!";
}
}
}

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