chwebdesigns

Hmm thanks for that info - need to start checking compatibility in chrome I think! Will have to look into all of the coding then and decide where the problem lies, whether it's in CSS / HTML / PHP or a mixture of all 3! Thanks for the help Cal

This is just a guess at what you mean by properly! But how about: background-color: white; background-image:url(blueGradient.png); background-repeat:repeat-x; background-position: bottom left; Also just a suggestion, it is normally better to define a style in a .css file as a class (e.g. tr .background ) and then have the code <tr class="background"> Hope this helps a bit, Cal

How strange, This problem is happening in IE9 but after double checking in firefox, I've realised that the opposite occurs in Firefox, as it is stopping the horizontal scroll before all of the pictures are there. Thanks, Cal

Hi, Thanks for the reply. The website is online at www.catherinelaura.com/pages/portfolio from there, there are 3 seperate galleries each gallery has the same coding and each has the same problem (they are the same page, just witha different ?id=xx value) Thanks, Cal

Hi, I have no idea why this problem is happening, so was wondering if anyone could help? I have a PHP script pulling images from a flickr account and displaying them on my website. The images are set so that they appear in a horizontal scroll box which fills the width of the page content. However, when the page is first loaded, there is a load of blank space at the end of the scroll box, making the scroll box continue, on the page refresh/reload this blank space disappears and the total width of the scroll box is just that so all of the images fit in. I hope this makes sense? Any ideas? The relevant parts of the CSS coding are as follows: #streamcontainer {white-space: nowrap;height: 360px;}#photostream {width: 670px;height: 365px;overflow-x: auto;overflow-y: hidden;white-space: nowrap;} I have also included below the relevant HTML and PHP Coding incase this helps at all? <div id="photostream"> <div id="streamcontainer"> <?php $flickr = getSet($theSet); ?> </div></div> <?php function getSet($which) {global $user;global $apikey;$method = 'flickr.photosets.getPhotos';$params['user_id'] = $user;$photoCollection =& new DOMIT_Document(); $request_url = 'http://www.flickr.com/services/rest/?'; if (empty($params)) $params = array();$params['api_key'] = $apikey;$params['method'] = $method;$params['photoset_id'] = $which; foreach ($params as $var => $val) { $var = urlencode($var); $val = urlencode($val); $request_url .= "&$var=$val"; }$safe_return = getFileContents($request_url);$response = $photoCollection->parseXML($safe_return);$photos =& $photoCollection->documentElement->getElementsByTagName("photo");$total = $photos->getLength(); for ($i=0; $i<$total; $i++) { $currImg =& $photos->item($i); $id =& $currImg->getAttributeNS($URI, 'id'); $server =& $currImg->getAttributeNS($URI, 'server'); $secret =& $currImg->getAttributeNS($URI, 'secret'); echo "<a href=\"http://static.flickr.com/".$server."/".$id."_".$secret.".jpg\" rel=\"lightbox[flickr]\" title=\"".$id."\" name=\"$user\"><img src=\"http://static.flickr.com/".$server."/".$id."_".$secret.".jpg\" alt=\"Catherine Laura Photography\" class=\"photo\" /></a>";}} ?> Any help or ideas are much appreciated - as I am absolutley stumped on thoughts now! Many thanks in advance, Cal

Hi, I have no idea what is causing the problem, so any help or ideas would be greatly appreciated. I am using a 3rd party script to connect the website to a flickr account and pull the images from there. The images then appear in a css defined <div> area with a scrollbar across the bottom. This works fine, however when the page is first loaded there is a load of blank space at the end of the scroll area, however once the page has been refreshed or reloaded this blank space disappears. I don't want the blank space to appear as it looks like the images haven't fully loaded when they have. As I am not sure what is causing the problem I have included the PHP Code, HTML Code and relevant CSS snipets. Any help or ideas are much appreciated! Many thanks, Cal 1) PHP Function to get the relevant set from flickr function getSet($which) { global $user; global $apikey; $method = 'flickr.photosets.getPhotos'; $params['user_id'] = $user; $photoCollection =& new DOMIT_Document(); $request_url = 'http://www.flickr.com/services/rest/?'; if (empty($params)) $params = array(); $params['api_key'] = $apikey; $params['method'] = $method; $params['photoset_id'] = $which; foreach ($params as $var => $val) { $var = urlencode($var); $val = urlencode($val); $request_url .= "&$var=$val"; } $safe_return = getFileContents($request_url); $response = $photoCollection->parseXML($safe_return); $photos =& $photoCollection->documentElement->getElementsByTagName("photo"); $total = $photos->getLength(); for ($i=0; $i<$total; $i++) { $currImg =& $photos->item($i); $id =& $currImg->getAttributeNS($URI, 'id'); $server =& $currImg->getAttributeNS($URI, 'server'); $secret =& $currImg->getAttributeNS($URI, 'secret'); echo "<a href=\"http://static.flickr.com/".$server."/".$id."_".$secret.".jpg\" rel=\"lightbox[flickr]\" title=\"".$id."\" name=\"$user\"><img src=\"http://static.flickr.com/".$server."/".$id."_".$secret.".jpg\" alt=\"Catherine Laura Photography\" class=\"photo\" /></a>"; } } 2) HTML Code to display photos <div id="photostream"> <div id="streamcontainer"> <?php $flickr = getSet($theSet); ?> </div> </div> 3) CSS Code for Containers #streamcontainer { white-space: nowrap; height: 360px; } #photostream { width: 670px; height: 365px; overflow-x: auto; overflow-y: hidden; white-space: nowrap; } Thanks again!

Many thanks @phpfreak , has worked now Also @Christian F. it is a slight mix between the 2 really, it is intendented slightly different in my code editor, but I know they aren't the best indentations!! Thanks, Cal

Hi, When I try and execute the following PHP code, I get the following error message: What I am trying to do is 'copy' the data from a mysql table back into the same table but with one of the fields with a different number, if that makes sense? The PHP code I am working with which brings the error message is: include("../setup/dbconnect.php"); $sql = "select * from classes where term='$import'"; #execute the query $conn = @mysql_query($sql ) or die("Could not execute query"); while ($row = mysql_fetch_array( $conn ) ) { $day = $row['day']; $time = $row['time']; $grade = $row['grade']; $teacher = $row['teacher']; $sqlvalues = "('$day', '$time', '$grade', '$TermID', '$teacher')"; $sql2 = "insert into classes (day,time,grade,term,teacher) values $sqlvalues"; include("../setup/dbconnect.php"); #execute the query $conn = @mysql_query($sql2 ) or die(mysql_error()); if ($conn) { echo"<br />Classes Copied"; } } Any help will be much appreciated. If you need any more info just let me know. Many thanks in advance, Cal

I have been thinking and thinking about it and still I am not getting anywhere. Obviously what will tell me that I have reached a new class by just looking down the list is when the class_assignment number changes Thanks

Thanks for the quick reply I am wanting the output to be in a table for example. So if I order by class_assignment that will list all classes in the one table, where each class needs to be in a separate table on the page, so is there a way of splitting the data up like this? Thanks, Cal

Hi, I am writing a class application, where students are assigned to a class in a mysql database such as: id student_name class_assignment 001 A Student 1 002 B Student 2 003 C Student 1 004 D Student 1 .... etc. what I want to be able to do is print a table off for each class. I know I could do this individually with an sql such as <?php $sql = "SELECT * from classes where class_assignment='1'"; ?> But what I would like to be able to do is 'report' class 1 register have a page break, then class 2 register etc. in one click - I am unsure at the moment how many classes there are going to be. Is this possible? Hope this makes sense? Many thanks in advance, Cal

Many thanks, Just what I needed

Hi, I don't have a lot of experience with mySQL and SQL commands. Here is my command on which I am working on: $sql = "SELECT * from shop_products where subcat='$cat' order by id asc"; This part of the code works fine. However I want to include to WHERE parts in the sql statement. I have tried this, however I come up with an error saying that it cannot execute the query: $sql = "SELECT * from shop_products where subcat='$cat' where shown='1' order by id asc Any ideas would be appreciated. Many thanks

Hi, I have a PHP code which searches a mysql database. And then shows the results. However, I want the code to search multiple columns and then show which column it comes from. An example of the table called $table: Gold Silver Bronze J Smith A Jones C Holmes and i used the php code to select it from a single column rather than searching multiple columns: <?php $sql = "SELECT * from $table where gold like '%$name%' "; ?> Hope that this makes sense. Thanks in advance

Where you have the code <form action='upload.php' you need to specify the album id again. So it will be something like <form action='upload.php?album=$albumid' method='post' Hope this helps Cal

Thanks for that works great!!

Hi, I'm pretty new to writing lots of things in php, and this is probably a obvious answer. I've got this section of code <?php if (!$_GET['nav'] ) { #do something } ?> This part works ok. But what I want to happen is if nav = nothing or nav = main then the same if function goes ahead. Hope this makes sense. Thanks in advance Cal

Hi I'm not sure whether this is the right place on the site to post or not, but anyway... I am having trouble updating the Library items in dreamweaver (CS3), it says that it has examined all of the files but hasn't updated any of them. This problem also occurs on an older version of dreamweaver (MX 2004) and on another computer. I've tried a few ways but running out of ideas. Many thanks in advance

Hi, I am converting my news area on my website to rss. I have created a form (with help from people here) to input it into the RSS feed. But I am really struggling on getting the PHP to read from the RSS feed. If anyone can point me in the right direction, I would be greatly appreciated. Cheers

great thanks

hi, i know this question has been asked before. Infact I asked the same question yesterday and then mangaged to fix it, but today I can't get it to work on a different project. I have to change the design to one of my clients website slightly, and I want it to work in both IE and Firefox. It works how I want it in IE but not in Firefox. I have put the screenshots and the CSS code. Thanks in advance Cal body { background-image: url(../images/body_bgound2.gif); background-repeat: repeat-x; background-position: top; background-color: #838193; margin-top: 3px; } #navbar { width: 150px; height: auto; vertical-align: top; float: left; margin: 3px 7px 3px 3px; } #maincontent { text-align: center; width: 750px; border: medium double #999999; background-image: url(../images/bgound.gif); background-repeat: repeat-x; background-position:top; background-color: white; margin: auto; padding: 0 0 0 0; } #pagecontent { width: 570px; float:right; margin: 3px 15px 2px 2px; } #content { width: 570px; height: auto; float: right; }

SOLVED I've adapted the code slightly and it works now. Never mind

hi i am in the process of designing a new website for myself. I reguarly test it in both IE and Firefox. How i want it to appear is in IE but I can't get it to look the same in Firefox. The screenshots and CSS are below. Thanks in advance body { background-color: #CCCCCC; font-family: Arial, Helvetica, sans-serif; color: black; font-size: 16px; margin: auto; } #pagecontents { background-color: white; width: 735px; border: 1px inset gray; margin: auto; } #content { width: 735px; float: right; margin: 2px; }

looks good, but isn't validated (in html or css)

if you're worried about size, do you use photoshop?? If so go file>save for web , i do this for all of my images, and they come out good quality and a small size, ideal!