webguync

January 31, 2011

I need some assistance with an error I get when trying to submit a form to my email address.

the error is this:

Warning: mail() [function.mail]: SMTP server response: 555 syntax error (#5.5.4) in E:\Contact\process.php on line 74

Sorry, unexpected error. Please try again later

the form code is

<form id="form" action="process.php" method="post" name="ContactForm">

   	 <label for="Name">Name</label>
   	 <input type="text" name="name" id="name" />
   	 <label for="email">E-mail</label>
   	 <input type="text" name="email" id="email" />
     <label for="website">Website</label>
   	 <input type="text" name="website" id="website" />
      <label for="message">Message</label>
   	 <textarea class="resizable" name="comment">
</textarea>
    	 <input type="submit" name="submit" id="submit" value="Submit">
    </form>

and the process code

[code=php:0]

<?php

//Retrieve form data. 
//GET - user submitted data using AJAX
//POST - in case user does not support javascript, we'll use POST instead
$name = ($_GET['name']) ? $_GET['name'] : $_POST['name'];
$email = ($_GET['email']) ?$_GET['email'] : $_POST['email'];
$website = ($_GET['website']) ?$_GET['website'] : $_POST['website'];
$comment = ($_GET['comment']) ?$_GET['comment'] : $_POST['comment'];

//flag to indicate which method it uses. If POST set it to 1
if ($_POST) $post=1;

//Simple server side validation for POST data, of course, you should validate the email
if (!$name) $errors[count($errors)] = 'Please enter your name.';
if (!$email) $errors[count($errors)] = 'Please enter your email.'; 
if (!$comment) $errors[count($errors)] = 'Please enter your comment.'; 

//if the errors array is empty, send the mail
if (!$errors) {

//recipient
$to = 'My Name <email@gmail.com>';	
//sender
$from = $name . ' <' . $email . '>';

//subject and the html message
$subject = 'Comment from ' . $name;	
$message = '
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" 
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head></head>
<body>
<table>
	<tr><td>Name</td><td>' . $name . '</td></tr>
	<tr><td>Email</td><td>' . $email . '</td></tr>
	<tr><td>Website</td><td>' . $website . '</td></tr>
	<tr><td>Comment</td><td>' . nl2br($comment) . '</td></tr>
</table>
</body>
</html>';

//send the mail
$result = sendmail($to, $subject, $message, $from);

//if POST was used, display the message straight away
if ($_POST) {
	if ($result) echo 'Thank you! I have received your message.';
	else echo 'Sorry, unexpected error. Please try again later';

//else if GET was used, return the boolean value so that 
//ajax script can react accordingly
//1 means success, 0 means failed
} else {
	echo $result;	
}

//if the errors array has values
} else {
//display the errors message
for ($i=0; $i<count($errors); $i++) echo $errors[$i] . '<br/>';
echo '<a href="form.php">Back</a>';
exit;
}


//Simple mail function with HTML header
function sendmail($to, $subject, $message, $from) {
$headers = "MIME-Version: 1.0" . "\r\n";
$headers .= "Content-type:text/html;charset=iso-8859-1" . "\r\n";
$headers .= 'From: ' . $from . "\r\n";

$result = mail($to,$subject,$message,$headers);

if ($result) return 1;
else return 0;
}

?>

[/code]

January 21, 2011

but still with the loop it will loop the same code over three times, so I guess I can't do it they way I am trying.

January 21, 2011

Hi, I have some code which displays my blog post in a foreach loop, and I want to add some social sharing code(FB like button, share on Twitter etc.), but the problem is the way I have my code now, creates 3 instances of the sharing buttons, but if you like one post, all three are liked and any thing you do affects all of the blog post. How can I fix this?

<?php
include ("includes/includes.php");

$blogPosts = GetBlogPosts();

foreach ($blogPosts as $post)
{
	echo "<div class='post'>";
	echo "<h2>" . $post->title . "</h2>";
	echo "<p class='postnote'>" . $post->post . "</p";
	echo "<span class='footer'>Posted By: " . $post->author . "</span>";
	echo "<span class='footer'>Posted On: " . $post->datePosted . "</span>";
	echo "<span class='footer'>Tags: " . $post->tags . "</span>";
	echo '
<div class="addthis_toolbox addthis_default_style ">
<a class="addthis_button_facebook_like" fb:like:layout="button_count"></a>
<a class="addthis_button_tweet"></a>
<a class="addthis_counter addthis_pill_style"></a>
</div>
<script type="text/javascript">var addthis_config = {"data_track_clickback":true};</script>
<script type="text/javascript" src="http://s7.addthis.com/js/250/addthis_widget.js#username=webguync"></script>';

	echo "</div>";
}


?>

January 19, 2011

this does seem to work when you have several JQuery scripts running on a page, just not with another library. I will search more into how to do that.

January 19, 2011

well as I interpret this is what I need to do.

var $jq = JQuery.noConflict();
$jq(document).ready(function () {
    $jq('img.menu_class').click(function () {
$jq('ul.the_menu').slideToggle('medium');
    });
});

but on a page I have a JQuery slider menu (the code above), the menu doesn't work on the same page as a form which also uses the mootools.js library to submit data.

one or the other works but not both.

January 19, 2011

still a little confused on this. Taking the following code, what would I need to do so that it won't conflict with other JQuery code or other JS libraries.

$(document).ready(function () {
    $('img.menu_class').click(function () {
$('ul.the_menu').slideToggle('medium');
    });
});

January 18, 2011

I got this all figured out. Marking Solved.

January 18, 2011

Hi,

I am trying to get a facebook like button displayed under each of my blog post, but so far I am just getting three like buttons displayed above the blog post instead of below each one. Below is the function code to display my blog post and also where I cam currently placing the FB like button code.

<?php
include 'blogpost.php';

$connection = mysql_connect('localhost', 'username', 'pw') or die ("<p class='error'>Sorry, we were unable to connect to the database server.</p>");
$database = "DBName";
mysql_select_db($database, $connection) or die ("<p class='error'>Sorry, we were unable to connect to the database.</p>");


function GetBlogPosts($inId=null, $inTagId =null)
{
if (!empty($inId))
{
	$query = mysql_query("SELECT * FROM blog_posts WHERE id = " . $inId . " ORDER BY id DESC LIMIT 2"); 
}
else if (!empty($inTagId))
{
	$query = mysql_query("SELECT blog_posts.* FROM blog_post_tags LEFT JOIN (blog_posts) ON (blog_post_tags.postID = blog_posts.id) WHERE blog_post_tags.tagID =" . $tagID . " ORDER BY blog_posts.id DESC");
}
else
{
	$query = mysql_query("SELECT * FROM blog_posts ORDER BY id DESC");
}

$postArray = array();
while ($row = mysql_fetch_assoc($query))
{
	$myPost = new BlogPost($row["id"], $row['title'], $row['post'], $row['postfull'], $row["author_id"], $row['date_posted']);

	array_push($postArray, $myPost);
	echo '<script src="http://connect.facebook.net/en_US/all.js#xfbml=1"></script><fb:like show_faces="true" width="450"></fb:like>';//this is where I am currently implementing the FB Like button
}
return $postArray;
}
?>

January 14, 2011

ok, it looks like I left out part of it thanks!

January 14, 2011

I have a form which is working, but the client wanted to add a recapatcha field so I am implementing that and placed the recaptcha code in the same directory as my form. The recaptcha displays, but you can enter in anything and the form still submits, so it's not doing any good!

Not sure where the problem lies exactly, but was hoping for some help if someone has experienced anything similar.

here is my code

in the html

<li>
<pre> <script> var RecaptchaOptions = {

  theme : 'clean'

}; </script> </pre>
<?php
          require_once('../ContactUs/recaptchalib.php');
          $publickey = "6LdZX8ASAAAAABUejj-bfZey47TTjN6X-EKfKBwy "; // you got this from the signup page
          echo recaptcha_get_html($publickey);
        ?>


                 </li>

the PHP to submit the Post data

<?php

if(!$_POST) exit;

$email = $_POST['email'];

if(!eregi("^[a-z0-9]+([_\\.-][a-z0-9]+)*" ."@"."([a-z0-9]+([\.-][a-z0-9]+)*)+"."\\.[a-z]{2,}"."$",$email )){
$error.="Invalid email address entered";
$errors=1;
}
if($errors==1) echo $error;
else{

$values = array ('name','email','phone','concerning','message','recaptcha_response_field');
$required = array('name','email','message','recaptcha_response_field');

$your_email = "email@email.com";
$email_subject = "New Message from our web site!";
$email_content = "new message:\n";

foreach($values as $value){
  if(in_array($value,$required)){
    if( empty($_POST[$value]) ) { echo 'PLEASE FILL IN REQUIRED FIELDS'; exit; }
    $email_content .= $value.': '.$_POST[$value]."\n";
  }
}

if(mail($your_email,$email_subject,$email_content)) {
echo 'Your message has been successfully sent!'; 
} else {
echo 'ERROR! please try again or use the email address listed above to contact Sandbox-Band';
}
}
?>

the recaptchalib.php file is exactly as I downloaded it from their site.

January 12, 2011

I am having some problems with a page I am working on that utilizes JQuery and MooTools. The JQuery is used on a sliding menu and the Moo Tools is used as a form field checker. i can get one or the other to work, but not both. I did some research at found you can invoke some no conflict code, but what I have tried so far isn't working. My configuration is below.

<?php require('../includes/JQuery.php'); ?>//this is where I have all of my JQuery scripts.
<script type="text/javascript">//this initializes the slider for the menu
       jQuery.noConflict();//trying the no conflict
   $(document).ready(function () {
    $('img.menu_class').click(function () {
$('ul.the_menu').slideToggle('medium');
    });
});
    </script>

<script type="text/javascript" src="../js/mootools.js"></script>

as the code is now, the MooTools feature works, but the JQuery does not. I also tried moving the MootTools call above the JQuery call and that enables the JQuery slide to work, but then the MooTools effect doesn't work.

January 12, 2011

well, I am still debugging the upload tool, but I can echo out the SQL and insert that directly into the MySQL DB through PHPMyAdmin so at least I got that part to work :-)

January 12, 2011

ok thanks, that help me out.

January 12, 2011

I need help echoing out my SQL statement in the following code. This is a data upload application which uploads a tab delemeted txt file into a MySQL table. I am getting a MySQL error.

MySQL Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Group,Title) VALUES ('','','','','' at line 1

so I need to see the SQL to see why it isn't working. I have tried echoing out but not seeing the echo, so must be doing it wrong.

<?php
require_once('databaseClass.php');

if ($_POST) {
foreach($_POST as $key=>$value) {
	if (empty($value)) {
		if ($key == 'fileurl') {
			$errors[] = 'Please provide the URL to the text file containing the data you want to load';
			}
		else if ($key == 'dbname') {
			$errors[] = 'Please provide the name of the database into which you want to load the data';
			}
		else if ($key == 'dbuser') {
			$errors[] = 'Please provide the appropriate Username for the database';
			}
		else if ($key == 'db_pw') {
			$errors[] = 'Please provide the appropriate PW for the database';
			}
		else if ($key == 'dbtable') {
			$errors[] = 'Please provide the database table into which you would like to insert data';
			}
		else if ($key == 'fields') {
			$errors[] = 'Please specify the field names for the table';
			}
		}
	}
if (!isset($errors)) {
	$file = fopen('../'.$_POST['fileurl'], 'r');
	if ($file) {
		$pattern = '/[\n\r\t]/';
		while (!feof($file)) {
			$line = trim(fgets($file));
			$newline = preg_replace($pattern,'\t',$line);
			$lines[] = explode('\t',$newline);
			//echo (fgets($file));
			}
		fclose($file);
		if (count($lines) > 0) {
			$countSuccess = 0;
			$fields = explode(',',$_POST['fields']);
			//$entryCnt = count($tmp);
			$db = new Database('localhost',$_POST['dbuser'],$_POST['db_pw'],$_POST['dbname'],0);
			for ($i=0; $i<count($lines); $i++) {
				$tmp = NULL;
				$sql = 'INSERT INTO '.$_POST['dbtable'].' (';
				for ($k=0; $k<count($lines[$i]); $k++) {
					if (isset($lines[$i][$k]) && $lines[$i][$k] != NULL) {
						$tmp[] = $fields[$k];
						}
					}
				$sql .= implode(',',$tmp);

				$sql .= ') VALUES (';
				for ($j=0; $j<count($lines[$i]); $j++) {
					if (isset($lines[$i][$j]) && $lines[$i][$j] != NULL) {
						if (is_numeric($lines[$i][$j])) {
$sql .= $lines[$i][$j];
echo $sql;//trying to echo out SQL here

}
else {
  $sql .= "'".mysql_real_escape_string($lines[$i][$j])."'";
}
if($j != (count($lines[$i])-1)) {
  $sql .= ',';
}
}
					}
				$sql .= ')';

				$result = $db->query($sql);
				if($result) {
					$countSuccess++;
					}
				//escape $sql;

				}

			$db->close();
			if($countSuccess > 0) {
				header('Location: '.$_SERVER['PHP_SELF'].'?numInserted='.$countSuccess);
				}
			else {
				$errors[] = 'No data was inserted into the database.  Please check all fields again.';
				}
			//print_r($lines);
			}
		else {
			$errors[] = 'No data in designated file';
			}
		}
	else {
		$errors[] = 'Not able to open specified file.  Please check that it is the correct URL to text file.';
		}
	}
}


?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>LOAD DATA alternative</title>
<link href="load.css" rel="stylesheet" type="text/css" />
</head>
<body>
<?php 
if ($_GET) {
echo '<div id="success"><h1>'.$_GET['numInserted'].' rows inserted successfully!</h1></div>';
}
?>
<div id="loadform">
  <h1>Please fill in all fields.</h1>
  <?php if (isset($errors)) {
	echo '<div id="alert"><p>Please correct the following:</p><ul>';
	foreach ($errors as $item) {
		echo "<li>$item</li>";
		}
	echo '</ul></div>';
	}
?>
  <form name="loaddata" method="post" action="<?php $_SERVER['PHP_SELF']; ?>">
    <p>Text file URL (RELATIVE to etsi-dataservices.com/):</p>
    <input name="fileurl" type="text" class="longfield" />
    <br />
    <p>DB Name:</p>
    <input name="dbname" type="text" class="shortfield" />
    <br />
    <p>DB Username:</p>
    <input name="dbuser" type="text" class="shortfield" />
    <br />
    <p>DB PW:</p>
    <input name="db_pw" type="password" class="shortfield"  />
    <br />
    <p>DB Table Name:</p>
    <input name="dbtable" type="text" class="shortfield" />
    <br />
    <p>Comma-delimited list of table's field names (e.g.- name,id,score,etc.), in SAME ORDER as text file data:</p>
    <input name="fields" type="text" class="longfield" />
    <br />
    <br />
    <input name="submit" type="submit" />
  </form>
</div>
</body>
</html>

January 10, 2011

anyone see any thing wrong with my code, or why this isn't working? I am not getting any errors, but not getting the a id="current".

January 9, 2011

yea, I do have a main page. Linking to an individual post would do the trick, but I am not sure how I would do that. I adapted the script from a tutorial I found online.

January 8, 2011

thanks for the reply. I think if I did it the with the code you posted I would have to re-do a lot of what I have, and I was hoping for a simpler solution. I realized it will probably help if I post all of the code, so I am doing that now.

blogpost.php...

<?php

class BlogPost
{

public $id;
public $title;
public $post;
public $author;
public $tags;
public $datePosted;

function __construct($inId=null, $inTitle=null, $inPost=null, $inPostFull=null, $inAuthorId=null, $inDatePosted=null)
{
if (!empty($inId))
{
	$this->id = $inId;
}
if (!empty($inTitle))
{
	$this->title = $inTitle;
}
if (!empty($inPost))
{
	$this->post = $inPost;
}

if (!empty($inDatePosted))
{
	$splitDate = explode("-", $inDatePosted);
	$this->datePosted = $splitDate[1] . "/" . $splitDate[2] . "/" . $splitDate[0];
}

if (!empty($inAuthorId))
{
	$query = mysql_query("SELECT first_name, last_name FROM people WHERE id = " . $inAuthorId);
	$row = mysql_fetch_assoc($query);
	$this->author = $row["first_name"] . " " . $row["last_name"];
}

$postTags = "No Tags";
if (!empty($inId))
{
	$query = mysql_query("SELECT tags.* FROM blog_post_tags LEFT JOIN (tags) ON (blog_post_tags.tag_id = tags.id) WHERE blog_post_tags.blog_post_id = " . $inId);
	$tagArray = array();
	$tagIDArray = array();
	while($row = mysql_fetch_assoc($query))
	{
		array_push($tagArray, $row["name"]);
		array_push($tagIDArray, $row["id"]);
	}
	if (sizeof($tagArray) > 0)
	{
		foreach ($tagArray as $tag)
		{
			if ($postTags == "No Tags")
			{
				$postTags = $tag;
			}
			else
			{
				$postTags = $postTags . ", " . $tag;
			}
		}
	}
}
$this->tags = $postTags;
}

}

?>

includes.php

<?php
include 'blogpost.php';
// Change this info so that it works with your system.
$connection = mysql_connect('localhost', 'username', 'pw') or die ("<p class='error'>Sorry, we were unable to connect to the database server.</p>");
$database = "DBName";
mysql_select_db($database, $connection) or die ("<p class='error'>Sorry, we were unable to connect to the database.</p>");


function GetBlogPosts($inId=null, $inTagId =null)
{
if (!empty($inId))
{
	$query = mysql_query("SELECT * FROM blog_posts WHERE id = " . $inId . " ORDER BY id DESC LIMIT 2"); 
}
else if (!empty($inTagId))
{
	$query = mysql_query("SELECT blog_posts.* FROM blog_post_tags LEFT JOIN (blog_posts) ON (blog_post_tags.postID = blog_posts.id) WHERE blog_post_tags.tagID =" . $tagID . " ORDER BY blog_posts.id DESC");
}
else
{
	$query = mysql_query("SELECT * FROM blog_posts ORDER BY id DESC");
}

$postArray = array();
while ($row = mysql_fetch_assoc($query))
{
	$myPost = new BlogPost($row["id"], $row['title'], $row['post'], $row['postfull'], $row["author_id"], $row['date_posted']);
	array_push($postArray, $myPost);
}
return $postArray;
}
?>

January 8, 2011

any ideas on how I would accomplish what I described?

January 8, 2011

I didn't know of it's existence. Please explain!

January 7, 2011

Hey there, I am trying out some tag cloud code, but something is amiss, as am getting no tags displaying. Using PHP/MYSQL and JQuery.

<?php

//connection information
  $host = "localhost";
  $user = "username";
  $password = "pw";
  $database = "DBName";

//make connection
  $server = mysql_connect($host, $user, $password);
  $connection = mysql_select_db($database, $server);

//query the database
  $query = mysql_query("SELECT * FROM tags");


//start json object
$json = "({ tags:["; 

//loop through and return results
  for ($x = 0; $x < mysql_num_rows($query); $x++) {
    $row = mysql_fetch_assoc($query);

	//continue json object
    $json .= "{tag:'" . $row["tag"] . "',freq:'" . $row["frequency"] . "'}";

	//add comma if not last row, closing brackets if is
	if ($x < mysql_num_rows($query) -1)
		$json .= ",";
	else
		$json .= "]})";
  }

//return JSON with GET for JSONP callback
$response = $_GET["callback"] . $json;
echo $response;

//close connection
mysql_close($server);

?>

and the JS

<script type="text/javascript">
		$(function() {

			//get tag feed
			$.getJSON("/tagcloud.php?callback=?", function(data) {

				//create list for tag links
				$("<ul>").attr("id", "tagList").appendTo("#tagCloud");

				//create tags
				$.each(data.tags, function(i, val) {

					//create item
					var li = $("<li>");

					//create link
					$("<a>").text(val.tag).attr({title:"See all pages tagged with " + val.tag, href:"http://localhost/tags/" + val.tag + ".html"}).appendTo(li);

					//set tag size
					li.children().css("fontSize", (val.freq / 10 < 1) ? val.freq / 10 + 1 + "em": (val.freq / 10 > 2) ? "2em" : val.freq / 10 + "em");

					//add to list
					li.appendTo("#tagList");

				});
			});
		});
	</script>

when i turn on error reporting I get a lot of undefined index notices for tag and frequency so not sure if that is causing the problem or not.

January 7, 2011

Hi, I have a blog page I am working on and I am trying to make some enhancements that I need some help with. In MySQL I have a table with id, title and post. In my page display I want to enable the user to click on the title and display a post on it's own so the URL would look like www.mysite.com/blog/?id=1 or something like that. Here is the PHP function to display the post from MySQL. all on one page.

function GetBlogPosts($inId=null, $inTagId =null)
{
if (!empty($inId))
{
	$query = mysql_query("SELECT * FROM blog_posts WHERE id = " . $inId . " ORDER BY id DESC LIMIT 2"); 
}
else if (!empty($inTagId))
{
	$query = mysql_query("SELECT blog_posts.* FROM blog_post_tags LEFT JOIN (blog_posts) ON (blog_post_tags.postID = blog_posts.id) WHERE blog_post_tags.tagID =" . $tagID . " ORDER BY blog_posts.id DESC");
}
else
{
	$query = mysql_query("SELECT * FROM blog_posts ORDER BY id DESC");
}

$postArray = array();
while ($row = mysql_fetch_assoc($query))
{
	$myPost = new BlogPost($row["id"], $row['title'], $row['post'], $row['postfull'], $row["author_id"], $row['date_posted']);
	array_push($postArray, $myPost);
}
return $postArray;
}

January 7, 2011

Hi, I have some code that I think worked at one point, but now it doesn't. I have a side navigation menu which I have set as an include. I want to change CSS styling to a current state to whatever page you are current on. For instance the portfolio link would look like this.

<li><a id="current" href="../Portfolio/" title="Visit my Portfolio">Portfolio</a></li>

Both the page I am trying to set this on and my includes are in separate directories, so I am not sure if that is messing things up, but the id="current is not being set with what I currently have as my code.

Here is my current code.

<?php
$menu = <<< MENU
<div id="SideMenu">
<div id="button">
<img src="../images/NavButton.png" width="184" height="32" class="menu_class" />
<ul class="the_menu">
<li><a href="../index.php" title="take me home">Home</a></li>
<li><a  href="../Portfolio/" title="Visit my Portfolio">Portfolio</a></li>
<li><a href="../blog/" title="See what I have to say">Blog</a></li>
<li><a href="../Contact/" title="Get in Touch with me">Contact</a></li>
</ul>
</div><!--end button div-->
</div><!--end SideMenu div-->
MENU;
$lines = split("\n", $menu);
foreach ($lines as $line) {
$current = false;
preg_match('/href="([^"]+)"/', $line, $url);
if (substr($_SERVER["REQUEST_URI"], 0, 5) == substr($url[1], 0, 5)) {
$line = str_replace('<a h', '<a id="current" h', $line);
}
echo $line."\n";
}

?>

any ideas?

January 5, 2011

ok thanks. Looks like it is version 5.0.45

January 5, 2011

not for certain this is a PHP issue, but on every page of my site, at the bottom, this error displays. Doesn't affect any of the code execution as far as I can tell, but it's annoying. Anyone else seen this?

Error in my_thread_global_end(): 1 threads didn't exit

January 5, 2011

yes, it works now.

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webguync

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