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andrew6607

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Posts posted by andrew6607

    CSS Menu Problem

    in CSS Help

    Posted

    Hello,

    I am currently trying to design my website with a dropdown menu. But, i am running into a slight problem with the allignment. I want the menu to allign to the center, but i can't get it to do that for some reason. I'm sure it will be a simple fix. Any help is welcome!

     

    Code is Below:

    style.css

    @charset "utf-8";
/* CSS Document */
html body{
margin:0;
padding:0;
vertical-align:middle;
background-color:#CCC;
}
#header{
margin:auto;
width:800px;
}
#navMenu{
margin:0;
padding:0;
}
#navMenu ul{
margin:0;
padding:0;
line-height:30px;
}
#navMenu li{
margin:0;
padding:0;
list-style:none;
float:left;
position:relative;
background:url(redBG.png);
}
#navMenu ul li a{
text-align:center;
font-family:"MS Serif", "New York", serif;
text-decoration:none;
height:30px;
width:100px;
display:block;
color:#FFF;
}
#navMenu ul ul{
position:absolute;
visibility:hidden;
top:30px;
}
#navMenu ul li:hover ul{
visibility:visible;
background:#000;
}
#navMenu li:hover{
background:url(redBGOver.png);
color:#FFF;
}
#navMenu ul li:hover ul li a:hover{
background:#CCC;
color:#000;	
}
#navMenu a:hover{
color:#000;	
}
#navMenu ul li:hover ul li a{
background:#000;
border:1px solid #FFF;
}

    index.html

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<link rel="stylesheet" type="text/css" href="css/style.css" />
<title>Andrew Erhardt - Blog and Portfolio</title>
</head>

<body>
<div id="header">
<img src="images/header.png" />
</div>
<div id="navMenu">
<ul>
        	<li><a href="#">Home</a>
            	<ul>
                </ul><!-- End Inner UL Tag -->
            </li><!-- End Main LI Tag -->
            <li><a href="#">About Me</a>
            	<ul>
                </ul><!-- End Inner UL Tag -->
            </li><!-- End Main LI Tag -->
             <li><a href="#">Portfolio</a>
            	<ul>
                <li><a href="#">Websites</a></li>
                <li><a href="#">Photos</a></li>
                <li><a href="#">Programs</a></li>
                </ul><!-- End Inner UL Tag -->
            </li><!-- End Main LI Tag -->
            <li><a href="#">Live Show</a>
            	<ul>
                <li><a href="#">Show Page</a></li>
                <li><a href="#">Pre-Recorded</a></li>
                <li><a href="#">Chat Rules</a></li>
                </ul><!-- End Inner UL Tag -->
            </li><!-- End Main LI Tag -->
        </ul><!-- End Main UL Tag -->
</div>
</body>
</html>

    A screenshot of the website i'm working on, is attached, to help give you a better idea of what i'm trying to explain.

     

     

     

    [attachment deleted by admin]

    Student Webdesigner

    in Archived Job Offerings

    Posted

    Hello,

    I am looking for some projects to help sharpen my skills.

     

    • Have Experience With Working In Photoshop
    • Can Create Simple Php Scripts

    I work better in groups. I will do this for free. If You are interested please Email me at erhardtandrew (at) hotmail.com or You can contact me via skype (fsphceo) Or MSN erhardtandrew (at) hotmail.com Or PM Me

     

    Thanks!

    [SOLVED] MySQL Help

    in PHP Coding Help

    Posted

    Hello,

    I am trying to set up a System For A Virtual Airline. When someone enters the amount of hours they did on a flight and then it ads it to the currents hours in the database. Example.. They currently have 200 Hours logged. And They submit a report with 2.8 Hours. So then the table would be updated and then say they have 202.8 Hours.

     

    Thanks!

    Need Help!!

    in HTML Help

    Posted

    Hello there,

    I am currently designing a site template using tables. But i keep running into a problem. When i enter text it all go's in one line. Insted of breaking. Look at this link for what im talking about. http://i268.photobucket.com/albums/jj36/pilotman5545/help.png

     

    See what i mean. it resized Please Help!!

     

    Here is the HTML Code!

     

    <table border="0" align="center" height="5" bgcolor="#0000FF">
     <tr>
        <td width="1000" height="5"></td>
     </tr>
</table>
<table border="0" align="center" cellpadding="0" cellspacing="0" bgcolor="0000FF">
     <tr>
        <td width="25" height="25" background="images/top_left_corner.jpg"></td>
        <td width="600" height="25" background="images/top.jpg"></td>
        <td width="25" height="25" background="images/top_right_corner.jpg"></td>
        <td width="25" bgcolor="#0000FF"></td>
        <td width="25" height="25" background="images/top_left_corner.jpg"></td>
        <td width="200" height="25" background="images/top.jpg"></td>
        <td width="25" height="25" background="images/top_right_corner.jpg"></td>
     </tr>
     <tr>
        <td width="25" height="100" background="images/left.jpg"></td>
        <td width="600" height="100"></td>
        <td width="25" height="100" background="images/right.jpg"></td>
        <td width="25" bgcolor="#0000FF"></td>
        <td width="25" height="100" background="images/left.jpg"></td>
        <td width="200" height="100"></td>
        <td width="25" height="100" background="images/right.jpg"></td>
     </tr>
     <tr>
        <td width="25" height="25" background="images/bottom_left_corner.jpg"></td>
        <td width="600" height="25" background="images/bottom.jpg"></td>
        <td width="25" height="25" background="images/bottom_right_corner.jpg"></td>
        <td width="25" bgcolor="#0000FF"></td>
        <td width="25" height="25" background="images/bottom_left_corner.jpg"></td>
        <td width="100" height="25" background="images/bottom.jpg"></td>
        <td width="25" height="25" background="images/bottom_right_corner.jpg"></td>
     </tr>
</table>
<table border="0" align="center" width="925" height="5">
     <tr>
        <td width="1000" height="5"></td>
     </tr>
</table>
<table border="0" align="center" cellpadding="0" cellspacing="0" bgcolor="0000FF">
     <tr>
        <td width="25" height="25" background="images/top_left_corner.jpg"></td>
        <td width="600" height="25" background="images/top.jpg"></td>
        <td width="25" height="25" background="images/top_right_corner.jpg"></td>
        <td width="25" bgcolor="#0000FF"></td>
        <td width="25" height="25" background="images/top_left_corner.jpg"></td>
        <td width="200" height="25" background="images/top.jpg"></td>
        <td width="25" height="25" background="images/top_right_corner.jpg"></td>
     </tr>
     <tr>
        <td width="25" height="100" background="images/left.jpg"></td>
        <td width="600" height="100"></td>
        <td width="25" height="100" background="images/right.jpg"></td>
        <td width="25" bgcolor="#0000FF"></td>
        <td width="25" height="100" background="images/left.jpg"></td>
        <td width="200" height="100"></td>
        <td width="25" height="100" background="images/right.jpg"></td>
     </tr>
     <tr>
        <td width="25" height="25" background="images/bottom_left_corner.jpg"></td>
        <td width="600" height="25" background="images/bottom.jpg"></td>
        <td width="25" height="25" background="images/bottom_right_corner.jpg"></td>
        <td width="25" bgcolor="#0000FF"></td>
        <td width="25" height="25" background="images/bottom_left_corner.jpg"></td>
        <td width="100" height="25" background="images/bottom.jpg"></td>
        <td width="25" height="25" background="images/bottom_right_corner.jpg"></td>
     </tr>
</table>

    Getting Data From MySQL

    in PHP Coding Help

    Posted

    Hello,

    I can not figure out how to fix this problem. I am trying to get data from mysql. I have 3 records in the table but it will only display one. Below is the code.

     

    <?php
$Host = "localhost";
$User = "root";
$Password = "******";
$DBName = "website";
$TableName = "members";

$Conn = mysql_connect ($Host, $User, $Password) or die ( "MySQL Error!" );

//now lets do the query
$Query = "SELECT * from $TableName";
$Result = mysql_db_query ($DBName, $Query, $Conn) or die ( "MySQL Error 2!" );

$data=mysql_fetch_assoc($Result);


?>
<table border="1" align="center">
     <tr>  
        <td>First Name</td><td>Last Name</td><td>Email</td><td>User Level</td><td>Delete</td><td>Edit User</td>
     </tr>
     <tr>
        <td><?php echo $data['fname']; ?></td><td><?php echo $data['lname']; ?></td><td><?php echo $data['email']; ?></td><td><?php echo $data['level']; ?></td><td><a href="delete.php?fname=<?php echo $data['fname']; ?>">Delete User</a></td><td><a href="edit.php?fname=<?php echo $data['fname']; ?>">Edit User</a></td>
     </tr>
</table>

    Thank you ahead of time!

    [SOLVED] Cant Get Info From MySQL

    in PHP Coding Help

    Posted

    Cant Get This To Get Info From The Database!!

     

    <?php
$Host = "localhost";
$User = "****";
$Password = "*******";
$DBName = "news";
$TableName = "news";

$Conn = mysql_connect ($Host, $User, $Password) or die ( "MySQL Error!" );

//now lets do the query
$Query = "SELECT * from $TableName";
$Result = mysql_db_query ($DBName, $Query, $Conn) or die ( "MySQL Error 2!" );

print ("$Result[content]");

?>

     

    There Are NO Errors Displayed On The Page!

    [SOLVED] SQL Syntax Error

    in PHP Coding Help

    Posted

    Hello,

     

    I have been Spending Almost A Hour Trying to Figure This Out. I have solved it before but i cant figure out how i did it. Please HELP!! Here is the error it gives:

     

    MySQL Said: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '*INTO new_members ( fname, lname, email, username, password ) values( 'Andre' at line 1

     

    Now Here Is The PHP CODE:

     

    <?php

include( 'includes/config.php' );
//Get Data From Forum
$fname = $_POST['fname'];
$lname = $_POST['lname'];
$email = $_POST['email'];
$username = $_POST['username'];
$password = $_POST['password'];
$cpassword = $_POST['cpassword'];

//Validate Info

if( $fname == false || $lname == false || $email == false || $username == false || $password == false ) {
echo "Please Fill Out All The Feilds!!";
}

if( $password == $cpassword ) {
$link = mysql_connect( $db_host, $db_username, $db_password );
   if( ! $link ) {
    die ( "MySQL Said: ".mysql_error() );
}
$db = mysql_select_db( $db_database, $link );
  if( ! $db ) {
   die ("MySQL Said: ".mysql_error() );
   }
$query = "INSERT *INTO new_members ( fname, lname, email, username, password )
   values( '$fname', '$lname', '$email', '$username', '$password' )";
mysql_query( $query, $link )
  or die ( "MySQL Said: ".mysql_error() );
  
mysql_close( $link );
}else{
echo "Your Passwords Dont Match";
} 
?>

     

    Thanks!!

     

    Andrew E

    [SOLVED] T_STRING Error

    in PHP Coding Help

    Posted

    Ok it fixed that line. Now I cant figure out. Whats its yelliing about now!

     

    or die( "MySQL Said: ". mysql_error() );

    Parse error: syntax error, unexpected ';' in C:\Users\Andrew Erhardt\Projects\Web\membersystem\validate.php on line 5

     

    >:( >:(>:( >:(

    [SOLVED] T_STRING Error

    in PHP Coding Help

    Posted

    Hello I cant Figure Out What is Going On here. Below is my code. I am Writing a Login System.

     

    <?php
require_once('includes/config.php');

mysql_connect( $db_host, $db_username, $db_password
            or die( "MySQL Said: ". mysql_error() )

mysql_select_db( $db_database )
              or die( "MySQL Said: ". mysql_error() );

$username = $_POST['username'];
$password = $_POST['password'];

$sql = "SELECT * FROM $table WHERE username='$username' and password='$password'";
$result = mysql_query( $sql );


$count = mysql_num_rows( $result );

if( $count==1){
session_register('username');
session_register('password');
header( 'location:memberarea.php' );
}else{

echo 'Sorry We Were Not Able to Log you in. Either Your Username or Password is wrong. Or Their is a major error in this system';

}
?>

     

    And the Error its gives is

    Parse error: syntax error, unexpected T_STRING in C:\Users\Andrew Erhardt\Projects\Web\membersystem\validate.php on line 7

     

    ??? ??? ??? ???

     

    Thanks Ahead Of Time!!

    [SOLVED] Another SQL syntax Error!!

    in PHP Coding Help

    Posted

    PHP Version: 5

    Mysql Version 5

     

    Error: INSERT error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' , , , , , )' at line 2

     

    Here is the code im using.

    <?php
$fname = $_POST['fname'];
$lname = $_POST['lname'];
$email = $_POST['email'];
$positon = $_POST['positon'];
$exp = $_POST['exp'];
$username = $_POST['username'];
$password = $_POST['password'];
$user = "root";
$pass = "##########";
$db = "#########";
$table = "#########";
$link = mysql_connect( "localhost", $user, $pass );
if ( ! $link ) {
  die( "Couldn't connect to the MySQL Server: ".mysql_error() );
}

mysql_select_db( $db )
  or die ( "Couldn't open $db: ".mysql_error() );
  
  
$query = "INSERT INTO staff( fname, lname, email, positon, exp, username, password )
   values( $fname, $lname, $email, $positon, $exp, $username, $password )"; 
   mysql_query( $query, $link )
     or die ( "INSERT error: ".mysql_error() );

mysql_close( $link );
?>

    [SOLVED] Sessions

    in PHP Coding Help

    Posted

    Nope I dont know whats going on ill send ya the code of the script

     

    <?php

    $usernamea=$_POST['username'];

    $title=$usernamea;

    ?>

    <title>

    Welcome <?php echo $title; ?>!

    </title>

    <?php

    include_once("includes/config.php");

    mysql_select_db($data,$connect) or die ("Cannot Connect to Database Server");

    $username=$_POST['username'];

    $password=$_POST['password'];

    // Connections

    $sql="SELECT * FROM users WHERE username='$username' && password='$password'";

    $query=mysql_query($sql);

    $row=mysql_fetch_assoc($query);

    $totalRow=mysql_num_rows($query);

    // If username is correct

    if ($username = $row['username']) {

    // If password is correct

    if ($password = $row['password']) {

    ?>

    <?php

    session_start();

    session_register('user_id');

    // store session data

    $_SESSION['username'];

    //retrieve session data

    echo "Welcome". $_SESSION['username'];

    ?>

     

    <?php

    } else {

    echo "Password is Incorrect! <a href='index.php'>Try Again</a>";

    }

    } else {

    echo "Wrong Password or the User does not exist! <a href='index.php'>Try Again</a>";

    }

    mysql_free_result($query);

    ?>

    [SOLVED] Sessions

    in PHP Coding Help

    Posted

    Hello im getting a error with sessions here it is

     

    Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at C:\xampp\htdocs\newsite\member.php:6) in C:\xampp\htdocs\newsite\member.php on line 24

     

    Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at C:\xampp\htdocs\newsite\member.php:6) in C:\xampp\htdocs\newsite\member.php on line 24

    Welcome

     

    And here is the code im using

     

    <?php

    session_start();

     

    // store session data

    $_SESSION['username'];

    ?>

    <?php

    //retrieve session data

    echo "Welcome". $_SESSION['username'];

    ?>

     

    PLEASE HELP!!

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