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Hi, Is there any php script which can open doc file. edit it and save into it. is yes please provide script link. Thanks

Hi, I've dynamic form. all div and fields are dynamic. so hard to ignore them. sample code is as follow <form> <select name="txtbrandCategory'.$i.'[]" id="txtbrandCategory'.$i.'" class="branddropdowncss required" onchange="showfeildsperbrndCat(this, \''.$i.'\')" id="brandcatslctbox"> <option value=""> -- select -- </option> ----------------------- ------------------------ ---------------------------- </select> <?php for(i=1; i<=10; i++) { ?> <div id="divid23<?php echo $i; ?>" style="display:none"><input type="text" name=txtname[] /></div> <div id="divid42<?php echo $i; ?>" style="display:none"><input type="text" name=txtphone[] /></div> <div id="divid39<?php echo $i; ?>" style="display:none"><input type="text" name=txtemail[] /></div> <?php } ?> </form> on select box change one of the div will show up. but when i submit a form if return all dives data. so i want to get only that div data which is display block. hope you understand now. thanks

Hi, I've have a form with some hidden DIVs. all DIVs has some feilds..... i want that only display: block div should be a part of my form. hidden div content should not me a part of my form. but when i submit a form and get values it gives all values. even container is hidden or block. would any one help me on this??? Thanks

Hi, is there one know if there is any script of PHP to convert pdf to images? I want to use flipbook on website. and i can only found a script of flipbook that loads only images. can't find any flipbook to load pdf file. so i decided to convert pdf to images and then load images to flipbook. I don't want to use ghostscript and imagemagic. so if anyone knows please guide. Thanks

hi, Thanks for prompt response and guide. I installed oscommerce on my local server. it is running fine. now i want to login oscommerce with my manual code pasted before. i place a file one folder up of oscommerce folder. so my login file path is c:\wamp\www\cart\login.php and my oscommerce path is c:\wamp\www\cart\oscommerce\index.php i want to log into oscommerce in my login.php file. after login it'll take me two oscommerce folder. i copy past all the code from cart\oscommerce\login.php into cart\login.php made some modification and try to run. it didn't give any error. says username password is correct and redirect to oscommerce\login.php it seems that there is some session problem. even though my code is working fine it require again login access. can you guide me how can i do that? Thanks

Hi, I'm trying to login oscommerce with manual code. but unable to do that. all entries going to database but don't understand what is missing??? here is my code $email_address = $_REQUEST['txtemail']; $password = $_REQUEST['password']; $check_customer_query = mysql_query("select customers_id, customers_firstname, customers_password, customers_email_address, customers_default_address_id from customers where customers_email_address = '" . $email_address . "'"); if (mysql_num_rows($check_customer_query)> 0) { $check_customer = mysql_fetch_assoc($check_customer_query); if (!tep_validate_password($password, $check_customer['customers_password'])) { echo "password not found."; }else { tep_session_recreate(); $check_country_query = mysql_query("select entry_country_id, entry_zone_id from address_book where customers_id = '" . (int)$check_customer['customers_id'] . "' and address_book_id = '" . (int)$check_customer['customers_default_address_id'] . "'"); $check_country = mysql_fetch_array($check_country_query); $customer_id = $check_customer['customers_id']; $customer_default_address_id = $check_customer['customers_default_address_id']; $customer_first_name = $check_customer['customers_firstname']; $customer_country_id = $check_country['entry_country_id']; $customer_zone_id = $check_country['entry_zone_id']; tep_session_register('customer_id'); tep_session_register('customer_default_address_id'); tep_session_register('customer_first_name'); tep_session_register('customer_country_id'); tep_session_register('customer_zone_id'); mysql_query("update customers_info set customers_info_date_of_last_logon = now(), customers_info_number_of_logons = customers_info_number_of_logons+1 where customers_info_id = '" . (int)$customer_id . "'"); anyone have any idea about?

Hi, I've a simple form. and want to submit using jquery ajax. it is doing nothing. can anyone help me on this. My code is : <script type="text/javascript"> $(document).ready(function() { $("#askexpfrm").submit(function(){ $.ajax({ url: 'submitAskTheExpert.php', type:'POST', data:'action=yes&', success: function(html) { alert('sani'); } }); return false; }); }); <form action="/" method="post" id="askexpfrm"> <label>Name:</label><br /><input type="text" class="asktheexpcss" name="txtname" /> </form> it is very simple form. it doesn't showing any alert. doing nothing... please guide what is wrong in it??

Hi guys, I'm trying put scroll color using AJAX. but failed. I've a div like this: <div class="scroll-pane" id="SLContainer"></div> I'm filling the dive using AJAX. On page load if i put color scroll code like below. it works fine. $(document).ready( function($) { $('.scroll-pane').jScrollPane(); } ); but when i use same function to fill div. and put same color scroll code in ajax function. it doesn't color the scroll. e.g function ajax() { ... ......... if (http_request.status == 200) { $('.scroll-pane').jScrollPane(); } .... .. } even i tried this: function ajax() { ... ......... if (http_request.status == 200) { $(document).ready( function($) { $('.scroll-pane').jScrollPane(); }); } .... .. } but no luck. can anyone guide me please??? Thanks

Thanks guys, It is really helpful and solved my problem. i really appreciate your all assistance. Thanks again.

Hi, Thanks for the reply. Yes, actually view table is like a relation table. many things could relate to many other things. ok forget it. can we get two specific id with one query ? means i've 10 record in table. I want to get 4 and 6 record only suppose i query for it like this select * from tbl_profile p where 1=1 and p.pro_id = '33' and p.pro_id = '56' but this query doesn't show the record. my requirement is not two use 'or' Please help on this Thanks

Hi, Can we use 'if condition' in query before where clause??? or is there any alternate way to do following thing? SCENARIO: ------------- i've two tables __________ tbl_profile ---------------- pro_id pro_name __________ _________ tbl_view -------------- v_id v_one v_two v_detail __________ tables has following content tbl_profile -------------------------------- pro_id pro_name 1 sani ...... ..... .. tbl_view v_id v_one v_two v_detail 1 2 3 testing detail 2 1 3 testing detail A 3 2 1 testing detail B 4 6 4 testing detail 5 7 5 testing detail profile id could come as foreign id in table view in two fields v_one and v_two. as you can c in above table. id '1' is as foreign in v_one and v_two against v_id 2 and 3 respectively. so i want to query that if profile id is found in v_one or v_two it should join. so i'm trying following query select * from tb_profile p left join tbl_countries c on (p.p_country = c.countries_id) if((select * from tbl_view where v_one = '1') > 0) left join tbl_view v i on (p.pro_id = v.v_one) if((select * from tbl_view where v_two = '1') > 0) left join tbl_view v i on (p.pro_id = v.v_two) is it a fine way to or we could different query for that? Please help Looking forward Thanks

how strang!!!!!!, no one knows how to upload image using jquery and ajax with page refresh!!!!!! dis......................

ok .leave it. anyone have simple code to upload image and some text field submission with out page refresh?? if have please post here. i've struck with it now. Thanks

Thanks for reply, Here is my full code <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> <script type="text/javascript" src="topnavscript/jquery.form.js"></script> <script> function savebasicinfo(val) { $(document).ready( function() { $('#basicinfofrm').submit(function () { $.ajax({ url: 'process.php', type:'POST', data:'action=yes', success: function(html) { alert(html); } }); }); } ); return false; } </script> <form method=" post" action="" onsubmit="return savebasicinfo(this);" enctype="multipart/form-data" id="basicinfofrm"> <input type="hidden" name="prnw_id" value="<?php echo $basicinfo['prnw_id']; ?>" /> <table width="100%" cellpadding="10" cellspacing="10"> <tr><td>Name</td><td><input type="text" name="prnw_name" class="jointxtinputcss" value="<?php echo $network->showoneoftwo($basicinfo['prnw_name'], 'Dummy Name'); ?>" /></td></tr> <tr><td>Email</td><td><input type="text" name="prnw_email" class="jointxtinputcss" value="<?php echo $network->showoneoftwo($basicinfo['prnw_email'], 'email@transformbody.biz'); ?>" /></td></tr> <tr><td>Phone</td><td><input type="text" name="prnw_phone" class="jointxtinputcss" value="<?php echo $network->showoneoftwo($basicinfo['prnw_phone'], '4535353453'); ?>" /></td></tr> <tr><td>City</td><td><input type="text" name="prnw_city" class="jointxtinputcss" value="<?php echo $network->showoneoftwo($basicinfo['prnw_city'], 'Dubai'); ?>" /></td></tr> <tr><td>Country</td><td> <?php echo $network->selectbox('tbl_countries', 'countries_id', 'countries_name', 'name ="prnw_country" class="joinslctinputcss"', $basicinfo['prnw_country']); ?> </td></tr> <tr><td>Date of Birth</td><td><input type="text" name="prnw_dateofbirth" class="jointxtinputcss" <?php echo $network->showoneoftwo($basicinfo['prnw_dateofbirth'], '2012-02-02'); ?> /></td></tr> <tr><td>Gender</td><td><?php echo $network->selectbox('tbl_job_gender', 'gen_id', 'gen_name', 'name ="prnw_gender" class="joinslctinputcss"', $basicinfo['prnw_gender']); ?></td></tr> <tr><td>Image</td><td><input type="file" name="prnw_image" class="jointxtinputcss" /><br> <img src="images/<?php echo $network->showoneoftwo($basicinfo['prnw_image'], 'dummy.png'); ?>" width="120" alt="sani" /> <input type="hidden" name="txtoldimage" value="<?php echo $network->showoneoftwo($basicinfo['prnw_image'], 'dummy.png'); ?>" /> </td></tr> <tr><td>Address</td><td><textarea name="prnw_address" class="jointxtinputcss" ><?php echo $network->showoneoftwo($basicinfo['prnw_address'], 'Main Bulevard, Albersha 1, Dubai, UAE'); ?></textarea></td></tr> <tr><td> </td><td><input type="submit" name="txtbasicinfosubmit" value="Save" class="joinsubmitcss" /></td></tr> </table> </form> and my process.php file has following code <?php $prnw_id = ''; $prnw_name = ''; $prnw_email = ''; $prnw_phone = ''; $prnw_country = ''; $prnw_city = ''; $prnw_dateofbirth = ''; $prnw_gender = '1'; $prnw_address = ''; $prnw_image = ''; $txtoldimage = ''; if(!empty($_FILES["prnw_image"]["name"])) { $accept = array('jpg','png','gif','bmp'); $extension = substr($_FILES['prnw_image']['name'],strrpos($_FILES['prnw_image']['name'],'.')+1); if(in_array($extension,$accept)) { $image->load($_FILES["prnw_image"]["tmp_name"]); $image->resizeToWidth(120); $random_digit = md5(rand(0000,9999)); $filename = $random_digit.$_FILES["prnw_image"]["name"]; $image->save("../../../network/images/profile/thumb/" . $filename); $prnw_image = $filename; } }else { $prnw_image = $txtoldimage;} print_r($_POST); ?> following error i'm getting: <br /> <b>Notice</b>: Undefined index: prnw_image in <b>C:\Program Files\VertrigoServ\www\demo\process.php</b> on line <b>491</b><br /> hope everything is clear now. please guide...

hi, Thanks for the reply, I'm using two files [/code] <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> <script type="text/javascript" src="topnavscript/jquery.form.js"></script> [/code] one is for jquery and one is for ajax form. the problem is . form is being submit. but it give error for file that index is undefine. even i've given encryption too. like this <form method=" post" action="" onsubmit="return savebasicinfo(this);" enctype="multipart/form-data" id="basicinfofrm"> Please guide thansk