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Eggzorcist

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Posts posted by Eggzorcist

    [SOLVED] Using GET isnt working.

    in Javascript Help

    Posted

    here's the PHP code.

     

    <?php
$dbhost = "localhost";
$dbuser = "root";
$dbpass = "";
$dbname = "tgj4u";


mysql_connect($dbhost, $dbuser, $dbpass);
mysql_select_db($dbname) or die(mysql_error());
$id =  $_GET['id'];
$id = mysql_real_escape_string($id);
$query = "SELECT * FROM maildata WHERE id = '$id'";
$qry_result = mysql_query($query);



if (mysql_num_rows($qry_result)){


while($info = mysql_fetch_assoc($qry_result)){

echo "Sent by: " . $info['sender'] . "<br>";	
echo "Recipient: " . $info['recipient'] . "<br>";	
echo "Departed: " . $info['depart'] . "<br>";
echo "Satus: " . $info['depart'] . "<br>";
echo "Current Location: " . $info['currentlocation'] . "<br>";
echo "Arrival Location: " . $info['finallocation'] . "<br>";
echo "Expected on: " . $info['expected'] . "<br>";

}
}

else
{
   echo "<p>No data was found with that ID.</p>\n";
}





?>

     

    I've tried with both mizila firefox and internet explorer.

    [SOLVED] Using GET isnt working.

    in Javascript Help

    Posted

    Alright, heres my JS code. All works but one thing. It seems like my PHP code isn't receiving any GET information but I'm having trouble seeing how it isnt.

     

     

    // JavaScript Document

var xmlhttp;

function showUser(str)
{
xmlhttp=GetXmlHttpObject();
if (xmlhttp==null)
  {
  alert ("Browser does not support HTTP Request");
  return;
  }
var url="trackeractions.php";
url=url+"?id="+str;
//url=url+"&sid="+Math.random();
xmlhttp.onreadystatechange=stateChanged;
xmlhttp.open("GET",url,true);
xmlhttp.send(null);
}

function stateChanged()
{
if (xmlhttp.readyState==4)
{
document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
}
}

function GetXmlHttpObject()
{
if (window.XMLHttpRequest)
  {
  // code for IE7+, Firefox, Chrome, Opera, Safari
  return new XMLHttpRequest();
  }
if (window.ActiveXObject)
  {
  // code for IE6, IE5
  return new ActiveXObject("Microsoft.XMLHTTP");
  }
return null;
}

     

     

     

    I'm not that good in AJAX. This is for my media design class.

     

     

    Thanks

    easy sql query issue

    in PHP Coding Help

    Posted

    Here is my code:

     

    <?php
$dbhost = "localhost";
$dbuser = "root";
$dbpass = "";
$dbname = "tgj4u";


mysql_connect($dbhost, $dbuser, $dbpass);

mysql_select_db($dbname) or die(mysql_error());
$id = $_GET['id'];
$id = mysql_real_escape_string($id);
$query = "SELECT * FROM maildata WHERE id = '$id'";



if ($qry_result = mysql_query($query) or die(mysql_error())){


while($info = mysql_fetch_array($qry_result)){

echo "Sent by: " . $info['sender'] . "<br>";	
echo "Recipient: " . $info['recipient'] . "<br>";	
echo "Departed: " . $info['depart'] . "<br>";
echo "Satus: " . $info['depart'] . "<br>";
echo "Current Location: " . $info['currentlocation'] . "<br>";
echo "Arrival Location: " . $info['finallocation'] . "<br>";
echo "Expected on: " . $info['expected'] . "<br>";

}


}



?>

     

     

    What I am trying to do is from the ID get information in maildata, but for some reason the while command isnt working and if I dont have while all I get from the echos is the text not the variables.

     

    Also if I were to add that if it doesnthave that ID to echo out something how could I do tht?

     

     

    thanks

    [SOLVED] Query and Display

    in Javascript Help

    Posted

    I downloaded firebug but coudnt seem to find the mistake.

     

    So far all its doing is refreshing the page and adding the ?id=55583&ID=Track to the url

     

    I'm unsure why ID=Track and I am not seeing any echo thats within my php document for some reason.

    [SOLVED] Query and Display

    in Javascript Help

    Posted

    I don't get any visual error but when I click submit it does "error on page" at the bottom info of the browser where it normally says the status of that loads the page or "done" status.

     

     

    The PHP does not yet work fully independantly, however, it does show information independantly just not the query information but everything else does.

    [SOLVED] Query and Display

    in Javascript Help

    Posted

    I'm trying to make a form which will using ajax get information through php and sql and will display that information Ajax style but I'm currently getting an error.

     

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<LINK REL=stylesheet HREF="stylesheet.css" TYPE="text/css">
</head>

<body>


<script language="javascript" type="text/javascript">

<!-- 
//Browser Support Code
function ajaxFunction(){
var ajaxRequest;  
try{
	ajaxRequest = new XMLHttpRequest();
} catch (e){

	try{
		ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
	} catch (e) {
		try{
			ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");

		} catch (e){

			alert("Your browser broke!");
			return false;
		}
	}
}

ajaxRequest.onreadystatechange = function(){
	if(ajaxRequest.readyState == 1){
		document.myForm.time.value = ajaxRequest.responseText;
	}
}
var id = document.getElementById('id').value;
var queryString = "?id=" + id;
ajaxRequest.open("GET", "trackeractions.php" + queryString, true);
ajaxRequest.send(null); 


}

//-->
</script>


<div class='wrap'>
<p><img src="images/logo.png" width="190" height="29" /><br />
</p>
<div class="nav">Home</div>
<div class="nav2">Services</div>
<div class="nav2">About Us</div>
<div class="nav2">Customer Support</div>
<div class="nav2">Tracker</div>
<div class="spacer"></div>
<div class="title">
  <div class="textle">Price & Services </div>
</div>
<div class='picture'><img src="images/cargo.png" alt="cargoplane" width="450" height="199" /></div>

<div class='content'>

Package ID:<input name="id" type="text" value="" size="10" maxlength="10" /> <br />
<input type='button' onclick='ajaxFunction()' value='Track' />

</div>


</div>
</body>
</html>

     

    php file

     

    <?php
$dbhost = "localhost";
$dbuser = "root";
$dbpass = "";
$dbname = "tgj4u";
//Connect to MySQL Server
mysql_connect($dbhost, $dbuser, $dbpass);
//Select Database
mysql_select_db($dbname) or die(mysql_error());
// Retrieve data from Query String
$id = $_GET['id'];
// Escape User Input to help prevent SQL Injection
$id = mysql_real_escape_string($id);
//build query
$query = "SELECT * FROM maildata WHERE id = '$id'";

//Execute query
$qry_result = mysql_query($query) or die(mysql_error());

// Insert a new row in the table for each person returned
$info = mysql_fetch_array($qry_result)

echo "Sent by: " . $info['sender'] . "<br>";	
echo "Recipient: " . $info['recipient'] . "<br>";	
echo "Departed: " . $info['depart'] . "<br>";
echo "Satus: " . $info['depart']; . "<br>";
echo "Current Location: " . $info['currentlocation'] . "<br>";
echo "Arrival Location: " . $info['finallocation'] . "<br>";
echo "Expected on: " . $info['expected'] . "<br>";


?>

     

    I've tried alot of things, but I dont see where the error is...

     

     

    Thanks

    registration script issue

    in PHP Coding Help

    Posted

    I made a script in which registrates a user very basicly. here are the functions used.

     

    I click submit get no error but it doesnt do anything to the databse nor does it send me the the url as indicated in the header();

     

     

    <?php
require_once('config.php');

function secure_var($var){

$var = mysql_real_escape_string(htmlentities($var));

}

function check_username($username){

$query = mysql_query("SELECT * FROM user_info WHERE username = {$username}");

if ($query >= 1){

return true;

}

else {

return false; }

}


function check_email($email){

$query = mysql_query("SELECT * FROM user_info WHERE email = {$email}");

if ($query >= 1){

return true;

}

else {

return false; }


}


// Register User
function register_user($username, $password1, $password2, $email, $captcha){

secure_var($username);
secure_var($password1);
secure_var($password2);
secure_var($email);

$Error = null;

// Validate Username Field
if(!preg_match("/\A[a-z0-9_]{4,15}$/i",$username)){
	$Error .= "Username Can Only Contain Letters, Numbers and Underscores (Between 4-15 Characters Long) <br />";
}

// Validates Username Availability
if(check_username($username) == true){

$Error .= "You're chosen username is taken. Plase choose another one.<br />";

}

// Validates Email Availability
if (check_email($email) == true){

$Error .= "You're email is already in use.<br />";

} 

// Validate Password Field
if (!preg_match("/\A[a-z0-9 _-]{4,15}$/i",$password1)){
	$Error .= "Password Can Only Contain Letters, Numbers, And Underscores (Between 4-15 Characters Long <br />";
}

// Validate Password Confirmation
if ($password1 != $password2){
	$Error .= "Password and Password Confirmation Do Not Match <br />";
}

// Validate Email Address Format
if (!preg_match("/\A[^0-9][a-zA-Z0-9_]+([.][a-zA-Z0-9_]+)*[@][a-zA-Z0-9_]+([.][a-zA-Z0-9_]+)*[.][a-zA-Z]{2,4}$/", $email)){
	$Error .= "Email Address Must Be In format: [username]@[domain].[extension] <br />";
}

// Validate Security Image
if ($captcha != $_SESSION['captcha']){
	$Error .= "Your Captcha Input Does Not Match The Image Shown";
}		

// Result Success or Error
if($Error == null){


	$reg_user = mysql_query("INSERT INTO user_info (username, password, email) VALUES ($username, $password, $email)");

	if($reg_user){
	header('login.php?reg=1');
	}

}else{
	// Echo the error(s)
	echo($Error);
}
}
?>

    [SOLVED] how to use submit buttons?

    in PHP Coding Help

    Posted

    still not responding...

     

    <?php
require_once("functions.php");

if (isset($_POST['post_form'])){
register_user($_POST['username'], $_POST['password1'], $_POST['password2'], $_POST['email'], $_POST['securityCode']);
}
?>


<p>Username: 
  <label>
  <input name="username" type="text" id="username" maxlength="15" />
  </label>
</p>
<p>
  Password: 
  <label>
  <input type="password" name="password1" id="password1" />
    </label>
  </p>
<p>
  Re-type Password: 
  <label>
  <input type="password" name="password2" id="password2" />
    </label>
  </p>
<p>
  E-mail: 
  <label>
  <input type="text" name="email" id="email" />
    </label>
</p>
<p>  <img src="captcha/captcha.php" alt="captcha" /><br />
  Security Code: 
  <label>
  <input name="securityCode" type="text" id="securityCode" maxlength="5" />
  </label>
</p>
<p>
  <label>
  <input type="submit" name="post_form" id="post_form" value="Submit" />
  </label>
</p>

    [SOLVED] CAPTCHA Session NULL

    in PHP Coding Help

    Posted

    I'm not sure why my capcha session is null when I try to echo it nothing shows up.

     

    <?php

$length = 5;
$width = 150;
$height = 50;

//Creates md5 hash
$hash = md5(rand(0, 9999));

//creates a code with $length  
$code = substr($hash, 15, $length);

//stores the code into a session
$_SESSION['captcha'] = $code;


//creates the image
$image = imagecreate($width, $height); 

//creates background and text colours
$background = imagecolorallocate($image, 0, 0, 0);
$text = imagecolorallocate($image, 255, 255, 255);

//creates the image
imagefill($image, 0, 0, $background); 

//Specifies font and text
imagettftext($image, 42, 8, 12, 60, $text, "captcha.ttf", $code);

//Tells the browser what kind of image is being outputted. 
header("Content-Type: image/png"); 

//creates the image
imagepng($image);

//frees up resources
imagedestroy($image); 

?>

     

    this is how i included it.

    <img src="captcha/captcha.php" alt="captcha" />

     

     

    [SOLVED] Registeration bug

    in PHP Coding Help

    Posted

     

    I don't understand, I leave everything blank and it passes and echo's out it should register the user.... Why is my regex not working?

     

    function register_user($username, $password1, $password2, $email, $captcha){


	if (!preg_match('/^[a-z\d_]{4,15}$/i',$username)){
		$usernameError = true;
	}

	if ($password1 != $password2){
		$passwordError = true;
	}

	if (!preg_match('/^[^0-9][a-zA-Z0-9_]+([.][a-zA-Z0-9_]+)*[@][a-zA-Z0-9_]+([.][a-zA-Z0-9_]+)*[.][a-zA-Z]{2,4}$/', $email)){
		$emailError = true;
	}

	if ($captcha != $_SESSION['captcha']){
		$captchaError = true;
	}		


	if ($usernameError == true or !isset($passwordError) or !isset($emailError) or !isset($captcha)){
		//Register the user
		echo "will register the user";
	}


	else {

		if ($usernameError == true){
		echo "You're username is not formatted properly.<br>";
		}
		if ($passwordError == true){
		echo "You're entered passwords do not match<br>";
		}
		if ($emailError == true){
		echo "Please enter a correct e-mail adress.<br>";
		}
		if ($captchaError == true){
		echo "Security code did not match.<br>";
		}
	}

}

    [SOLVED] Issues with Captcha

    in PHP Coding Help

    Posted

    I have one major issue with my captcha, It's doing everything I want it to but one thing.

    I thinks its alone on the page and makes my register.php a png image and outputting nothing else but itself.

     

    heres my code:

    <?php
function create_captcha($length){

//Creates md5 hash
$hash = md5(rand(0, 9999));

//creates a code with $length  
$code = substr($hash, 15, $length);

//stores the code into a session
$_SESSION['captcha'] = $code;  

//image size
$width = 150;
$height = 50;

//creates the image
$image = imagecreate($width, $height); 

//creates background and text colours
$background = imagecolorallocate($image, 0, 0, 0);
$text = imagecolorallocate($image, 255, 255, 255);

//creates the image
imagefill($image, 0, 0, $background); 

//Specifies font and text
imagettftext($image, 42, 5, 15, 55, $text, "captcha.ttf", $code);

//Tells the browser what kind of image is being outputted. 
header("Content-Type: image/png"); 

//creates the image
imagepng($image);

//frees up resources
imagedestroy($image); 
}
?>

     

    thanks

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