Recreational_Champ

Thanks for moving the post: I noticed I had posted in the wrong spot after submission. I have solved my problem!!! forget about symbolic links and just update .bash_login(or whatever your file name might be) #path is now set to MAMP mysql server and as a default I have added my other path as well export PATH="/Applications/MAMP/Library/bin:/usr/local/mysql/bin:$PATH" I understand that I can opt to run the two servers on different ports and just specify which mysql I want by that means instead, but I haven't tried that yet.

Hello~ I have two mysql servers running on my computer, the one I installed by itself and the one that came packaged with MAMP. I have created a path in a file called .bash_login: export PATH="/usr/local/mysql/bin:$PATH" and I am not quit sure why this path is set as such because mysql_sock is located in /tmp. I want to be able to run the MAMP mysql server from the cli and know that I can create a sym link to accomplish this task: sudo ln -s /Applications/MAMP/tmp/mysql/mysql.sock /tmp/mysql.sock If I create the sym link will I be able to run the mysql server packed with mamp from cli? What will be the effects on the current mysql server? What is mysql looking for to actually run? If I have supplied enough information, could you help me understand what is going on here. I would also be happy to keep everything as is and do something like: mysql -u 'user' -h '/path/to/mamp_mysql_file' -p, but still want to understand whats going on.

Sorry for not specifying exactly what I was trying to accomplish; I really thought the code was short and strait forward enough to follow without explanation. I don't just want to code for a solution, but code in the most efficient way as possible. I feel as though my solutions are elementary in their structure and do think that it looks "bad" to have repetitive processes. I guess I kinda wanted for someone to post a solution not because I wanted it done for me, but to understand what I could do to improve my self in the future YES! YES! YES! That is the solution I was looking for: select logs.answer_id, count(*) from logs,answers where answers.question_id=$_GET['variable'] and logs.answer_id=answers.answer_id group by answer_id I had yet to discover grouping Thank you so very much for your time!

I would like to know if there is a more efficient way than what I already have. <?php $ip = gethostbyaddr($_SERVER['REMOTE_ADDR']); require_once ('mysql_connect.inc.php'); $query = "INSERT INTO logs VALUES(NULL,{$_GET['a_id']},'$ip',NULL)"; mysql_query($query) or die("Not inserted". mysql_error()); $query = "SELECT * FROM answers,logs where answers.question_id={$_GET['q_id']} and logs.answer_id=answers.answer_id"; $result = mysql_query($query) or die('Error, query failed'); $num_rows = mysql_num_rows($result); $sum_1; $sum_2; $sum_3; if($_GET['q_id'] == 1) { $query = "SELECT COUNT(answer_id) AS times_chosen FROM logs where answer_id=1"; $result = mysql_query($query) or die('Error, query failed'); $row = mysql_fetch_array($result); $sum_1 = $row['times_chosen']; $query = "SELECT COUNT(answer_id) AS times_chosen FROM logs where answer_id=2"; $result = mysql_query($query) or die('Error, query failed'); $row = mysql_fetch_array($result); $sum_2 = $row['times_chosen']; $query = "SELECT COUNT(answer_id) AS times_chosen FROM logs where answer_id=3"; $result = mysql_query($query) or die('Error, query failed'); $row = mysql_fetch_array($result); $sum_3 = $row['times_chosen']; } if($_GET['q_id'] == 2) { $query = "SELECT COUNT(answer_id) AS times_chosen FROM logs where answer_id=4"; $result = mysql_query($query) or die('Error, query failed'); $row = mysql_fetch_array($result); $sum_1 = $row['times_chosen']; $query = "SELECT COUNT(answer_id) AS times_chosen FROM logs where answer_id=5"; $result = mysql_query($query) or die('Error, query failed'); $row = mysql_fetch_array($result); $sum_2 = $row['times_chosen']; $query = "SELECT COUNT(answer_id) AS times_chosen FROM logs where answer_id=6"; $result = mysql_query($query) or die('Error, query failed'); $row = mysql_fetch_array($result); $sum_3 = $row['times_chosen']; } if($_GET['q_id'] == 3) { $query = "SELECT COUNT(answer_id) AS times_chosen FROM logs where answer_id=7"; $result = mysql_query($query) or die('Error, query failed'); $row = mysql_fetch_array($result); $sum_1 = $row['times_chosen']; $query = "SELECT COUNT(answer_id) AS times_chosen FROM logs where answer_id=8"; $result = mysql_query($query) or die('Error, query failed'); $row = mysql_fetch_array($result); $sum_2 = $row['times_chosen']; $query = "SELECT COUNT(answer_id) AS times_chosen FROM logs where answer_id=9"; $result = mysql_query($query) or die('Error, query failed'); $row = mysql_fetch_array($result); $sum_3 = $row['times_chosen']; } $percent_1 = ($sum_1 / $num_rows) * 100; $percent_2 = ($sum_2 / $num_rows) * 100; $percent_3 = ($sum_3 / $num_rows) * 100; mysql_free_result($result); mysql_close($connection); ?>

what about: ob_start() //code ob_flush()

Beautiful!!! Thank you for your time!!!

Well, thats all that I have on that page --which works well alone. It will be a graph based on poll results and I want to display other other php/html code next to that image. <?php header ("Content-type: image/png"); $cavas = imagecreate(300,300); $gray = imagecolorallocate ($cavas,0xcc,0xcc,0xcc); $white = imagecolorallocate ($cavas,0x33,0x33,0x33); $light_purple = imagecolorallocate ($cavas,943,387,453); $color = imagecolorallocate ($cavas,'abc',123,956); imagefilledrectangle($cavas,0,0,40,70,$white); imagefilledrectangle($cavas,0,80,20,160,$light_purple); imagefilledrectangle($cavas,0,170,70,250,$color); imagepng($cavas); ?> <html> <h2>Poll results:</h2> </html> make sense?

<?php header ("Content-type: image/png"); $cavas = imagecreate(300,300); $gray = imagecolorallocate ($cavas,0xcc,0xcc,0xcc); $white = imagecolorallocate ($cavas,0x33,0x33,0x33); $light_purple = imagecolorallocate ($cavas,943,387,453); $color = imagecolorallocate ($cavas,'abc',123,956); imagefilledrectangle($cavas,0,0,40,70,$white); imagefilledrectangle($cavas,0,80,20,160,$light_purple); imagefilledrectangle($cavas,0,170,70,250,$color); imagepng($cavas); ?> How can I add that image that I created to an existing page without header errors?

You haven't tried an energy drink then

I have had many views and no responses, does this post make sense? Is the question so obvious that no one will respond? Any help will be greatly appreciated.

Hello all~ I have made a php game printing out images using a multidimensional array stored within a session variable named 'board.' I am having quite some time trying to navigate the current state of my player. <form action="this.php" method="get" accept-charset="utf-8"> <input type="submit" name="right" value="→"> <input type="submit" name="left" value="←"> <input type="submit" name="up" value="↑"> <input type="submit" name="down" value="↓"> <input type="submit" name="reset" value="reset;"> </form> if(isset($_GET['right'])) { $dir = "right"; move($dir); } if(isset($_GET['left'])) { $dir = "left"; move($dir); } if(isset($_GET['up'])) { $dir = "up"; move($dir); } if(isset($_GET['down'])) { $dir = "down"; echo "$dir"; } if(isset($_GET['reset'])) { session_destroy(); setcookie(session_name(),"", time() - 3600); $_SESSION=array(); echo "reset"; Now, I can move the player in any direction I choose, but I have to hit the submit button "twice" to get the player to move only after I have moved in a different direction. Example: New session started, player in a random position... Try to navigate player up/down/left/right and it will move in the direction I last clicked "once" before moving the current selection... even when cookies/sessions have been cleared. Somehow the submit GET status retains last moved state; I am one click behind and cannot figure it out My move() is working just fine! Problem occurs when I submit reset as well. A walk through would be very helpful Thanks

I would like to traverse images in my array by using form buttons for navigation i.e. up, down, left, or right. I have: <form action="<?php $_SERVER['PHP_SELF'] ?>" method="get" accept-charset="utf-8"> <p> <input type="submit" name="right" value="right"> <input type="submit" name="left" value="left"> <input type="submit" name="up" value="up"> <input type="submit" name="down" value="down"> <input type="submit" name="reset" value="reset"> </p> </form> What code would be required so that if the submit button right is pressed I would be able to call a function that does things every time right is pressed ? Thanks