hemangi

Thanks very much guys, it all works fine now! I like it slim and I am a girl

HI everyone, I am beginner in PHP and I need help with little code. I am making a web site in Dreamweaver using MySql database and PHP. I have image address in row 10 of the database table and I display them well but they only exist for some of the records, not all. But when I place the recordset on the page and test it in browser-it displays the image when the recordset contains it's address, but it displayes an empty image (like broken link one) for all the rest of the records. What I need is simple if else statement in php to tell it to display alternative image or nothing when the row record is empty. I have this code, but is obviously wrong because it gives me an error: <?php if ($row_rsList['WL']==""){ echo "images/emptyGraphic.gif"}?> <?php else echo $row_rsList['WL'] /> "rsList" is my recordset in dreamweaver which contains all the table rows and "WL" is row number 10. I place instances of all the row in the page, like phone:... email:... etc and I also would like to know how to make them not show if the record is empty. Instead I have now empty line where this record was supposed to be. I would like it to ignore the line and bring the next record directly under it. Can you please help me !!! Regards, Emiliya