ldb358
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Posts posted by ldb358
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Will they always be in sets of 2 words?
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okay post the code and ill take a look
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no you should just create one column and store the $tag variable in it and then you'll have a list of tags that you can later search
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change the name of them to:
<input name="tag[]" type="checkbox" value="accident" /> <input name="tag[]" type="checkbox" value="airport"/> <input name="tag[]" type="checkbox" value="airtoair"/>
then you can loop through it like so:
$tags = new Array(); foreach($_POST['tag'] as $tag){ if($tag){ tags[] = $tag; } } $tag = implode(',',$tags);
then inset the $tag variable in your database as text
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UPDATE users SET id=id-1 WHERE id>$post_id
Where $post_id = the id of the post deleted
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your condition should look like this:
if ($random == 0) { $a = 0; $a++; }
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try:
<?php $data = 'Pulp Fiction'; $out = substr($data, 0, 7); if(strlen($data > 7){ $out .= '...'; } echo $out; ?>
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you could do something like this:
<?php $string = "The quick brown fox jumps over the moon to discover that it really wasn't the moon at all but a big rock in the ground"; $delimiter = "discover"; $maxlenth = 15; $new = substr($string,strpos($string,$delimiter)-$maxlenth,$maxlenth*2+strlen($delimiter)); ?>
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okay thank you for you help
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okay thanks i am reading up on openVZ, it seems to be exactly what i was looking for.
the issue however comes once traffic starts to hit & without specs, we couldn't say.What exactly do you mean by this? I am assuming you mean site traffic, which should be pretty low as i will only be running a portfolio and blog on it
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i dont get what your asking i guess because if the value != 0 that is what it is supposed to output
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I currently have a desktop that was great but after i got my laptop has gotten little use, so i am thinking about making it into a vps web server where i will provide the server and my friends will pay for the internet connection the specs are:
750gb hard drive (would like to partion it in to 3 separate vps')
8gb ram
2.2 amd quadcore
my questions are:
a)Are these specs good enough? (i would assume so but you never know)
b)what software would i need to do this?(i want to run a ubuntu server)
c)Any other advise?
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try:
$test = $database->query($status); $row = mysql_fetch_array($test); if($row['status'] == '0'){
if that doesn't work what mysql class are you using?
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try adding:
$test = $database->query($status); echo $database->error; //check if there is a mysql error var_dump($test); //check if its returning an object
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if i understand your question properly you can connect to the same mysql server from different site
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you have a typo:
$q2 = mysql_query("INSRET INTO `players` (id, timestamp, gameid, players) VALUES ('NULL', 'NULL', '$gameid', '$players')") or die(mysql_error()); //should be $q2 = mysql_query("INSERT INTO `players` (id, timestamp, gameid, players) VALUES ('NULL', 'NULL', '$gameid', '$players')") or die(mysql_error());
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your checking whether the object == 0 you need to add:
$test = $database->query($status); $row = $test->fetch_object(); if($row->status == '0'){
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okay i get on that thanks
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by links do you mean the ones on the menu bar, side bar or all of them?
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hey i just launched my new site and im looking for some feed back both on the design and the content it is located here:
http://lanesportfolio.com/blog/
thanks in advance
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as stated above use simpleXML a quick example:
$xmlfile = 'file.xml'; $xml = simplexml_load_file($xml); $images = array(); foreach($xml->pic as $link){ $images[] = $link->image; }
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yeah sorry i missed that
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okay your setting it in the wrong place, what you need to do is replace:
session_register($myusername); session_register($mypassword); //with $_SESSION['username'] = $myusername; $_SESSION['password'] = $mypassword;
so your final script would look like:
<?php ob_start(); $host="localhost"; // Host name $username="xx"; // Mysql username $password="xx"; // Mysql password $db_name="xx"; // Database name $tbl_name="members"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // Define $myusername and $mypassword // To protect MySQL injection $myusername = stripslashes($myusername); $mypassword = stripslashes($mypassword); $myusername = mysql_real_escape_string($myusername); $mypassword = mysql_real_escape_string($mypassword); $sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'"; $result=mysql_query($sql); // Mysql_num_row is counting table row $count=mysql_num_rows($result); // If result matched $myusername and $mypassword, table row must be 1 row if($count==1){ // Register $myusername, $mypassword and redirect to file "login_success.php" $_SESSION['username'] = $myusername; $_SESSION['password'] = $mypassword; header("Location: /clients/".$myusername."/"); } else { echo "Wrong Username or Password"; ob_end_flush(); ?>
and your other script should look like:
session_start(); if(isset($_SESSION['username']){ header("location:../../index.php"); }
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i'm 17 now and when i joined i was 16
OOP why does this not work?
in PHP Coding Help
Posted
what version of php are you using when i run it on 5.3 it works but if i would have to guess i would say your on an older version of php because if you look here
http://php.net/manual/en/language.oop5.static.php
it says that the first method of calling a static function was added in 5.3