prashanth

http://www.symfony-project.org/doc/ see this link you will get more information

[[WARNING]] XSL module is installed: FAILED *** Install the XSL module (recommended for Propel) *** this warning is important.

what is the necessity of changing the include_path just follow the procedure as per the blog,the zendframe will installed successfully. if you have any questions in that blog let me know.

Hello See the below link http://roshanbh.com.np/2008/09/change-textbox-value-dropdown-list-ajax-php.html

Hi See the below link i have given the procedure how to install the zendFramework in xampp http://prashanthm08.blogspot.com/2009/12/zend-framework.html still if you have any issues let me know.

Hi we can achieve this by using AJAX. Here is the flow ---------------------- when you change the option in the select box call the javascript function. you need to build the javascript function which will request to the php file. php file should take the id and perform the database operations and echo the name. in javascript you will get the response and that response you can assign to the textbox. you try in this way and just search in the net you will get lot of scripts. still if you are not clear how to do let me know with your requirements,i will give the code to you.

Hello peter11 by seing your post title it seems you are checking the username with database records here is the logic ---------------------- // Connect // $con = mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name", $con)or die("cannot select DB"); // CHECK LOGIN // $query = ("SELECT * FROM members WHERE username='".$_POST['username'] ."'"); $checklogin = mysql_query($query); $res = mysql_fetch_array($checklogin,MYSQL_ASSOC); if (!empty($res)){ echo "TAKEN"; } else echo "FREE"; Still if you are not clear let me know

Hi here is the code for your problem $con = mysql_connect("hostname","mysql username","mysql password"); mysql_select_db("databse name",$con); $query = "SELECT * FROM members"; $checklogin = mysql_query($query); while($res = mysql_fetch_array($checklogin,MYSQL_ASSOC)) { $result[] = $res; } the results will have the details so now you can loop the results and you can check the conditions as your wish. Let me know if you need in detail code i will provide.

You will get external library json.php if you download this and include in your script the json functions(json_encode and json_decode etc...) will work as usually.

thanks for your suggestion thorpe.

sorry i want to upgrade to php 5.3.1 it is not 3.1

Hi Everyone, Can any one tell me how to upgrade the PHP version to current 3.1 in xampp. Thanks in Advance

Hello everybody This is Prashanth iam having 3+ years of Experience in PHP. i have worked with different Frameworks in PHP Like Cake,Symfony,QCodo,CodeIginitor iam welcome to everyone to ask me about any questions related to PHP

Hi jokerbla make sure symfony will work in wampp or not? iam sure it will work in xampp only in windows systems.if it will work in wamp also we need to include the php path in system variables.

yes it is. It is one of very good and powerful Framework now a days.

It will be easier if you maintain the data of users&posts details in a separate table. Scenario: ------------ create a table read_posts(what ever the name you want put the table name) with id,user_id,post_id. when you are displaying the list of new posts from posts table depends upon the created date.just check with this table depends upon the post_id and the user_id(the id of user who logged in) if the record exists in that table that means the user "read" that post if not he didn't read so you can highlight with different color.

Make sure that the login details you are entering correct. it seems you are login to the phpmyadmin with mysql username(root) with blank password. but where as your mysql password is not blank. you have to login with phpmyadmin with mysql username ans password

Hi You Need to to install "PHP filter" module in Core-Optional Section to embed PHP Code into the Page.