[Undefined function?]

I get an error saying call to undefined function. Shouldn't move_uploaded_file() work?

(I know I didn't set the size and etc, it's just a practice test) Also, my host's php version is 4.4.9 could that be a problem?

 

<?php
session_start();
include "functions.php";
include "database.php";


if(($_POST['upload'])){
    $uploadname = $_FILES['avatar']['name'];
    $tmp_name = $_FILES['avatar']['tmp_name'];

  if($uploadname){
     echo "...";
    }
   
  else{
     die("Please select a file numb nuts!");
    }

   if($uploadname) {
        $location = "avatars/$name";
        move_uploaded_file($tmp_name,"$location");
          
        $query = mysql_query("UPDATE narutorpg SET imagelocation = '$location' WHERE username = '$name'");
        $die("Your avatar is uploaded. <a href = 'character.php'> home </a>");

      }
}



echo " <form action = '' method = 'POST' enctype = 'multipart/form-data'>
File:<input type = 'file' name = 'avatar'> <input type = 'submit' name = 'upload' Value = 'upload'> 
</form>";





?>

 

 

 

[You guys will love this ^_^]

"I spent 27 hours on this" Haha.

[VERY SIMPLE QUESTION]

You should start using <br /> instead of <BR> <BR> is old HTML which is dieing.

[php time help]

The user can simply delete the session cookie.

 

Yeah i know. I'll inevitable have to use the database to store the timestamp, but this is a temporary fix until tomorrow.

[php time help]

I don't see how that's possible. As was mentioned above, sessions expire when the user closes their browser.

 

session_set_cookie_params()

 

worked for me.

[UPDATE after a time delay]

I fixed mine by using sessions.

 

session_start();
session_set_cookie_params(84600);

if(isset($_POST['submit'])){
$_SESSION['clicked'] = 1;
}

 

You should know what to do from here. (:

[php time help]

I fixed by using sessions like suggested, thanks for everyones support.

[php time help]

Still looking for a simpler soultion, this should be possible without having to use the database, how would I check it with sessions? anyone know?

[php time help]

Depends on what you mean by "once a day".  If I click today (Monday) at 11:59PM, can I click again tomorrow (Tuesday) at 12:01AM even though it's been only 2 minutes?

 

Just 24 hours time. All I want is a 24 hours between clicks on the submit button for each person.

[php time help]

I'm not sure how that would, that's why I wanted an example, how do I use the php time function to check if they clicked within 24 hours?

[UPDATE after a time delay]

Perhaps updating the database right away, and then caching the results for the user for a certain period of time would be a solution.

 

Otherwise you'd probably have to store everything in a temporary directory, and then set up a cron job to scan the folder and make the DB updates.

 

I have the same question, but I was pretty  sure you could some how use a php time function to do this..or maybe javascript? Is going through all that trouble the only way?

[php time help]

Is there a way to use PHP time to only allow a user to press a button in a form (for example a submit button) once a day? If so, could I get an example? Thanks.

[Database modification script help]

mysql_query($insertAdminInfoQuery) or die("ERROR: " .mysql_error())

 

Forgot a semicolon, though I didn't even really read the whole script, just followed the error.

 

needs to be

 

 

mysql_query($insertAdminInfoQuery) or die("ERROR: " .mysql_error());

[Way to insert +7 into a field?]

UPDATE account_info SET experience = experience + 7 WHERE username = $name

This worked perfectly, thanks a lot.

[Way to insert +7 into a field?]

Hi, I have a field called experience in mysql and I want to add +7 to said field, is it possible using UPDATE or insert? If so, what's the syntax?

 

Here's what I have that doesn't work, it sets experience to 7, but won't add another 7 when clicked again.

 

 if(isset($_POST['submit'])){
    $query = "UPDATE account_info SET experience = +7 WHERE username = $name"; 
    $result = mysql_query($query) or die(mysql_error());
}

 

 

don't ask for the whole script, because you won't need it to answer that o.0

[output a row?]

Everything is working great now! I figured out what happen!

 

Thanks!

[output a row?]

Edit:

 

got this:

 

sql: SELECT * FROM account_info WHERE username = "tony"

result: Resource id #3

after mysql_fetch_array

0

[output a row?]

<?php
include "database.php";
session_start();

$name = $_session['outname'];
function output_wins($name){
  $sql = "SELECT * FROM account_info WHERE username = '$name'";
  $result = mysql_query($sql) or die(mysql_error());
  $wins = mysql_fetch_array($result);
  return $wins['win'];
}



?>

[output a row?]

change the mysql_query line to this:

 

$result = mysql_query($sql) or die(mysql_error());

I did and this is the error:

mysql_fetch_array(): supplied argument is not a valid MySQL result resource

 

[output a row?]

Ah, here's the error:

mysql_fetch_array(): supplied argument is not a valid MySQL result resource

[output a row?]

Ehh, it seems to work but it's not outputting anything. It's blank.

[why won't this work? Seems simple enough]

$sql = 'SELECT * FROM account_info WHERE username ="'.$name.'"';
$result = mysql_query($sql) . mysql_error();
$row = mysql_fetch_row($result);

 

I get

 

Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource

 

I'm trying to output the row "wins" for a certain user.

[output a row?]

How do I got about outputing one row that can only hold one value? Any reason why the function below doesn't work?

 

<?php
include "database.php";
session_start();
$name = $_session['outname'];

function output_wins(){
$sql = 'SELECT * FROM account_info WHERE username ="' . $name .'"';
$result = mysql_query($sql);
$wins = mysql_fetch_array($result);
echo $wins['win'];
}



output_wins();

?>

 

Is there an easier way I can output this one row?

[I have a comment. ]:]

Respect my authority.

 

Jokes. Please don't hurt me.

 

I'd like to give thanks to all of the people who have helped me recently on the problems I have been having with PHP. Sometimes, when I get a question answered, I'll be so excited to try out the solution myself, I forget to give thanks to that person who spent time out of his/her day to help me.

 

I think the website is great and hope that it will be here for the long run. I would have probably given up no php without this site, hell, I predict that soon half of this websites posts will belong to me asking for help. 

[Poistion for each computer screen??]

I fixed by doing this.

 

body{   width: 800px; height: 600px; }