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Found 467 results

  1. crack576
    <body> <?php include 'sql.php'; $query = "SELECT * FROM validation"; $result = mysqli_query($con , $query); $rows = mysqli_fetch_assoc($result) ; $totals = mysqli_num_rows($result) ; ?> <div id="css"> <form > <table width="80%" border="0" cellpadding="2" cellspacing="2" > <caption><h2>Personal Details of Customers</h2></caption> <tr class="white"> <td bgcolor="#330033"> </td> <td bgcolor="#330033"> Id Number </td> <td bgcolor="#330033"> Full Name </td> <td bgcolor="#330033"> Email Address </td> <td bgcolor="#330033"> Website </td> <td bgcolor="#330033"> Comment </td> <td bgcolor="#330033"> Time </td> </tr> <?php while($rows=mysqli_fetch_assoc($result) { <tr> <input type="raido" name="ID" value="<?php echo $rows['ID']; ?>" /> <td bgcolor="#FFFFCC"><?php echo $rows['ID'];?></td> <td bgcolor="#FFFFCC"><?php echo $rows['Name'];?> </td> <td bgcolor="#FFFFCC"><?php echo $rows['Email'];?></td> <td bgcolor="#FFFFCC"><?php echo $rows['Website'];?></td> <td bgcolor="#FFFFCC"><?php echo $rows['Comment'];?></td> <td bgcolor="#FFFFCC"><?php echo $rows['Time'];?></td> <td> </td> <td> <a href="delete.php? ID= "$rows[ID]" /"> <input type="submit" name="del" value="Delete" /> </a> <input type="button" name= "edit" value="Edit" /> </td> </tr> } ?> </table> </form> </div> </body>
  2. kyle01
    Hi there, I have this conversion program I am trying to make. Basically I have one file called 'index.html' and another called 'convert.php', the basic function of this program is to show a form in the html page and then get the calculation from the php form and then show the result back on the html page. The html page uses a dropdown list of different conversions the user can select from. Below is the code I've got. Please can you help with fixing this thing! It's really annoying me! :@ HTML CODE: <HTML> <HEAD> <title>Unit Converter</title> </HEAD> <BODY> <h1>CONVERSION</h1> <form action="convert.php" method="post"> <link rel="StyleSheet" media="screen" href="convert.css"> Type of conversion: <br> <select name="conversionType"> <option value="null" selected="selected">Select type...</option> <option value="null"></option> <option value="null">--Temperature--</option> <option value="C-F">Celsius to Fahrenheit</option> <option value="C-K">Celsius to Kelvin</option> <option value="C-R">Celsius to Rankine</option> <option value="K-C">Kelvin to Celsius</option> <option value="K-F">Kelvin to Fahrenheit</option> <option value="K-R">Kelvin to Rankine</option> <option value="F-C">Fahrenheit to Celsius</option> <option value="F-K">Fahrenheit to Kelvin</option> <option value="F-R">Fahrenheit to Rankine</option> <option value="R-C">Rankine to Celsius</option> <option value="R-K">Rankine to Kelvin</option> <option value="R-F">Rankine to Fahrenheit</option> </select> <br><br> Value to convert:<br> <input type="text" name="conversionInput"> <br><br> <input type="submit" value="Convert"> </form> </BODY> </HTML> PHP CODE: <HTML> <title>Conversion Output</title> </HTML> <?php $conversionType = $_POST['conversionType']; $conversionInput = $_POST['conversionInput']; $conversionValue; $conversionFrom; $conversionTo; if ($conversionType == 'C-F') { $conversionValue = $conversionInput * (5/9) + 32; $conversionFrom = "° Celsius"; $conversionTo = "° Fahrenheit"; } if ($conversionType == 'C-K') { $conversionValue = $conversionInput + 273.15; $conversionFrom = "° Celsius"; $conversionTo = "° Kelvin"; } if ($conversionType == 'C-R') { $conversionValue = ($conversionInput + 273.15) * (9/5); $conversionFrom = "° Celsius"; $conversionTo = "° Rankine"; } if ($conversionType == 'K-C') { $conversionValue = $conversionInput - 273.15; $conversionFrom = "° Kelvin"; $conversionTo = "° Celsius"; } if ($conversionType == 'K-F') { $conversionValue = $conversionInput * (9/5) - 459.67 ; $conversionFrom = "° Kelvin"; $conversionTo = "° Fahrenheit"; } if ($conversionType == 'K-R') { $conversionValue = $conversionInput * (9/5); $conversionFrom = "° Kelvin"; $conversionTo = "° Rankine"; } if ($conversionType == 'F-C') { $conversionValue = ($conversionInput - 32) * (5/9) ; $conversionFrom = "° Fahrenheit"; $conversionTo = "° Celsius"; } if ($conversionType == 'F-K') { $conversionValue = ($conversionInput + 459.67) * (5/9); $conversionFrom = "° Fahrenheit"; $conversionTo = "° Kelvin"; } if ($conversionType == 'F-R') { $conversionValue = $conversionInput + 459.67; $conversionFrom = "° Fahrenheit"; $conversionTo = "° Rankine"; } if ($conversionType == 'R-C') { $conversionValue = ($conversionInput + 491.67) * (5/9); $conversionFrom = "° Rankine"; $conversionTo = "° Celsius"; } if ($conversionType == 'R-K') { $conversionValue = $conversionInput * (5/9); $conversionFrom = "° Rankine"; $conversionTo = "° Kelvin"; } if ($conversionType == 'R-F') { $conversionValue = $conversionInput - 459.67; $conversionFrom = "° Rankine"; $conversionTo = "° Fahrenheit"; } echo "$conversionInput $conversionFrom = $conversionValue $conversionTo"; ?>
  3. Pavlos1316
    In HTML5 some attributes are no longer supported eg: name attr for <a> is no longer supported. What happens when in a tag like <a> exists a non supported attr? <a id="me" name="you"> Will it just be ignored like is not there or it can cause problems later on and how?
  4. jupiter
    I'm experimenting with a basic CRUD App. The table created by the code below renders, however when I view source, the last tag is the closing </tr> after the while loop finishes. There's nothing after that. No closing table, html, or body tags. I can't see what I've done wrong. <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> <title>Eric's PHP CRUD App</title> <style type="text/css"> table { font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 10px; text-align: center; margin: 0 auto; } table td { text-align:center; border: 1px solid #dfdfdf; } tr:nth-child(odd) { background: #fdfdfd; } tr:nth-child(even) { background: #B8D3FF; } th { background-color:#ccc; } .center { width: 1050px; margin:0px auto; } h1 { font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 14px; padding-bottom: 15px; text-align: center; margin: 0 auto; color: white; } </style> </head> <body bgcolor="#999"> <?php require_once("db_connect.php"); echo "<h1>Update Student Records</h1>"; echo "<table cellpadding='10'>"; echo "<tr bgcolor='#cccccc'>"; echo "<th>First Name</th>"; echo "<th>Last Name</th>"; echo "<th>Test 1 Grade</th>"; echo "<th>Test 2 Grade</th>"; echo "<th>Test 3 Grade</th>"; echo "<th>Test 4 Grade</th>"; echo "<th>Final Exam Grade</th>"; echo "<th>Average Grade</th>"; echo "<th>Final Grade</th>"; echo "<th>delete</th>"; echo "<th>edit</th>"; echo "</tr>"; $sql = "SELECT * FROM students"; $result = mysqli_query($link, $sql) or die(mysql_error()); while($row = mysqli_fetch_array($result, MYSQLI_ASSOC) or die(mysql_error())) { $final = ""; $average = (($row["test1Grade"]) + ($row["test2Grade"]) + ($row["test3Grade"]) + ($row["test4Grade"]) + ($row["finalExamGrade"])) / 5; if ($average >= 90) { $final = "A"; } else if ($average >= 80) { $final = "B"; } else if ($average >= 70) { $final = "C"; } else if ($average >= 60) { $final = "D"; } else if ($average < 60) { $final = "F"; } echo "<tr>"; echo "<td>" . $row["firstName"] . "</td>"; echo "<td>" . $row["lastName"] . "</td>"; echo "<td>" . $row["test1Grade"] . "</td>"; echo "<td>" . $row["test2Grade"] . "</td>"; echo "<td>" . $row["test3Grade"] . "</td>"; echo "<td>" . $row["test4Grade"] . "</td>"; echo "<td>" . $row["finalExamGrade"] . "</td>"; echo "<td>" . round($average) . "</td>"; echo "<td>" . $final . "</td>"; echo "<td><a href='delete.php?id=" . $row['studentID'] . "'>›</a></td>"; echo "<td><a href='update.php?id=" . $row['studentID'] . "'>›</a></td>"; echo "</tr>"; } echo "</table>"; ?> <a href='insert.php'>Add new student</a> </body> </html>
  5. Woody777
    Good Day guys I need some help with something that I am busy with. I have a wallpaper that need to get weather effects on it but it has to be according to the current weather status and time. The wallpaper is in the attached. I have searched the net the whole day now and cant find what I am looking for. Let me give an example: If it rains the background wallpaper must have the rainy look and be wet, when its sunny there need to be a sun and the background must be brighter. Please help me with this.
  6. pepelepew1962
    Hello: I am having a brain fart on how to get this done and any ideas would greatly be appreciated. I am working on a in-house mailbox project and have my first problem. I am going to try and explain this a simple as possible as putting the words from my head to screen harder than I thought. I have a page with 1 div called msgs_main. Inside of that div are 2 more, top one called msgs_msgs and the bottom called msgs_content. The msgs_msgs div contains a simple mysqli query displaying the records that correspond to the user. What I want/need is that when the user clicks one of the rows, the contents of the message are displayed in the msgs_content div. I could provide the code, if it helps, but I am not really looking for answered code, but a process to learn from, like. "First, get a join and have all the records display in the msg_msgs div. Display them all to see that all the data is there. Later in production, remove the un-necessary fields from top div". Then research .... etc
  7. appobs
    Are either of these OK depending on circumstance or stupid things I should never do? Is one or the other sensible/idiotic? Is there an obvious 'better' way? I think all the php tags opening and closing within the DIVs is untidy but it's static HTML therefore if there's a LOT of it it's easier on the server right/wrong? On the other hand, maybe all the open/close of php tags defeats the object. I'm applying for a web design apprenticeship (I know, I need one) so I'm trying to appear less stupid as much as make nice php. Many thanks in advance, I know I'll end up better off by asking here <?php // php in here ?> <div class='content header'> <?php include("includes/header.php"); ?> </div> <div class='content content1'> <?php include("includes/intro.php"); ?> </div> <div class='content content2'> <?php include("includes/quals.php"); ?> </div> <div class='content content3'> <?php include("includes/experience.php"); ?> </div> <div class='content content4'> <?php include("includes/hobbies-and-interests.php"); ?> </div> <?php // More php here ?> Or this one: <?php print("<div class='content header'>"); include("includes/header.php"); print("</div> \r\n <div class='content content1'>"); include("includes/intro.php"); print("</div> \r\n <div class='content content2'>"); include("includes/quals.php"); print("</div> \r\n <div class='content content3'>"); include("includes/experience.php"); print("</div> \r\n <div class='content content4'>"); include("includes/hobbies-and-interests.php"); print("</div> \r\n"); ?> test.zip
  8. jamesmargolis
    I’m trying to construct a button that simply writes an "aleph" character into a text area, see below. My code does not work, can anyone tell me why ? How should I fix it ? <!DOCTYPE html> <html> <meta charset="UTF-8"> <head> <title>Example</title> <script type="text/javascript"> //JavaScript code goes here function insertAtEnd(text) { var theArea = document.getElementById("thisArea"); theArea.value += '' + text + '';; } </script> </head> <body> <input type="button" id="aleph" name="aleph" value="Write an aleph" onClick="javascript:insertAtEnd(\'<span>א</span>\');return(false)" /> <textarea id="thisArea"> </textarea> </body> </html>
  9. brokenglass
    Hi guys, Does anyone know why my code isn't working?: $servername="127.0.0.1"; $username="root"; $password=""; $dbname="testdb"; $connection = new mysqli($servername,$username,$password); $result = "SELECT 'Country' from 'w'"; echo '<select>'; foreach($result as $res) { echo '<option value="'.$res['Country'].'">' . $res['Country'] . '</option>'; } echo '</select>'; } There's not a credential issue, the table is called 'w' and the collumn I'm trying to get the values from is 'Country' Any help is appreciated. Cheers, Broken
  10. rec0il
    Hi again PHP Freaks. So I would like to code something similar to the buy menu of Counter-strike: Global offensive in-game module, just in a browser and for a project of mine. I've made the design in photoshop to illustrate better. I just don't know what I should look into to make this kind of menu, I would love if someone could explain me what languages that this would require. (I'm guessing HTML, CSS and jQuery but I am not sure) more specific help like which particular codes would be much appreciated. Here is a picture of what I would like to create. (Also attached) http://i1227.photobucket.com/albums/ee433/rec0ill/CSGOKeyz_zps4195288a.png
  11. jamesmargolis
    I’m trying to write a post-panel where the user can see the preview of his post to the right of the text area he’s writing into. I tried the following into a file called writepost.php : <?php $text=(isset($_GET['message']))?$_GET['message']:''; $formatted_text=nl2br(stripslashes(htmlspecialchars($text))); echo '<form method="post" action="proceedtopost.php?>'. '<table>'. '<td style width="50%"><tr>'. '<fieldset> Write your post here : <br> <textarea cols="50" rows="12" '. 'id="message" name="message">'.$text.'</textarea>'. '</fieldset> <p> '. '<input type="submit" name="submit" formaction="writepost.php" value="Preview" /> '. '<input type="submit" name="submit" value="Sent" /> '. '</p>'. '</td>'. '<td>'. '<fieldset> Your post will appear as follows :<br><p> '. $formatted_text. '</fieldset>'. '</td></tr>'. '</table>'. '</form>'; There are several things wrong with this code : 1) When the user hits the "Preview" button, I expect writepost.php to be reloaded (this is what happens), and the current content of the textarea to be stored in $_GET['message'] (this is not what happens). 2) Why does my browser output the preview part under the text area (or in other words outputs the HTML table as a single column of two cells), when I insist in my HTML code for the table to be displayed as a single row ?
  12. lordterrin
    I have a page that functions like this: The user begins by loading ajaxtest.php, then using a drop-down menu, selects a user, after which a DIV on ajaxtest.php is populated with the user's selction to getuser.php?q=John%Doe Here's a visual representation of what is currently happening, along with the part I don't understand. getuser.php consists largely of a a large HTML table which interacts through PHP with my SQL database. Several of the fields in this table are editable, and after the user changes one of these fields, he can press an "update" button, which calls an AJAX script in update.js and runs update.php, which contains all my SQL queries to update the database, without the user being redirected to this update.php page. All of this is processing perfectly - the user makes some sort of edit, hits "update", and the database gets updated without any redirection or refresh. Here's what I can't figure out though. Once the user makes a change, and hits "update," the database updates, but the end user doesn't see those changes that he made. I can't just do a simple page refresh, because the action is taking place on getuser.php, but getuser.php is loaded inside of a #DIV on ajaxtest.php. If I use something like window.location.reload(), this just refreshes ajaxtest.php and puts the user back to the starting point of having to select a user. This is not what I want. I don't want to refresh ajaxtest.php, I want to "refresh" ajaxtest.php with getuser.php?q=John%Doe insidethe DIV on ajaxtest.php. It seems like this is very common - several forums have this capability, where a user has a page loaded, adds a comment, and sees that comment immediately without a full page refresh. I just don't know how to do it, and I've tried at lengths to search the web for an answer with no luck. Can someone walk me through how to do this?
  13. tpass
    Hello - hope you are all well. I am creating a website for a family friend who has a shop. See preview of the site in this picture .... Currently the results are showing in one column. I want to show them in three columns in the format of: 1 2 3 4 5 6 7 8 9 etc But formatted with the picture and then the title and the border. The current code i have is.... HEAD <?php $sql = "SELECT * FROM abs_productcat WHERE catid = $catid ORDER BY catid ASC"; $can = mysql_query($sql); $catname = mysql_fetch_assoc($can); ?> BODY <?php while ($row_pro = mysql_fetch_assoc($rs_proddetails)) { ?><tr> <td><table width="243" border="0" align="left" cellpadding="15" cellspacing="0" class="sectionborders"> <tr> <td height="120" align="center"><p><strong><a href="indproducts.php?ProductID=<?php echo $row_pro['ProductID']; ?>"><img src="products/product_<?php echo $row_pro['ProductID']; ?>" alt="<?php echo $row_pro['ProductName']; ?>" height="120" class="sectionborders" border="0" /></a></strong></p> <p><strong><a href="indproducts.php?ProductID=<?php echo $row_pro['ProductID']; ?>" class="products"><?php echo $row_pro['ProductName']; ?></a></strong></p></td> </tr> </table></td> </tr> <tr> <td> </td> </tr> <?php } ?> THANK YOU FOR YOUR HELP!!!
  14. bogdaniel
    Hello I have an array with data from `mysql` that I would like to output it in a table using twig. The image is an example of want i want to achieve but without any luck. `print_r` of the array data Array ( [Administrator] => Array ( [0] => Array ( [RoleName] => Administrator [PermissionName] => Catalog-View [PermissionId] => 1 ) [1] => Array ( [RoleName] => Administrator [PermissionName] => Catalog-Edit [PermissionId] => 2 ) [2] => Array ( [RoleName] => Administrator [PermissionName] => Catalog-Delete [PermissionId] => 3 ) ) [Moderator] => Array ( [0] => Array ( [RoleName] => Moderator [PermissionName] => Catalog-View [PermissionId] => 1 ) ) ) The `HTML` code: <table> <tr> <thead> <th>Controller - Action</th> {% for permission in permissions %} {% for item in permission %} <th>{{item.RoleName}}</th> {% endfor %} {% endfor %} </thead> </tr> {% for permission in permissions %} {% for item in permission %} <tr> <td>{{item.PermissionName}}</td> <td>{{item.PermissionId}}</td> </tr> {% endfor %} {% endfor %} </table> OUTPUT: <table> <tbody> <tr></tr> </tbody> <thead> <tr> <th>Controller - Action</th> <th>Administrator</th> <th>Administrator</th> <th>Administrator</th> <th>Moderator</th> </tr> </thead> <tbody> <tr> <td>Catalog-View</td> <td>1</td> </tr> <tr> <td>Catalog-Edit</td> <td>2</td> </tr> <tr> <td>Catalog-Delete</td> <td>3</td> </tr> <tr> <td>Catalog-View</td> <td>1</td> </tr> </tbody> </table> Later Edit MySQL Query: SELECT t3.PermissionName, t1.PermissionId, t2.RoleName FROM tbl_user_role_perm AS t1 INNER JOIN tbl_user_roles AS t2 ON t1.RoleId = t2.RoleId INNER JOIN tbl_user_permissions AS t3 ON t1.PermissionId = t3.PermissionId MySQL Dump: -- Dumping structure for table tbl_user_permissions CREATE TABLE IF NOT EXISTS `tbl_user_permissions` ( `PermissionId` int(11) NOT NULL AUTO_INCREMENT, `PermissionName` varchar(50) NOT NULL, `PermissionDescription` varchar(100) NOT NULL, PRIMARY KEY (`PermissionId`) ) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=latin1; -- Dumping data for table tbl_user_permissions: ~2 rows (approximately) DELETE FROM `tbl_user_permissions`; /*!40000 ALTER TABLE `tbl_user_permissions` DISABLE KEYS */; INSERT INTO `tbl_user_permissions` (`PermissionId`, `PermissionName`, `PermissionDescription`) VALUES (1, 'Catalog->View', 'View Catalog Method'), (2, 'Catalog->Edit', 'Edit Catalog Method'), (3, 'Catalog->Delete', 'Delete Catalog Method'); /*!40000 ALTER TABLE `tbl_user_permissions` ENABLE KEYS */; -- Dumping structure for table tbl_user_role CREATE TABLE IF NOT EXISTS `tbl_user_role` ( `UserRoleId` int(10) NOT NULL AUTO_INCREMENT, `UserId` int(10) NOT NULL, `RoleId` int(10) unsigned NOT NULL, PRIMARY KEY (`UserRoleId`), KEY `FK_tbl_user_role_tbl_user_roles` (`RoleId`), KEY `UserId` (`UserId`) ) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=latin1; -- Dumping data for table tbl_user_role: ~2 rows (approximately) DELETE FROM `tbl_user_role`; /*!40000 ALTER TABLE `tbl_user_role` DISABLE KEYS */; INSERT INTO `tbl_user_role` (`UserRoleId`, `UserId`, `RoleId`) VALUES (1, 13, 22), (2, 14, 22); /*!40000 ALTER TABLE `tbl_user_role` ENABLE KEYS */; -- Dumping structure for table tbl_user_roles CREATE TABLE IF NOT EXISTS `tbl_user_roles` ( `RoleId` int(10) unsigned NOT NULL AUTO_INCREMENT, `RoleName` varchar(50) NOT NULL, `CreatedDate` datetime NOT NULL, `ModifiedDate` datetime DEFAULT NULL ON UPDATE CURRENT_TIMESTAMP, PRIMARY KEY (`RoleId`) ) ENGINE=InnoDB AUTO_INCREMENT=29 DEFAULT CHARSET=utf8; -- Dumping data for table tbl_user_roles: ~7 rows (approximately) DELETE FROM `tbl_user_roles`; /*!40000 ALTER TABLE `tbl_user_roles` DISABLE KEYS */; INSERT INTO `tbl_user_roles` (`RoleId`, `RoleName`, `CreatedDate`, `ModifiedDate`) VALUES (22, 'Administrator', '2014-10-28 09:53:08', NULL), (23, 'Moderator', '2014-10-28 09:53:13', NULL), (24, 'Admin', '2014-10-28 12:22:05', '2014-10-28 12:22:06'), (25, 'User', '2014-10-29 15:10:36', '2014-10-29 15:10:37'), (26, 'SuperUser', '2014-10-29 15:10:45', '2014-10-29 15:10:46'), (27, 'Accountant', '2014-10-29 15:10:53', '2014-10-29 15:10:54'), (28, 'God', '2014-10-29 15:11:02', '2014-10-29 15:11:02'); /*!40000 ALTER TABLE `tbl_user_roles` ENABLE KEYS */; -- Dumping structure for table tbl_user_role_perm CREATE TABLE IF NOT EXISTS `tbl_user_role_perm` ( `RoleId` int(10) unsigned NOT NULL, `PermissionId` int(10) unsigned NOT NULL, KEY `RoleId` (`RoleId`), KEY `PermissionId` (`PermissionId`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8; -- Dumping data for table tbl_user_role_perm: ~3 rows (approximately) DELETE FROM `tbl_user_role_perm`; /*!40000 ALTER TABLE `tbl_user_role_perm` DISABLE KEYS */; INSERT INTO `tbl_user_role_perm` (`RoleId`, `PermissionId`) VALUES (22, 2), (22, 1), (23, 1), (22, 3); /*!40000 ALTER TABLE `tbl_user_role_perm` ENABLE KEYS */; /*!40101 SET SQL_MODE=IFNULL(@OLD_SQL_MODE, '') */; /*!40014 SET FOREIGN_KEY_CHECKS=IF(@OLD_FOREIGN_KEY_CHECKS IS NULL, 1, @OLD_FOREIGN_KEY_CHECKS) */; /*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */; Can you help me to make the coding required so that the correct column have the correct permissions? thank you in advance.
  15. jason360
    am coming across the problem. When I use copied text in my input form it gives some characters this � character. I am not sure how to post text so this doesn't happen. Example: This line copied: The 976cc, 101-hp Rotax® 1000R V-Twin engine is known for its reliable power. Produces: The 976cc, 101-hp Rotax� 1000R V-Twin engine is Can-Am's most powerful side-by-side engine. My code: if (get_magic_quotes_gpc()) { $description_clean_magic = stripslashes($description); } else { $description_clean_magic = $description; }
  16. evgenyvo
    Hi All, I'm trying to return HTML page contains the Russian characters sent as POST variables and also static data as part of HTML result. I'm not able to put it work together. If I set windows-1251 - the static data displayed incorrectly. If I set UTF-8 - the dynamic (POST) data displayed incorrectly Any thoughts? Thank you very much in advance, Evgeny Following is the simple HTML example and also Fiddler request example <?php header('Content-Type: text/html;charset=windows-1251'); $firstName = $_POST["from"]; $subject = $_POST["subject"]; $message = $_POST["message"]; $version = phpversion(); $messageToSend = " <html> <meta http-equiv='Content-Type' content='text/html; charset=windows-1251'> <head> <title>Christiada2033 automatic email</title> </head> <body> <p>Static russian: По-русски</p> <table> <tr> <td>Version:</td> <td>$version </tr> <tr> <td>Static russian: Отправитель:</td> <td>Post value russian: $firstName</td> </tr> <tr> <td>Static russian: Тема:</td> <td>Post value russian: $subject</td> </tr> <tr> <td>Static russian: Сообщение:</td> <td>Post value russian: $message</td> </tr> </table> </body> </html> "; printf($messageToSend); die(); ?> =====================Fiddler===================== POST http://myhost/mysite/mail_html2.php HTTP/1.1 Host: myhost Connection: keep-alive Content-Length: 132 Cache-Control: max-age=0 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8 Origin: http://localhost User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/38.0.2125.111 Safari/537.36 Content-Type: application/x-www-form-urlencoded Referer: http://myhost/mysite/Mail_Html2.shtml Accept-Encoding: gzip,deflate Accept-Language: en-GB,en;q=0.8,en-US;q=0.6,ru;q=0.4,he;q=0.2 from=%C8%E2%E0%ED+%CF%E5%F2%F0%EE%E2&subject=%D2%E5%EC%E0&message=%CF%F0%E8%E2%E5%F2%2C+%EF%F0%E8%E2%E5%F2%21&submit=Submit+Feedback =====================Fiddler=====================
  17. PaulRyan
    Hello, I'm Paul Ryan. I am 23 years old and have around 8 years experience in programming with the following languages: - PHP - MySQLi - HTML - CSS - JavasScript (jQuery, AJAX) I have worked on many project over the years, including the following: - BoxSelect.com - Taccd.com - FTA.ie - BelfastCookerySchool.com - Dittnyebad.no - MassasjeShop.no - Project: Universe (Personal Project) I have worked on many other smaller jobs, updating outdated code, database and code optimizations etc. You can contact me via the following methods: - PHP Freaks Personal Message - Skype: paulryanmc91 - E-mail: paul.ryan.mclaughlin@gmail.com I am available to start work immediately whether the job be big or small, don't hesitate to contact me. Thanks for your time, look forward to hearing from you. Kind Regards, Paul Ryan
  18. minat0
    Hi there, I want to pass a input variable from login_success.php which will be sent to sqlprocess.php as the variable 'SQLinput'; sqlprocess.php $link = mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $query = $_REQUEST['SQLinput']; //You don't need a ; like you do in SQL $result = mysql_query($query); $numfields = mysql_num_fields($result); login_sucess.php <form action="" method="post" <label> <span>SQL Input :</span> <input type ="text" id="message" name="SQLinput" placeholder="Input SQL"></textarea> </label> <label> <span>SQL Output :</span> <output id="text" id="SQLoutput" ></input> <script type="text/javascript" charset="utf-8"> // handles the click event for link 1, sends the query function getOutput() { getRequest( 'sqlprocess.php', // URL for the PHP file drawOutput, // handle successful request drawError // handle error ); return false; } // handles drawing an error message function drawError () { var container = document.getElementById('output'); container.innerHTML = 'Bummer: there was an error!'; } // handles the response, adds the html function drawOutput(responseText) { var container = document.getElementById('output'); container.innerHTML = responseText; } // helper function for cross-browser request object function getRequest(url, success, error) { var req = false; try{ // most browsers req = new XMLHttpRequest(); } catch (e){ // IE try{ req = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { // try an older version try{ req = new ActiveXObject("Microsoft.XMLHTTP"); } catch (e){ return false; } } } if (!req) return false; if (typeof success != 'function') success = function () {}; if (typeof error!= 'function') error = function () {}; req.onreadystatechange = function(){ if(req .readyState == 4){ return req.status === 200 ? success(req.responseText) : error(req.status) ; } } req.open("GET", url, true); req.send(null); return req; } </script> <a href="#" onclick="return getOutput();"><button type="submit" id="search_btn" value="Submit">Submit</button> </a> <div id="output">waiting for action</div> Prior to the JS code - I was able to peform this action - however the JS code enables me to post the query onto the same page. I would like essentially like to query the database through an input box and output the same result on the same page. Thanks!
  19. minat0
    Hi there, This may not be the correct space to post this - but I'm very new to all this. I've created a page that will run a php script to output a query. I would then like to send that same query via email - however from a design perspective I don't think the correct process is to click 'submit' to view the query and then 'submit' to send the result via email? Can you please advise on some design solutions regarding this issue? Thanks!
  20. bgreen0704
    I am partnered with a marketing company located in downtown Chicago that is in need of a Sr. PHP Developer. This person will be designing, planning, and building complex content and data management systems from the ground up utilizing PHP technologies and frameworks. This is a permanent/direct hire opportunity. Must have experience with: CodeIgniter or Laravel frameworks GIT or SVN Front end technologies (HTML, CSS, etc.) Salary expectations: $100k - $125k (based on experiene) If interested please send resumes/inquries to Brittany Green at bgreen@awistaffing.com Please note: We do not offer sponsorship at this time (h1b, L2, etc.)
  21. Woody777
    Hi there guys I have a problem that I can't seem to get fixed. Below Is the code I am using and the Link to the Tutorial: http://fearlessflyer.com/create-an-awesome-photo-gallery-with-fancybox-and-timthumb/ <?php $path = 'http://' . $_SERVER['SERVER_NAME'] . 'moment/uploads/'; $files = scandir('uploads/'); ?> <ul> <?php foreach ($files as $file){ if ($file == '.' || $file == '..'){ echo ''; } else { ?> <li ><a href="<?php echo $path . $file; ?>" rel="lightbox"><img src="timthumb.php?src=<?php echo $path . $file; ?>&h=194&w=224&zc=1&q=100" /></a></li> <?php } }?> </ul> <!-- FANCYBOX --> <script type='text/javascript' src='assets/js/jquery.fancybox.js'></script> <script type='text/javascript' src='assets/js/jquery.mousewheel-3.0.6.pack.js'></script> <link rel='stylesheet' href='assets/css/jquery.fancybox.css' /> <script> $(document).ready(function(){ $("a[rel=lightbox]").fancybox({ 'transitionIn' : 'elastic', 'transitionOut' : 'elastic' }); }); </script> My pictures and everything is working but when I click on the image to open up in a lightbox it gives me an error: The Requested Content Cannot Be Loaded, Please Try Again Later. In the attached is a image of the error
  22. OsirisElKeleni
    Hello everyone, i'm Osiris and i'm stuck with this PHP/HTML code, i'm fairly new at this so this might be a dumb question. i have a database, but i want to output all data into a table from the database using HTML codes. i had it so far that i could outpust the info in just plain text but it doesn't output in the HTML table. Can anyone see what i did wrong? This is my PHP code its in the body section <?php $dbhost = 'localhost'; $dbuser = 'root'; $dbpass = 'password'; $conn = mysql_connect($dbhost, $dbuser, $dbpass); if(! $conn ) { die('Could not connect: ' . mysql_error()); } $sql = 'SELECT `Name`, `Color`, `Type`, `Subtype`, `Power`, `Toughness`, `Manacost`, `Rarity`, `Expansion`, `Foil`, `Stock` FROM `mtgtabel`'; mysql_select_db('mtgstock'); $retval = mysql_query( $sql, $conn ); if(! $retval ) { die('Could not get data: ' . mysql_error()); } echo '<table class=mytable>'; echo "<tr><th >Name</th><th >Color</th><th >Type</th><th >Sub Type</th><th >Power</th><th >Toughness</th><th >Converted mana cost</th><th >Rarity</th><th >Expansion</th><th >Foil</th><th >Stock</th></tr>"; while($row = mysql_fetch_array($retval, MYSQL_ASSOC)) { echo "<tr><td>"; echo $row['Name'] echo "</td><td>"; echo $row['Color']; echo "</td><td>"; echo $row['Type']; echo "</td><td>"; echo $row['Subtype']; echo "</td><td>"; echo $row['Power']; echo "</td><td>"; echo $row['Toughness']; echo "</td><td>"; echo $row['Manacost']; echo "</td><td>"; echo $row['Rarity']; echo "</td><td>"; echo $row['Expansion']; echo "</td><td>"; echo $row['Foil']; echo "</td><td>"; echo $row['Stock']; echo "</td></tr>"; } echo "</table>"; mysql_close($conn); ?> Thanks in advance!
  23. enemeth
    Hello All, I have been going crazy trying to figure this out, I hope someone can help me out I have header and footer.php files that on all my pages I get them to load with include, but for some strange reason, this certain page it will not load I did some research and apparently theres problems with div and php, does anyone know how to make this work? Thank you in advance, Elaine test.txt
  24. kjetterman
    When I click on the letter of the alphabet on my form page, it will bring up the results of my query. I got this part working. The next part is to be able to click on any of the populated results and have it autofill my form with organization, first name, last name, email address and phone number. I know that I need to use Ajax and jQuery to accomplish this. Here is my html <!-- Letter Search --> <div class="searchBox span12"> <h3>Choose the First Letter of the Person's Last Name</h3> <ul> <li class="alphabets" id="A"><a href="?by=A">A</a></li> <li class="alphabets" id="B"><a href="?by=B">B</a></li> <li class="alphabets" id="C"><a href="?by=C">C</a></li> <li class="alphabets" id="D"><a href="?by=D">D</a></li> <li class="alphabets" id="E"><a href="?by=E">E</a></li> <li class="alphabets" id="F"><a href="?by=F">F</a></li> <li class="alphabets" id="G"><a href="?by=G">G</a></li> <li class="alphabets" id="H"><a href="?by=H">H</a></li> <li class="alphabets" id="I"><a href="?by=I">I</a></li> <li class="alphabets" id="J"><a href="?by=J">J</a></li> <li class="alphabets" id="K"><a href="?by=K">K</a></li> <li class="alphabets" id="L"><a href="?by=L">L</a></li> <li class="alphabets" id="M"><a href="?by=M">M</a></li> <li class="alphabets" id="N"><a href="?by=N">N</a></li> <li class="alphabets" id="O"><a href="?by=O">O</a></li> <li class="alphabets" id="P"><a href="?by=P">P</a></li> <li class="alphabets" id="Q"><a href="?by=Q">Q</a></li> <li class="alphabets" id="R"><a href="?by=R">R</a></li> <li class="alphabets" id="S"><a href="?by=S">S</a></li> <li class="alphabets" id="T"><a href="?by=T">T</a></li> <li class="alphabets" id="U"><a href="?by=U">U</a></li> <li class="alphabets" id="V"><a href="?by=V">V</a></li> <li class="alphabets" id="W"><a href="?by=W">W</a></li> <li class="alphabets" id="X"><a href="?by=X">X</a></li> <li class="alphabets" id="Y"><a href="?by=Y">Y</a></li> <li class="alphabets" id="Z"><a href="?by=Z">Z</a></li> </ul> <? include('search.php'); ?> </div> <hr style="color:#ccc; margin-bottom:20px;" /> <!-- Main Form --> <div id="mainForm"> <form method="post" id="icsForm" class="searchBox span12"> <div id="col1" class"span6"> <h3>Contact Information</h3> <label>Church / Organization:</label><input type="text" name="organization" id="organization" class="span6 upright" /><br /> <label>First Name:</label><input type="text" name="firstName" id="firstName" class="span6 upright" /> <label>Last Name:</label><input type="text" name="lastName" id="lastName" class="span6 left upright" /> <label>Email Address:</label><input type="text" name="email" id="email" class="span6 left upright" /> <label>Phone Number:</label><input type="text" name="phone" id="phone" class="span6 left upright" /> </div> </div> Here is my php if(preg_match("/^[A-Z | a-z]+/", $_POST['name'])){ $name=$_POST['name']; } if(isset($_GET['by'])){ $letter=$_GET['by']; //query to sort by last name $sql="SELECT contact_id, first_name, last_name, church_org, email_address, phone_number FROM ics_data WHERE last_name LIKE '$letter%' ORDER BY last_name ASC"; //run the query against the mysql query function $result=mysql_query($sql); //count results $numrows=mysql_num_rows($result); echo "<p>" .$numrows . " results found for " . $letter . "</p>"; //Create while loop and loop through result set while($row=mysql_fetch_array($result)){ $first_name=$row['first_name']; $last_name=$row['last_name']; $church_org=$row['church_org']; $email_address=$row['email_address']; $phone_number=$row['phone_number']; $contact_id=$row['contact_id']; //display the result of the array echo "<div id=\"search-results\">"; echo "<ul class=\"letter-results\">\n"; echo "<li class=\"result-row\">" . "<a href=\"#\" class=\"testclass\">" .$first_name . " " .$last_name . "". ", " ."" .$church_org ."</a></li>\n"; echo "</ul>"; echo "</div>"; } } Here is my Javascript file (Ajax) $(document).ready( function() { function formfill() { var organization = $('#organization').val(); var firstname = $('#firstname').val(); var lastname = $('#lastname').val(); var email = $('#email').val(); var phone = $('#phone').val(); $.ajax ({ method: "GET", url: "search.php", dataType: 'json', data: { organization:organization, firstname:firstname, lastname:lastname, email:email, phone:phone }, type: "POST", success: function(data) { $organization $firstname $lastname $email $phone }, failure: function() { alert('fail!'); } }); } I know that I do not have a reference yet to JSON in my php file and that it is needed. I'm not solid on the Ajax part. That is the part that is tripping me up. I know that I need to make the form autofill when clicking on a specific result returned from my query... but i'm not sure how to do that. Thank you in advance for any help or advice you can give!! I am relatively new to programming. Hopefully I posted this in the right forum as a lot of these technologies overlap.
  25. manjumadhav93
    Hi experts,I have the following problem.I have a file login.php which is used to allow users to log in.When the form is submitted it is redirected to checkuserlogin.php.If the credentials are right he is redirected to main.php.But in main.php if the user clicks back browser button,he is redirected to login.php and in login.php if he presses forward button,he is redirected to main.php.Can any one tell he how to make sure the application is not redirected to main.php when user presses forward button and how to make sure the application is not redirected to login.php when user presses back button.
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