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Hi, I want to make a select from mysql to show some data in page. To show a table with data from mysql but limited to only 5 and this to show total number of rows. I'm thinking to make two selects. SELECT count(*) FROM table1 and after that to use mysql_num_rows to count total number in that table. Then another SELECT name,prename FROM table1 LIMIT 1, 5 to show only first 5 rows. It's there a way to use only one select insted of two but having the same results ? Thanks

I am trying to use a <select> <option> to display text on a web page. The data comes from a database. This is what I am attempting: When an option is selected and submit button clicked them some text will be displayed. At the moment I do have text on the web page, but none of the selected options change this. I have four pieces of text: Page 1, Page 2 etc. At the moment Page 4 text is displayed. I would like each piece of text to be displayed. This is the php: <?php // Connect to the database $pdo = new PDO("mysql:host=localhost;dbname=###", "###", ""); $sql = "SELECT * FROM testdb ORDER BY id"; try { $stmt = $pdo->prepare($sql); $stmt->execute(); $data = $stmt->fetchAll(); } catch(Exception $ex){ echo ($ex -> getMessage()); } ?> This is the html: <form name="###" method="post" action="#"> <p></p> <select onchange="reload(this.form)"> <option>test one</option> <?php foreach ($data as $output) { ?> <option value=''><?php echo $output['header']; ?></option> <?php } ?> </select> <br> <button type="submit" value="submit">Submit</button> </form> <?php echo $output['pages']; ?> I would appreciate help with this. However, from previous attempts at adding data to a page I used isset() and I think $_POST(), possibly together. If these are the things I need to use, then please could you include their usage within any examples you feel would help. Thank you.

Hi, Thanks for taking the time. I'm trying PDO for the first time and I'm trying to make a CRUD codebase. I can insert but I have trouble with the select statement and iterate through the data, Apache gives me this error: Fatal error: Uncaught Error: Call to a member function fetch_assoc() on boolean in index.php:38 This is line 38: $getName = $result; while( $row = $getName->fetch_assoc() ){ echo $row['name']; } This is my code: $pdo = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password); // set the PDO error mode to exception $pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $stmt = $pdo->prepare("SELECT name FROM users"); $stmt->execute(); // set the resulting array to associative $result = $stmt->setFetchMode(PDO::FETCH_ASSOC); $getName = $result; //Iterate through the data // line 38: while( $row = $getName->fetch_assoc() ){ echo $row['name']; }

Hello there friends I have an select box and I would like to define the alue of the selects with array. Like this: var price_list= new Array(); price_list["-"]=0; price_list["bronze"]=5; price_list["silver"]=10; price_list["gold"]=15; The I have a Selectbox where <form action="" id="metal" onsubmit="return false;" <select id="a" name="metals" class="form-select"> <option value="-">-</option> <option value="bronze">bronze</option> <option value="silver">silver</option> <option value="gold">gold</option> </select> And performig calculations with following script (that works fine if the value is directly in select). And obviously there is another select (#b) but that is just numbers so I didn show it here. $(document).ready(function() { function compute() { var a = $('#metals').val(); var b = $('#b').val(); var total = a * b * 1.22; $('#result').text(total); } $('#metals, #b').change(compute); }); I just get returned NaN If you have an answer then please hit

Im having trouble on my php script. it is working on my computer but when I put it in x10hosting it fails and gives an error 500. I tried tracing the problem and I found out that it happens if I call get_result. Here is the part code: $username = strtolower(filter_input(INPUT_POST, 'username')); $password = filter_input(INPUT_POST, "password"); $remember = filter_input(INPUT_POST, "remember"); $result = array(); include 'Connection.php'; $query = "SELECT Number, Username, Password, Alias, Level FROM user WHERE Username = ?;"; $stmt = $conn->prepare($query); if(!$stmt->prepare($query)) { die( "Failed to prepare statement."); } $stmt->bind_param("s", $username); $stmt->execute(); echo $stmt->error; //error hapens here $selectResult = $stmt->get_result();

I'm looking to replace a select dropdown with images. My current code for the drop down is <div class="app_services_dropdown_select"> <select name="app_select_services" class="app_select_services"> <option value="1" selected="selected">Class IV MOT (Up to 3,000KG)</option> <option value="2">Class VII MOT (3,000KG - 3,500KG)</option></select> <input type="button" class="app_services_button" value="Show available times"> </div> Which is generated by this code: $s .= '<div class="app_services">'; $s .= '<div class="app_services_dropdown">'; $s .= '<div class="app_services_dropdown_title">'; $s .= $select; $s .= '</div>'; $s .= '<div class="app_services_dropdown_select">'; $s .= '<select name="app_select_services" class="app_select_services">'; if ( $services ) { foreach ( $services as $service ) { $service_description = ''; // Check if this is the first service, so it would be displayed by default if ( $service->ID == $appointments->service ) { $d = ''; $sel = ' selected="selected"'; } else { $d = ' style="display:none"'; $sel = ''; } // Add options $s .= '<option value="'.$service->ID.'"'.$sel.'>'. stripslashes( $service->name ) . '</option>'; } } $s .= '</select>'; $s .= '<input type="button" class="app_services_button" value="'.$show.'">'; $s .= '</div>'; $s .= '</div>'; And I really want an image of a car as value 1 and a van as value 2, plus I really want it to submit on click rather than having the button. Is it possible to replace the dropdown with images instead or would I need to use a radio button, then style it using an image? You can see my current dropdown in use here