Jump to content

Search the Community

Showing results for tags 'form data'.

More search options

  • Search By Tags

    Type tags separated by commas.
  • Search By Author

Content Type


  • Welcome to PHP Freaks
    • Announcements
    • Introductions
  • PHP Coding
    • PHP Coding Help
    • Regex Help
    • Third Party Scripts
    • FAQ/Code Snippet Repository
  • SQL / Database
    • MySQL Help
    • PostgreSQL
    • Microsoft SQL - MSSQL
    • Other RDBMS and SQL dialects
  • Client Side
    • HTML Help
    • CSS Help
    • Javascript Help
    • Other
  • Applications and Frameworks
    • Applications
    • Frameworks
    • Other Libraries
  • Web Server Administration
    • PHP Installation and Configuration
    • Linux
    • Apache HTTP Server
    • Microsoft IIS
    • Other Web Server Software
  • Other
    • Application Design
    • Other Programming Languages
    • Editor Help (Dreamweaver, Zend, etc)
    • Website Critique
    • Beta Test Your Stuff!
  • Freelance, Contracts, Employment, etc.
    • Services Offered
    • Job Offerings
  • General Discussion
    • PHPFreaks.com Website Feedback
    • Miscellaneous

Find results in...

Find results that contain...

Date Created

  • Start


Last Updated

  • Start


Filter by number of...


  • Start





Website URL








Donation Link

Found 1 result

  1. Hi all, I have a form that submits data to a mysql db. It's working fine. What I am trying to do is output an html page (or possibly 2) that is propagated with the data that I just sent to the db. example: when I submit a new workorder, a page comes up with all the data i just submitted. so that can be printed as a "customer copy". and in a perfect world, another page comes up that is a material order form. That can be faxed to my vendor to order the materials for that job. Not looking to auto print or fax anything. I am just having trouble getting the data into my html page. Here is what I have, but sadly is not working. <?php $link = mysqli_connect("xxxx", "xxxx", "xxxx", "xxxx"); $sql = "SELECT customer FROM jobs WHERE id=6487"; echo $sql; mysqli_close($link); ?> I would like to use the data from the last id submitted and have tried several things like: WHERE id=mysqli::$insert_id and WHERE id=$insert_id with no luck. Here is a pic of the html form and the output i'm getting. Any help would be greatly appreciated. Thanks in advance. OGBugsy
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.