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insert command, super easy fix.

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#1 eddorey2k3

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Posted 19 May 2006 - 10:16 PM

I'm sure this is a super simple fix, but for some reason I'm not seeing it. Any help would be good.

The PHP is designed to capture certain information about the site visitor, and then store them in a database. Simple, really. The information is being captured, but for some reason, it's inputting the variable names into the database, instead of the values.

It connects to the database correctly, and picks up the right table. The problem is that it submits the variable names, instead of the value.....even though I've already said that.

The original code was obtained from the PHP website (I believe), but that used static values instead of dynamic variables.

I'm assuming it's something to do with the variable names being in brackets?

Code below. (The relevant section)

$date = date("D dS F, Y");
$time = date("g:i:sa"); //find out how to get this back into GMT
$referer = $_SERVER['HTTP_REFERER'];
$useragent = $_SERVER['HTTP_USER_AGENT'];
/*Adds the data to the database*/

$db = "databasename";
$result = mysql_select_db($db) or die("Unable to select the database, but could connect to server");

$adduserinfo = 'INSERT INTO `userlogging` (`ID`, `date`, `time`, `IP`, `browser`, `referer`) VALUES (\'\', \'$date\', \'$time\', \'$ip\', \'$useragent\', \'$referer\')';
$adduserinforesult = mysql_query($adduserinfo) or die ("Error in query $adduserinfo");

#2 .josh

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Posted 19 May 2006 - 10:20 PM

try this alternate method:

$adduserinfo = "INSERT INTO userlogging (ID, date, time, IP, browser, referer) VALUES ('', '$date', '$time', '$ip', '$useragent', '$referer')";

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#3 eddorey2k3

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Posted 20 May 2006 - 10:41 AM

Works like a charm. Thanks a lot!

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