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Passing array as param


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Are you trying to generate an URL from an array? In your example, you're using "param" as a name in the query string twice. That's impossible. If you want to 'convert' an array's keys and values into names and values in a query string, this'll do:


$url = 'http://url.com?';
$array = array('name' => 'Joe', 'age' => 23);
foreach ($array as $key => $val) {
$url .= "$key=$val&";
$url = substr($url, 0, -1);
echo $url;
// http://url.com?name=Joe&age=23

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