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#1 visken

visken
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Posted 15 June 2006 - 11:57 AM

Hi all,

I am new to PHP and need your help with the following:

I want to construct the following array named $arr_user_movie: (n is number of user and m is number of movies)
array ([1]=>array([1]=>0/1
[2]=>0/1
[3]=>0/1
...
[m]=>0/1
array ([2]=>array([1]=>0/1
[2]=>0/1
[3]=>0/1
...
[m]=>0/1
......
array ([n]=>array([1]=>0/1
[2]=>0/1
[3]=>0/1
...
[m]=>0/1

example of use: $arr_user_movie[6][86] has to contain a 1 if user 6 has watched movie with id86, 0 otherwise

I made the following script, however at the end when I check the value PHP doesn't return anything!

When I insert 'echo $arr_user_movie[6][86] before line 'for ($user_id=1; $user_id<=NUMBERUSERS; $user_id++)', then PHP returns 1.

Can you help me?


arr_movie=array(1=>1);
for ($j=2; $j<=NUMBERMOVIES; $j++)
{
$arr_movie[]=1;//zo voeg je telkens een veld toe
}

$i=1;
$arr_user_movie=array($i=>$arr_movie);

for($i=2; $i<=NUMBERUSERS; $i++)
{
$arr_user_movie[]=$arr_movie;
}
// $arr_user_movie[x][x] bevat een waarde 1


for ($user_id=1; $user_id<=NUMBERUSERS; $user_id++)
{
for ($movie_id=1; $movie_id<=NUMBERMOVIES; $movie_id++)
{
$query_user_movie="select * from rating
where user_id=".$user_id."
and movie_id=".$movie_id."";
$result_user_movie=mysql_query($query_user_movie, $connect);
$num_results_user_movie=mysql_num_rows($result_user_movie);
// if an entry found then set 1 else set 0:
if ($num_results_user_movie==0)
{
$arr_user_movie[$user_id][$movie_id]=1;
}
else
{
$arr_user_movie[$user_id][$movie_id]=0;
}
}
}

echo $arr_user_movie[1][1];

#2 visken

visken
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Posted 15 June 2006 - 12:37 PM

Hi

maybe I have explained my problem not well. Therefore my first problem:

How do you create the following array?
(n is number of user and m is number of movies)
array ([1]=>array([1]=>0/1
                         [2]=>0/1
                         [3]=>0/1
                   ...
                         [m]=>0/1
array ([2]=>array([1]=>0/1
                         [2]=>0/1
                         [3]=>0/1
                   ...
                         [m]=>0/1
......
array ([n]=>array([1]=>0/1
                         [2]=>0/1
                         [3]=>0/1
                   ...
                         [m]=>0/1


Thank you for your help!!!

[!--quoteo(post=384141:date=Jun 15 2006, 01:57 PM:name=visken)--][div class=\'quotetop\']QUOTE(visken @ Jun 15 2006, 01:57 PM) View Post[/div][div class=\'quotemain\'][!--quotec--]
Hi all,

I am new to PHP and need your help with the following:

I want to construct the following array named $arr_user_movie: (n is number of user and m is number of movies)
array ([1]=>array([1]=>0/1
[2]=>0/1
[3]=>0/1
...
[m]=>0/1
array ([2]=>array([1]=>0/1
[2]=>0/1
[3]=>0/1
...
[m]=>0/1
......
array ([n]=>array([1]=>0/1
[2]=>0/1
[3]=>0/1
...
[m]=>0/1

example of use: $arr_user_movie[6][86] has to contain a 1 if user 6 has watched movie with id86, 0 otherwise

I made the following script, however at the end when I check the value PHP doesn't return anything!

When I insert 'echo $arr_user_movie[6][86] before line 'for ($user_id=1; $user_id<=NUMBERUSERS; $user_id++)', then PHP returns 1.

Can you help me?
arr_movie=array(1=>1);
for ($j=2; $j<=NUMBERMOVIES; $j++)
{
$arr_movie[]=1;//zo voeg je telkens een veld toe
}

$i=1;
$arr_user_movie=array($i=>$arr_movie);

for($i=2; $i<=NUMBERUSERS; $i++)
{
$arr_user_movie[]=$arr_movie;
}
// $arr_user_movie[x][x] bevat een waarde 1
for ($user_id=1; $user_id<=NUMBERUSERS; $user_id++)
{
for ($movie_id=1; $movie_id<=NUMBERMOVIES; $movie_id++)
{
$query_user_movie="select * from rating
where user_id=".$user_id."
and movie_id=".$movie_id."";
$result_user_movie=mysql_query($query_user_movie, $connect);
$num_results_user_movie=mysql_num_rows($result_user_movie);
// if an entry found then set 1 else set 0:
if ($num_results_user_movie==0)
{
$arr_user_movie[$user_id][$movie_id]=1;
}
else
{
$arr_user_movie[$user_id][$movie_id]=0;
}
}
}

echo $arr_user_movie[1][1];
[/quote]





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