I've just started to learn PHP and I need some help with a script, what I'm looking for is a script that will display an image if accessed by a specific IP address and an alternate image if accessed by any other IP. If any one could assist me in locating or writting a script that would preform those actions it would be greatly appreciated. [img src=\"style_emoticons/[#EMO_DIR#]/smile.gif\" style=\"vertical-align:middle\" emoid=\":smile:\" border=\"0\" alt=\"smile.gif\" /]
Thanks in advance,
newbie needs script help
1 reply to this topic
Posted 21 June 2006 - 06:09 PM
If your just learning then maybe this would be a good place to start. You will find a users ip in the $_SERVER array. Look it up [a href=\"http://php.net/globals\" target=\"_blank\"]here[/a]. Then you'll need to use an if() conditional. Look them up [a href=\"http://php.net/if\" target=\"_blank\"]here[/a].
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